ÌâÄ¿ÄÚÈÝ
£¨1£©ÈçͼËùʾ£¬Ä³»ìºÏÆøÌ庬ÓгõÖл¯Ñ§³£¼ûµÄÆøÌ壬½«ÆäÒÀ´Îͨ¹ý×°ÓгÎÇåµÄʯ»ÒË®µÄ¼×ÒÒÁ½¸öÊÔ¼ÁÆ¿£¬¼×ÎÞÃ÷ÏÔÏÖÏó£¬ÒÒÖеijÎÇåµÄʯ»ÒË®±ä»ë×Ç£®Ôò¸ÃÆøÌåµÄ³É·ÖΪ______£»¼×Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£®
£¨2£©ÏÖÓÐÏ¡ÑÎËᡢʯ»ÒË®¡¢Ê³ÑÎË®¡¢Ì¼ËáÄÆÈÜÒºËÄÖÖÎÞÉ«ÈÜÒº£¬Îª¼ø±ðËüÃÇ·Ö±ð±àºÅΪA¡¢B¡¢C¡¢D£¬È»ºó¸÷È¡ÉÙÐí½øÐÐÁ½Á½»ìºÏʵÑ飬ÏÖÏó¼ûÓÒ±í£¨Í¼ÖС°¡ý¡±¡°¡ü¡±¡°-¡±·ûºÅ·Ö±ð±íʾÉú³É³Áµí¡¢ÆøÌåºÍÎÞÃ÷ÏԱ仯£©£®¸ù¾Ý±íÖÐʵÑéÏÖÏóÅжÏ
A | B | C | D | |
A | - | - | ¡ý | - |
B | - | - | ¡ü | - |
C | ¡ý | ¡ü | - | - |
D | - | - | - | - |
¢ÚAÓëC·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______£¬¸Ã·´Ó¦µÄ»ù±¾·´Ó¦ÀàÐÍÊÇ______£®
£¨3£©Ä³¿ÎÍâѧϰС×éÓÃ̼ËáÄÆÈÜÒº·Ö±ð¼ø±ð³ÎÇåʯ»ÒË®ÓëÑÎËᣮʵÑéºó½«·ÏÒºµ¹ÈëͬһÉÕ±ÖУ¬×îºóÉÕ±ÄÚÒºÌå³ÎÇ壮ÀÏʦÒýµ¼¿ÎÍâС×éµÄͬѧÌÖÂÛ·ÖÎöºóÈÏΪ£¬ÉÕ±ÖгÎÇåµÄÈÜÒº¿ÉÄܻẬÓÐÏÂÁÐÎïÖÊ£ºNa2CO3¡¢HCl¡¢Ca£¨OH£©2¡¢NaOH¡¢NaCl¡¢CaCl2£¬ÇëÄã¸ù¾Ý³õÈý»¯Ñ§Ëùѧ֪ʶÅжϣº¸ÃÉÕ±³ÎÇåÈÜÒºÖÐÒ»¶¨º¬ÓеÄÈÜÖÊÊÇ______£¬Ò»¶¨²»º¬ÓеÄÈÜÖÊÊÇ______£®
½â£º£¨1£©»ìºÏÆøÌåµÄ³É·ÖÊÇHClºÍCO2£¬Ö÷ÒªÊÇÂÈ»¯ÇâÖкÍÁËÇâÑõ»¯¸Æ£¬µ¼Ö¶þÑõ»¯Ì¼ÎÞ·¨ÓëÇâÑõ»¯¸Æ·´Ó¦Éú³É³Áµí£»ËùÒÔ¼×ÎÞÃ÷ÏÔÏÖÏó£¬ÒÒÖеijÎÇåµÄʯ»ÒË®±ä»ë×Ç£®¼×Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨OH£©2+2HCl=CaCl2+2H2O£®
¹Ê´ð°¸Îª£ºHClºÍCO2£»Ca£¨OH£©2+2HCl=CaCl2+2H2O£®
£¨2£©¢ÙAÓëC·´Ó¦Éú³É³Áµí£¬È·¶¨A¡¢CÊÇʯ»ÒË®»ò̼ËáÄÆÈÜÒº£»ÓÖÒòBÓëC·´Ó¦Éú³ÉÆøÌ壬CÊÇ̼ËáÄÆÈÜÒº£¬BÊÇÏ¡ÑÎË᣻AÊÇʯ»ÒË®£»DÊÇʳÑÎË®£®
¹Ê´ð°¸Îª£ºHCl£»
¢Ú¸ù¾ÝAÊÇʯ»ÒË®£¬CÊÇ̼ËáÄÆÈÜÒº£¬¶þÕß·´Ó¦µÄ»¯Ñ§Ê½ÊÇ£ºNa2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH£»ÊÇÁ½ÖÖ»¯ºÏÎïÏ໥½»»»³É·Ö£¬Éú³ÉÁíÍâÁ½ÖÖ»¯ºÏÎïµÄ¸´·Ö½â·´Ó¦£®
¹Ê´ð°¸Îª£ºNa2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH£»¸´·Ö½â·´Ó¦£»
£¨3£©¸ù¾Ý̼ËáÄÆÈÜÒºÓëʯ»ÒË®µÄ»¯Ñ§·´Ó¦Ê½ÊÇ£ºNa2CO3+Ca£¨OH£©2¨T2NaOH+CaCO3¡ý£»Ì¼ËáÄÆÈÜÒºÓëÏ¡ÑÎËáµÄ»¯Ñ§·´Ó¦Ê½ÊÇ£ºNa2CO3+2HCl¨T2NaCl+H2O+CO2¡ü£®Na2CO3¡¢HCl¡¢Ca£¨OH£©2¡¢NaOH¡¢NaCl¡¢CaCl2ÖÐNaClÊÇÉú³ÉÎ²¢ÇÒ²»ÓëÆäËûÎïÖÊ·´Ó¦£¬ËùÒÔÒ»¶¨ÓУ»ÊµÑéºó½«·ÏÒºµ¹ÈëͬһÉÕ±ÖУ¬×îºóÉÕ±ÄÚÒºÌå³ÎÇ壮˵Ã÷Éú³ÉµÄ³ÁµíCaCO3Óë¶àÓàµÄÑÎËá·´Ó¦ÁË£¬²¢Éú³ÉÁËCaCl2£¬²¢²»ÔÙÓëÆäËûÎïÖÊ·´Ó¦£¬ËùÒÔÒ²Ò»¶¨ÓУ»Ca£¨OH£©2¡¢Na2CO3¡¢NaOH¶¼ÄÜÓëÑÎËá·´Ó¦£¬ËùÒÔÒ»¶¨Ã»ÓУ®
¹Ê´ð°¸Îª£ºNaCl¡¢CaCl2£»Ca£¨OH£©2¡¢Na2CO3¡¢NaOH£®
·ÖÎö£º£¨1£©¸ù¾Ý¼×ÎÞÃ÷ÏÔÏÖÏó£¬ÒÒÖеijÎÇåµÄʯ»ÒË®±ä»ë×Ç£®ÅжϻìºÏÆøÌåµÄ³É·Ö£»
£¨2£©¸ù¾Ý±í¸ñÖÐAÓëC·´Ó¦Éú³É³Áµí£¬È·¶¨A¡¢CÊÇʯ»ÒË®»ò̼ËáÄÆÈÜÒº£»ÓÖÒòBÓëC·´Ó¦Éú³ÉÆøÌ壬CÊÇ̼ËáÄÆÈÜÒº£¬BÊÇÏ¡ÑÎË᣻ȷ¶¨¸÷ÎïÖʺóд³öAÓëC·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬ÒÔ¼°·´Ó¦ÀàÐÍ£»
£¨3£©¸ù¾ÝÁ½ÖÖ·´Ó¦µÄ·´Ó¦Îï¡¢Éú³ÉÎïÒÔ¼°ËûÃÇÖ®¼äµÄ·´Ó¦Åжϣ®
µãÆÀ£º±¾Ì⿼²é¸ù¾ÝÏÖÏóÅжÏÎïÖÊ£¬ÒªÍ¬Ñ§ÃǶÔËùѧÎïÖʵÄÐÔÖÊ¡¢×´Ì¬¡¢ÓëÆäËûÎïÖʵķ´Ó¦£¬¶¼ÒªÁËÈ»ÓÚÐÄ£¬·ñÔòºÜÄÑ×÷¶Ô£¬ÄѶȽϴó£®
¹Ê´ð°¸Îª£ºHClºÍCO2£»Ca£¨OH£©2+2HCl=CaCl2+2H2O£®
£¨2£©¢ÙAÓëC·´Ó¦Éú³É³Áµí£¬È·¶¨A¡¢CÊÇʯ»ÒË®»ò̼ËáÄÆÈÜÒº£»ÓÖÒòBÓëC·´Ó¦Éú³ÉÆøÌ壬CÊÇ̼ËáÄÆÈÜÒº£¬BÊÇÏ¡ÑÎË᣻AÊÇʯ»ÒË®£»DÊÇʳÑÎË®£®
¹Ê´ð°¸Îª£ºHCl£»
¢Ú¸ù¾ÝAÊÇʯ»ÒË®£¬CÊÇ̼ËáÄÆÈÜÒº£¬¶þÕß·´Ó¦µÄ»¯Ñ§Ê½ÊÇ£ºNa2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH£»ÊÇÁ½ÖÖ»¯ºÏÎïÏ໥½»»»³É·Ö£¬Éú³ÉÁíÍâÁ½ÖÖ»¯ºÏÎïµÄ¸´·Ö½â·´Ó¦£®
¹Ê´ð°¸Îª£ºNa2CO3+Ca£¨OH£©2=CaCO3¡ý+2NaOH£»¸´·Ö½â·´Ó¦£»
£¨3£©¸ù¾Ý̼ËáÄÆÈÜÒºÓëʯ»ÒË®µÄ»¯Ñ§·´Ó¦Ê½ÊÇ£ºNa2CO3+Ca£¨OH£©2¨T2NaOH+CaCO3¡ý£»Ì¼ËáÄÆÈÜÒºÓëÏ¡ÑÎËáµÄ»¯Ñ§·´Ó¦Ê½ÊÇ£ºNa2CO3+2HCl¨T2NaCl+H2O+CO2¡ü£®Na2CO3¡¢HCl¡¢Ca£¨OH£©2¡¢NaOH¡¢NaCl¡¢CaCl2ÖÐNaClÊÇÉú³ÉÎ²¢ÇÒ²»ÓëÆäËûÎïÖÊ·´Ó¦£¬ËùÒÔÒ»¶¨ÓУ»ÊµÑéºó½«·ÏÒºµ¹ÈëͬһÉÕ±ÖУ¬×îºóÉÕ±ÄÚÒºÌå³ÎÇ壮˵Ã÷Éú³ÉµÄ³ÁµíCaCO3Óë¶àÓàµÄÑÎËá·´Ó¦ÁË£¬²¢Éú³ÉÁËCaCl2£¬²¢²»ÔÙÓëÆäËûÎïÖÊ·´Ó¦£¬ËùÒÔÒ²Ò»¶¨ÓУ»Ca£¨OH£©2¡¢Na2CO3¡¢NaOH¶¼ÄÜÓëÑÎËá·´Ó¦£¬ËùÒÔÒ»¶¨Ã»ÓУ®
¹Ê´ð°¸Îª£ºNaCl¡¢CaCl2£»Ca£¨OH£©2¡¢Na2CO3¡¢NaOH£®
·ÖÎö£º£¨1£©¸ù¾Ý¼×ÎÞÃ÷ÏÔÏÖÏó£¬ÒÒÖеijÎÇåµÄʯ»ÒË®±ä»ë×Ç£®ÅжϻìºÏÆøÌåµÄ³É·Ö£»
£¨2£©¸ù¾Ý±í¸ñÖÐAÓëC·´Ó¦Éú³É³Áµí£¬È·¶¨A¡¢CÊÇʯ»ÒË®»ò̼ËáÄÆÈÜÒº£»ÓÖÒòBÓëC·´Ó¦Éú³ÉÆøÌ壬CÊÇ̼ËáÄÆÈÜÒº£¬BÊÇÏ¡ÑÎË᣻ȷ¶¨¸÷ÎïÖʺóд³öAÓëC·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬ÒÔ¼°·´Ó¦ÀàÐÍ£»
£¨3£©¸ù¾ÝÁ½ÖÖ·´Ó¦µÄ·´Ó¦Îï¡¢Éú³ÉÎïÒÔ¼°ËûÃÇÖ®¼äµÄ·´Ó¦Åжϣ®
µãÆÀ£º±¾Ì⿼²é¸ù¾ÝÏÖÏóÅжÏÎïÖÊ£¬ÒªÍ¬Ñ§ÃǶÔËùѧÎïÖʵÄÐÔÖÊ¡¢×´Ì¬¡¢ÓëÆäËûÎïÖʵķ´Ó¦£¬¶¼ÒªÁËÈ»ÓÚÐÄ£¬·ñÔòºÜÄÑ×÷¶Ô£¬ÄѶȽϴó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿