ÌâÄ¿ÄÚÈÝ

£¨5·Ö£©ÄÜÔ´¡¢»·¾³ÓëÈËÀàµÄÉú»îºÍÉç»á·¢Õ¹ÃÜÇÐÏà¹Ø¡£
£¨1£©Ä¿Ç°£¬ÈËÀàÒÔ»¯Ê¯È¼ÁÏΪÖ÷ÒªÄÜÔ´¡£³£¼ûµÄ»¯Ê¯È¼ÁÏ°üÀ¨Ãº¡¢Ê¯Óͺ͠    ¡£
£¨2£©Îª¼õÉÙÎÛȾ¡¢Ìá¸ßúµÄÀûÓÃÂÊ£¬¿É½«Æäת»¯Îª¿ÉȼÐÔÆøÌ壬´Ë¹ý³Ì¿ÉÈÏΪÊÇ̼ÓëË®µÄ·´Ó¦£¬Æä΢¹ÛʾÒâͼÈçÏÂËùʾ£º

¢Ù ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ     ¡£
¢Ú ¸Ã·´Ó¦Éú³ÉÎïµÄ·Ö×Ó¸öÊý±ÈΪ     ¡£
£¨3£©Îª¼õÉÙÎÂÊÒÆøÌåÅÅ·Å£¬ÈËÃÇ»ý¼«Ñ°ÕÒ²»º¬Ì¼ÔªËصÄȼÁÏ¡£¾­Ñо¿·¢ÏÖNH3ȼÉյIJúÎïûÓÐÎÛȾ£¬ÇÒÊÍ·Å´óÁ¿ÄÜÁ¿£¬ÓÐÒ»¶¨Ó¦ÓÃÇ°¾°¡£
¢Ù NH3ÖеªÔªËغÍÇâÔªËصÄÖÊÁ¿±ÈΪ     ¡£
¢Ú ½«NH3ȼÉÕ·´Ó¦µÄ»¯Ñ§·½³Ìʽ²¹³äÍêÕû£º4NH3 + 3O2  µãȼ  6H2O +       ¡£
£¨1£©ÌìÈ»Æø     £¨2£©¢Ù C + H2O ¸ßΠCO + H2      ¢Ú COÓëH2µÄ·Ö×Ó¸öÊý±ÈΪ1¡Ã1
£¨3£©¢Ù 14¡Ã3             ¢Ú 2N2

ÊÔÌâ·ÖÎö£º£¨1£©Èý´ó»¯Ê¯È¼ÁÏ°üÀ¨Ãº¡¢Ê¯ÓͺÍÌìÈ»Æø
£¨2£©¸ù¾Ý΢¹ÛʾÒâͼ£¬¿É·Ö±ðд³ö¸÷ÎïÖʵĻ¯Ñ§Ê½£¬AΪC£¬BΪH2O£¬CΪCO£¬DΪH2£¬ËùÒÔ¢Ù ¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºC + H2O ¸ßΠCO + H2£¬¢Ú¸ù¾Ý·´Ó¦µÄ»¯Ñ§·½³Ìʽ£¬¿ÉÅжϸ÷´Ó¦Éú³ÉÎïµÄ·Ö×Ó¸öÊý±ÈΪ1¡Ã1
£¨3£©¢Ù¸ù¾Ý»¯Ñ§Ê½£¬NH3ÖеªÔªËغÍÇâÔªËصÄÖÊÁ¿±È=14¡Á1£º1¡Á3=14£º3
¢Ú¸ù¾ÝÖÊÁ¿Êغ㶨ÂɵÄ΢¹Û½âÊÍ£º»¯Ñ§·´Ó¦Ç°ºó£¬Ô­×ÓµÄÖÖÀ࣬¸öÊý¶¼²»±ä£¬ËùÒÔ²»ÄÑÍƳö»¯Ñ§·½³Ìʽ²¹³äÍêÕûΪ£º4NH3 + 3O2  µãȼ  6H2O + 2N2
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø