ÌâÄ¿ÄÚÈÝ

ÀÏʦÓÃÓÒͼËùʾװÖÃΪͬѧÃÇ×öÁËÒ»¸öʵÑé¡£A×°ÖÃÖÐ×°ÓÐÌå»ý±ÈԼΪ3:1µÄ¿ÕÆøºÍ¶þÑõ»¯Ì¼µÄ»ìºÏÆø£»B×°ÖÃÖРʢÓÐ×ãÁ¿Ìú·Û£»C×°ÖÃÖÐÊ¢ÓÐ×ãÁ¿µÄÏ¡ÑÎËá¡£

£¨1£©¹Ø±Õ»îÈû£Ë£¬µ±½«A×°ÖÃÖнºÍ·µÎ¹ÜÀï×ãÁ¿µÄŨÇâÑõ»¯ÄÆ

ÈÜÒº¼·ÈëÆ¿ÖУ¬¿ÉÒԹ۲쵽A×°ÖÃÖеÄÏÖÏóÊÇ       £»A×°Ö÷¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ       ¡£

£¨2£©Á¢¼´´ò¿ª»îÈû£Ë£¬Ò»¶Îʱ¼äºó£¬¹Ø±Õ»îÈû£Ë¡£B×°ÖÃÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ       £»ÔÚÕû¸öʵÑé¹ý³ÌÖУ¬¿ÉÒԹ۲쵽װÖÃB¡¢CÖеÄʵÑéÏÖÏóÊÇ        ¡£

£¨3£©C×°ÖõÄ×÷ÓÃÊÇ       £¨Ìî×Öĸ£©¡£

a£®ÌṩҩƷ   b£®¿ØÖÆÆøÌå×ÜÁ¿   c£®µ÷½Ú×°ÖÃÄÚµÄѹǿ   d£®¿ÉÓÃÀ´´¢´æÆøÌå

£¨1£©±ñÆøÇòÖð½¥ÕÇ´ó    2 NaOH+CO2 = Na2CO3+H2O

  £¨2£©2HCl+Fe = FeCl2+H2¡ü    C×°ÖÃÖеÄÏ¡ÑÎËáÁ÷ÈëB×°ÖÃÖУ¬B×°ÖÃÖÐÌúÖð½¥¼õÉÙ£¬±íÃæÓÐÆøÅÝ£¬ÈÜÒºÓÉÎÞÉ«±ä³ÉdzÂÌÉ«£»C×°ÖõÄÏ¡ÑÎËáÖÐÓÐÆøÅÝð³ö¡£   

  £¨3£©a c b

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø