ÌâÄ¿ÄÚÈÝ

ÓêË®×ÊÔ´»¯ÊÇÒ»ÖÖ·¢Õ¹Ç÷ÊÆ£¬2008Äê°ÂÔË»áËùʹÓõİÂÔ˳¡¹Ý¶¼½¨Á¢ÁËÓêË®ÀûÓÃϵͳ£¬´ó´óÌá¸ßÁËÓêË®ÀûÓÃÂÊ¡£
(1)ÓêË®ÔÚ½µÂä¹ý³ÌÖг£ÊÜNO2¡¢SO2µÄÎÛȾÐγÉËáÓê¡£ÈôÒª²â¶¨Ä³ÓêË®Ëá¶È£¬¿ÉʹÓà               
(2)ÓêË®Êܵ½SO2ÎÛȾʱ£¬½«·¢ÉúSO2ÓëË®µÄ·´Ó¦£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                   £»¿ÕÆøÖеÄSO2Ö÷ÒªÀ´Ô´ÓÚ                   
(3)ÊÕ¼¯µÄµØÃæÓêË®³£Ð¯´øÊ÷Ò¶¡¢ËÜÁÏ´üµÈ²»ÈÜÔÓÎ´¦ÀíÓêˮʱӦ½øÐгÁ½µ¡¢                £»
(4)ҪʹÖ÷ÒªÊÜSO2ÎÛȾµÄËáÓê¿É±»»ØÊÕÀûÓ㬱ØÐë¶ÔÆäËáÐÔ½øÐÐÖкͣ¬ÄãÈÏΪÒÔϽÏΪ¾­¼ÃÓÐЧµÄ·½·¨ÊǼÓÈëÊÊÁ¿µÄ                    ¹ÌÌå(ÌîÐòºÅ)¡£
A£®NaOH   B£®Ca(OH)2   C£®CaCl2   D£®Na2CO3
(1)pHÊÔÖ½(»òpH¼Æ)
(2)SO2+H2O==H2SO3£»»¯Ê¯È¼ÁϵÄȼÉÕ
(3)¹ýÂË
(4)B
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø