ÌâÄ¿ÄÚÈÝ
£¨2006?·¬Ø®Çø¶þÄ££©½ðÊôÊÇÒ»ÖÖÖØÒªµÄ²ÄÁÏ£¬ÈËÀàµÄÉú»îºÍÉú²ú¶¼Àë²»¿ª½ðÊô£®ÏÂÁÐÊÇÓйؽðÊôµÄÎÊÌ⣺
£¨1£©ÒÔϹØÓÚÌúµÄÐðÊö£¬´íÎóµÄÊÇ
A¡¢ÉúÌúºÍ¸Ö¶¼ÊÇÌúÔªËصĵ¥ÖÊ B¡¢ÌúÊǵçºÍÈȵĵ¼Ìå
C¡¢ÌúÖÆÆ·ÔÚ³±ÊªµÄ¿ÕÆøÖлáÉúÐâD¡¢ÌúË¿ÄÜÔÚÑõÆøÖÐȼÉÕ
£¨2£©µØ¿ÇÖнðÊôÔªËصĺ¬Á¿×î¸ßÊÇ
£¨3£©²¨¶û¶àÒºÊÇÒ»ÖÖÅ©ÒµÉϳ£ÓõÄɱ¾ú¼Á£¬ÊÇÓÉÁòËáÍ¡¢Ê¯»Ò¼ÓË®ÅäÖƶø³É£¬ÎªÊ²Ã´²»ÓÃÌúÖÆÆ·ÅäÖƲ¨¶û¶àÒº£¬ÇëÓû¯Ñ§·½³Ìʽ±íʾÀíÓÉ£º
£¨4£©Ã¿ÄêÊÀ½çÉϸÖÌúµÄ²úÁ¿ºÜ¸ß£¬µ«¸ÖÌúµÄÐâÊ´Ò²¸øÈËÀà´øÀ´Á˾޴óµÄËðʧ£®ÌúÔÚ¿ÕÆøÖÐÐâÊ´µÄÖ÷ÒªÔÒòÊÇÌú¸ú
£¨5£©ÂÁµÄ»î¶¯ÐÔ±ÈÌúÇ¿£¬µ«ÂÁÔÚ¿ÕÆøÖÐÈ´±íÏÖ³öÁ¼ºÃµÄ¿¹Ê´ÐÔ£¬ÆäÔÒòÊÇ
£¨6£©ÒªÓÃ1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿ó£¬ÀíÂÛÉÏ¿ÉÒÔÉú²úº¬ÔÓÖÊ4%µÄÉúÌú
£¨7£©Èô½«6.5gп·ÅÈëÏ¡ÁòËáÈÜÒºÖÐÇ¡ºÃÍêÈ«·´Ó¦£¬Ôò¿ÉÉú³ÉÇâÆøµÄÖÊÁ¿Îª
£¨1£©ÒÔϹØÓÚÌúµÄÐðÊö£¬´íÎóµÄÊÇ
A
A
A¡¢ÉúÌúºÍ¸Ö¶¼ÊÇÌúÔªËصĵ¥ÖÊ B¡¢ÌúÊǵçºÍÈȵĵ¼Ìå
C¡¢ÌúÖÆÆ·ÔÚ³±ÊªµÄ¿ÕÆøÖлáÉúÐâD¡¢ÌúË¿ÄÜÔÚÑõÆøÖÐȼÉÕ
£¨2£©µØ¿ÇÖнðÊôÔªËصĺ¬Á¿×î¸ßÊÇ
ÂÁ
ÂÁ
£¨3£©²¨¶û¶àÒºÊÇÒ»ÖÖÅ©ÒµÉϳ£ÓõÄɱ¾ú¼Á£¬ÊÇÓÉÁòËáÍ¡¢Ê¯»Ò¼ÓË®ÅäÖƶø³É£¬ÎªÊ²Ã´²»ÓÃÌúÖÆÆ·ÅäÖƲ¨¶û¶àÒº£¬ÇëÓû¯Ñ§·½³Ìʽ±íʾÀíÓÉ£º
Fe+CuSO4¨TFeSO4+Cu
Fe+CuSO4¨TFeSO4+Cu
£®£¨4£©Ã¿ÄêÊÀ½çÉϸÖÌúµÄ²úÁ¿ºÜ¸ß£¬µ«¸ÖÌúµÄÐâÊ´Ò²¸øÈËÀà´øÀ´Á˾޴óµÄËðʧ£®ÌúÔÚ¿ÕÆøÖÐÐâÊ´µÄÖ÷ÒªÔÒòÊÇÌú¸ú
¿ÕÆøÖеÄÑõÆøºÍË®
¿ÕÆøÖеÄÑõÆøºÍË®
µÈÎïÖÊÏ໥·´Ó¦µÄ½á¹û£®£¨5£©ÂÁµÄ»î¶¯ÐÔ±ÈÌúÇ¿£¬µ«ÂÁÔÚ¿ÕÆøÖÐÈ´±íÏÖ³öÁ¼ºÃµÄ¿¹Ê´ÐÔ£¬ÆäÔÒòÊÇ
ÂÁºÍÑõÆø·´Ó¦Éú³ÉÁËÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬¸²¸ÇÔÚÂÁ±íÃ棬±£»¤ÁËÀï²ãµÄ½ðÊôÂÁ
ÂÁºÍÑõÆø·´Ó¦Éú³ÉÁËÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬¸²¸ÇÔÚÂÁ±íÃ棬±£»¤ÁËÀï²ãµÄ½ðÊôÂÁ
¶àÓà
¶àÓà
£®£¨6£©ÒªÓÃ1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿ó£¬ÀíÂÛÉÏ¿ÉÒÔÉú²úº¬ÔÓÖÊ4%µÄÉúÌú
583.3
583.3
¶Ö£®£¨7£©Èô½«6.5gп·ÅÈëÏ¡ÁòËáÈÜÒºÖÐÇ¡ºÃÍêÈ«·´Ó¦£¬Ôò¿ÉÉú³ÉÇâÆøµÄÖÊÁ¿Îª
0.2
0.2
¿Ë£®·ÖÎö£º£¨1£©ÒÀ¾ÝÌúµÄÏà¹ØÐÔÖÊ·ÖÎöÅжϣ»
£¨2£©ÒÀ¾ÝµØ¿ÇÖÐÔªËصÄ×é³ÉÇé¿ö·ÖÎöÅжϣ»
£¨3£©ÒÀ¾Ý½ðÊô»î¶¯ÐÔ˳ÐòÖлÐÔÇ¿µÄ½ðÊô¿ÉÒ԰ѻÐÔÈõµÄ½ðÊô´ÓÆäÑÎÈÜÒºÖÐÖû»³öÀ´µÄ¹æÂÉ·ÖÎöÅжϣ»
£¨4£©¸ù¾ÝÌúÉúÐâµÄÔÀí·ÖÎöÅжϣ»
£¨5£©ÒÀ¾ÝÂÁÓëÑõÆø·´Ó¦µÄ»¯Ñ§ÐÔÖÊ·ÖÎöÅжϣ»
£¨6£©¾Ý»¯Ñ§±ä»¯Ç°ºóÔªËØÖÊÁ¿²»±ä£¬ÓÉÁ¶³öº¬ÔÓÖÊ4%µÄÉúÌúÖÐÌúÔªËØÖÊÁ¿Óë1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿óʯÖÐËùº¬ÌúÔªËØÖÊÁ¿ÏàµÈ£¬¼ÆËãÉú³ÉÌúµÄÖÊÁ¿£®
£¨7£©ÓÉпµÄÖÊÁ¿¸ù¾ÝпÓëÁòËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ¼ÆËã³öÉú³ÉÇâÆøµÄÖÊÁ¿£®
£¨2£©ÒÀ¾ÝµØ¿ÇÖÐÔªËصÄ×é³ÉÇé¿ö·ÖÎöÅжϣ»
£¨3£©ÒÀ¾Ý½ðÊô»î¶¯ÐÔ˳ÐòÖлÐÔÇ¿µÄ½ðÊô¿ÉÒ԰ѻÐÔÈõµÄ½ðÊô´ÓÆäÑÎÈÜÒºÖÐÖû»³öÀ´µÄ¹æÂÉ·ÖÎöÅжϣ»
£¨4£©¸ù¾ÝÌúÉúÐâµÄÔÀí·ÖÎöÅжϣ»
£¨5£©ÒÀ¾ÝÂÁÓëÑõÆø·´Ó¦µÄ»¯Ñ§ÐÔÖÊ·ÖÎöÅжϣ»
£¨6£©¾Ý»¯Ñ§±ä»¯Ç°ºóÔªËØÖÊÁ¿²»±ä£¬ÓÉÁ¶³öº¬ÔÓÖÊ4%µÄÉúÌúÖÐÌúÔªËØÖÊÁ¿Óë1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿óʯÖÐËùº¬ÌúÔªËØÖÊÁ¿ÏàµÈ£¬¼ÆËãÉú³ÉÌúµÄÖÊÁ¿£®
£¨7£©ÓÉпµÄÖÊÁ¿¸ù¾ÝпÓëÁòËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÒÔ¼ÆËã³öÉú³ÉÇâÆøµÄÖÊÁ¿£®
½â´ð£º½â£º£¨1£©ÉúÌúÓë¸Ö¶¼ÊÇÌúµÄºÏ½ð²»ÊÇ´¿¾»ÎﵱȻ²»Êǵ¥ÖÊ£»ÌúÊǵçºÍÈȵĵ¼Ì壻ÔÚ¿ÕÆøÖÐÒ×ÓÚÑõÆø¼°Ë®·´Ó¦¶øÉúÐ⣬²¢ÄÜÔÚÑõÆøÖÐȼÉÕÉú³ÉËÄÑõ»¯ÈýÌú£»
£¨2£©µØ¿ÇÖÐÔªËصĺ¬Á¿ÅÅÔÚÇ°ËÄλµÄÔªËØ·Ö±ðÊÇ£ºÑõ¡¢¹è¡¢ÂÁ¡¢Ìú£¬ËùÒÔº¬Á¿×î¶àµÄ½ðÊôÊÇÂÁ£»
£¨3£©²¨¶û¶àÒºÖк¬ÓÐÁòËáÍ£¬ÓÉÓÚÌúµÄ»î¶¯ÐÔ±ÈÍÇ¿ËùÒÔÌú¿ÉÒÔ°ÑÍ´ÓÁòËáÍÈÜÒºÖÐÖû»³öÀ´£¬Òò´Ë²»ÄÜÓÃÌúÖÆÆ·ÅäÖƲ¨¶û¶àÒº£¬Ïà¹ØµÄ·½³ÌʽΪ£ºFe+CuSO4¨TFeSO4+Cu£»
£¨4£©ÌúµÄÉúÐâʵ¼ÊÉÏÊÇÌúÓë¿ÕÆøÖеÄÑõÆø¼°Ë®¹²Í¬×÷ÓõĽá¹û£»
£¨5£©ÂÁµÄ»¯Ñ§ÐÔÖʽϻîÆÃÔÚ¿ÕÆøÖÐÄÜÓëÑõÆø·´Ó¦Éú³ÉÑõ»¯ÂÁ£¬Ñõ»¯ÂÁ¸²¸ÇÔÚÂÁ±íÃ棬Æðµ½Á˱£»¤Àï²ãµÄ½ðÊôÂÁµÄ×÷Óã»
£¨6£©Ñõ»¯ÌúFe2O3ÖÐÌúÔªËصÄÖÊÁ¿·ÖÊý=
¡Á100%=70%
1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿óʯÖУ¬Ñõ»¯ÌúµÄÖÊÁ¿=1000t¡Á80%=800t
ÀíÂÛÉÏ¿ÉÒÔÁ¶³öº¬ÔÓÖÊ4%µÄÉúÌúµÄÖÊÁ¿=
¡Ö583.3t
£¨7£©ÉèÉú³ÉÇâÆøµÄÖÊÁ¿Îªx£®
Zn+H2SO4=ZnSO4+H2¡ü
65 2
6.5g x
=
x=0.2g
£¨1£©A £¨2£©Al¡¡£¨ÂÁ£©£¨3£©Fe+CuSO4¨TFeSO4+Cu¡¡£¨4£©¿ÕÆøÖеÄÑõÆøºÍË®£¨5£©ÂÁºÍÑõÆø·´Ó¦Éú³ÉÁËÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬¸²¸ÇÔÚÂÁ±íÃ棬±£»¤ÁËÀï²ãµÄ½ðÊôÂÁ£®£¨6£©583.3£¨7£©0.2
£¨2£©µØ¿ÇÖÐÔªËصĺ¬Á¿ÅÅÔÚÇ°ËÄλµÄÔªËØ·Ö±ðÊÇ£ºÑõ¡¢¹è¡¢ÂÁ¡¢Ìú£¬ËùÒÔº¬Á¿×î¶àµÄ½ðÊôÊÇÂÁ£»
£¨3£©²¨¶û¶àÒºÖк¬ÓÐÁòËáÍ£¬ÓÉÓÚÌúµÄ»î¶¯ÐÔ±ÈÍÇ¿ËùÒÔÌú¿ÉÒÔ°ÑÍ´ÓÁòËáÍÈÜÒºÖÐÖû»³öÀ´£¬Òò´Ë²»ÄÜÓÃÌúÖÆÆ·ÅäÖƲ¨¶û¶àÒº£¬Ïà¹ØµÄ·½³ÌʽΪ£ºFe+CuSO4¨TFeSO4+Cu£»
£¨4£©ÌúµÄÉúÐâʵ¼ÊÉÏÊÇÌúÓë¿ÕÆøÖеÄÑõÆø¼°Ë®¹²Í¬×÷ÓõĽá¹û£»
£¨5£©ÂÁµÄ»¯Ñ§ÐÔÖʽϻîÆÃÔÚ¿ÕÆøÖÐÄÜÓëÑõÆø·´Ó¦Éú³ÉÑõ»¯ÂÁ£¬Ñõ»¯ÂÁ¸²¸ÇÔÚÂÁ±íÃ棬Æðµ½Á˱£»¤Àï²ãµÄ½ðÊôÂÁµÄ×÷Óã»
£¨6£©Ñõ»¯ÌúFe2O3ÖÐÌúÔªËصÄÖÊÁ¿·ÖÊý=
56¡Á2 |
56¡Á2+16¡Á3 |
1000tº¬Ñõ»¯Ìú80%µÄ³àÌú¿óʯÖУ¬Ñõ»¯ÌúµÄÖÊÁ¿=1000t¡Á80%=800t
ÀíÂÛÉÏ¿ÉÒÔÁ¶³öº¬ÔÓÖÊ4%µÄÉúÌúµÄÖÊÁ¿=
800t¡Á70% |
1-4% |
£¨7£©ÉèÉú³ÉÇâÆøµÄÖÊÁ¿Îªx£®
Zn+H2SO4=ZnSO4+H2¡ü
65 2
6.5g x
65 |
6.5g |
2 |
x |
x=0.2g
£¨1£©A £¨2£©Al¡¡£¨ÂÁ£©£¨3£©Fe+CuSO4¨TFeSO4+Cu¡¡£¨4£©¿ÕÆøÖеÄÑõÆøºÍË®£¨5£©ÂÁºÍÑõÆø·´Ó¦Éú³ÉÁËÖÂÃܵÄÑõ»¯ÂÁ±¡Ä¤£¬¸²¸ÇÔÚÂÁ±íÃ棬±£»¤ÁËÀï²ãµÄ½ðÊôÂÁ£®£¨6£©583.3£¨7£©0.2
µãÆÀ£º´ËÌâÊÇÒ»µÀ¹ØÓÚÌúÏà¹ØµÄ¿¼²éÌ⣬Éæ¼°µ½ÌúÓëÆäËü½ðÊôµÄÏà¹ØÐÔÖÊ£¬Ö»ÓжԳ£¼û½ðÊôµÄÐÔÖÊÊýÁ¿ÕÆÎÕ£¬²ÅÄÜÇáËɽâÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿