ÌâÄ¿ÄÚÈÝ
£¨7·Ö£©Ä³¹¤³§ÏÖÓк¬ÉÙÁ¿ÌúмµÄÍм·ÏÁÏ¡£Ä³Ð£¾Å£¨5£©°à»¯Ñ§ÐËȤС×éµÄͬѧÓû´ÓÖлØÊÕÍ£¬ËûÒÀ¾Ý¡°ÂÌÉ«»¯Ñ§¡±µÄ˼ÏëÉè¼ÆÁËÁ½ÖÖ·½°¸£º
·½°¸¢ñ(ÎïÀí·½·¨)£º½«´ÅÌú½Ó´¥ÌúмºÍÍм»ìºÏÎͺÍÌú·Ö±ðµÃµ½»ØÊÕ¡¡
·½°¸¢ò (»¯Ñ§·½·¨): ¹ý³ÌÈçÏ£º
¢Ù²Ù×÷AµÄÃû³ÆÊÇ £¬Íê³É¸Ã²Ù×÷ÐèÒªµÄ²£Á§ÒÇÆ÷ÓÐÉÕ±¡¢Â©¶·ºÍ £»
¢ÚB¿ÉÄÜΪ ___________£»Ð´³öÏà¹ØµÄ»¯Ñ§·½³Ìʽ_____________________________£»
¢ÛÈ·¶¨¸øÌúмºÍÍм¼ÓÈëµÄBÒѾ¹ýÁ¿µÄ·½·¨ÓУº___________________ ¡£
¢Ü¸Ã·½°¸ÌåÏÖÂÌÉ«»¯Ñ§µÄ˼ÏëÓУºÍµÃµ½ÁË»ØÊÕ£¬ ¡£
·½°¸¢ñ(ÎïÀí·½·¨)£º½«´ÅÌú½Ó´¥ÌúмºÍÍм»ìºÏÎͺÍÌú·Ö±ðµÃµ½»ØÊÕ¡¡
·½°¸¢ò (»¯Ñ§·½·¨): ¹ý³ÌÈçÏ£º
¢Ù²Ù×÷AµÄÃû³ÆÊÇ £¬Íê³É¸Ã²Ù×÷ÐèÒªµÄ²£Á§ÒÇÆ÷ÓÐÉÕ±¡¢Â©¶·ºÍ £»
¢ÚB¿ÉÄÜΪ ___________£»Ð´³öÏà¹ØµÄ»¯Ñ§·½³Ìʽ_____________________________£»
¢ÛÈ·¶¨¸øÌúмºÍÍм¼ÓÈëµÄBÒѾ¹ýÁ¿µÄ·½·¨ÓУº___________________ ¡£
¢Ü¸Ã·½°¸ÌåÏÖÂÌÉ«»¯Ñ§µÄ˼ÏëÓУºÍµÃµ½ÁË»ØÊÕ£¬ ¡£
¢Ù¹ýÂË£»²£Á§°ô¡£¢ÚÑÎËá»òÁòËá»òÁòËáÍÈÜÒºµÈ¡£Fe + 2HCl ="==" FeCl2 + H2¡ü»òFe + H2SO4 = FeSO4 + H2¡ü»òFe + CuSO4 ="==" FeSO4 + Cu µÈ¢ÛÈ¡¹ýÂ˺óµÄÈÜÒºÉÙÐí£¬·ÅÔÚÊÔ¹ÜÖУ¬¼ÓÈëÉÙÁ¿Ìú£¬ÈôðÆøÅÝ£¬ËµÃ÷Ëá¹ýÁ¿¡££¨ºÏÀí´ð°¸¾ù¿É¸ø·Ö£©¢Ü·ÏÎïÀûÓᢽÚÔ¼×ÊÔ´µÈ
¢ÙÓÉÁ÷³Ìͼ¿ÉÖª²Ù×÷AΪ¹ÌÒº·ÖÀ룬Òò´Ë²Ù×÷AΪ¹ýÂË£¬Íê³É¹ýÂ˲Ù×÷µÄ²£Á§ÒÇÆ÷ÓÐÉÕ±¡¢Â©¶·ºÍ²£Á§°ô¡£¢Ú²Ù×÷AÖÐÓмÓÈë¹ýÁ¿º¬BµÄ¹¤Òµ·ÏË®£¬×îÖյõ½ÍмºÍÈÜÒº£¬¿ÉÖªÌúмÈܽâÔÚ¹¤Òµ·ÏË®ÖÐÁË£¬ÔÚ³õÖн׶ÎÄÜÓëÌú·´Ó¦µÄ¾ÍÖ»ÓÐÑÎËá»òÁòËá»òÁòËáÍÈÜÒº¡£Æä·´Ó¦·½³Ìʽ¿ÉÄÜÊÇ¡£Fe + 2HCl ="==" FeCl2 + H2¡ü»òFe + H2SO4 = FeSO4 + H2¡ü»òFe + CuSO4 ="==" FeSO4 + Cu ¢ÛÒª¼ìÑé¼ÓÈëµÄBÒѾ¹ýÁ¿ÔòÖ»ÐèÔÚ·´Ó¦ºóµÄÈÜÒºÖмÓÈëÄÜÓëB·´Ó¦ÇÒ·´Ó¦ÏÖÏóÃ÷ÏÔµÄÎïÖʼ´¿É£¬ÈçFe£¬È¡¹ýÂ˺óµÄÈÜÒºÉÙÐí£¬·ÅÔÚÊÔ¹ÜÖУ¬¼ÓÈëÉÙÁ¿Ìú£¬ÈôðÆøÅÝ£¬ËµÃ÷Ëá¹ýÁ¿¡£¢ÜÂÌÉ«»¯Ñ§µÄ˼ÏëÓУºÊ¹×ÊÔ´µÃµ½×î´óÀûÓ㬷ÏÎïÀûÓ㬽ÚÔ¼×ÊÔ´£¬±£»¤»·¾³µÈµÈ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿