ÌâÄ¿ÄÚÈÝ
·Ö×Ó¡¢Ô×Ó¶¼ÓÐÒ»¶¨µÄÖÊÁ¿£®¹ú¼ÊÉϹ涨·Ö±ð²ÉÓÃÏà¶Ô·Ö×ÓÖÊÁ¿ºÍÏà¶ÔÔ×ÓÖÊÁ¿À´±íʾ·Ö×Ó¡¢Ô×ÓµÄÖÊÁ¿£®ÒÔË®·Ö×ÓΪÀý£¬ÏÂÃæÊÇË®·Ö×ÓµÄÏà¶Ô·Ö×ÓÖÊÁ¿[Mr(H2O)]¼ÆËã¹ý³Ì£º
[Mr(H2O)]£½
£½
£½2Ar(H)£«Ar(O)
¸ù¾ÝÉÏÊö¼ÆËã¹ý³Ì£¬ÄãÈÏΪÏÂÁÐ˵·¨²»ºÏÀíµÄÊÇ
[¡¡¡¡]
A£®Ïà¶Ô·Ö×ÓÖÊÁ¿µÈÓÚ¹¹³É·Ö×ӵĸ÷Ô×ÓµÄÏà¶ÔÔ×ÓÖÊÁ¿µÄ×ܺÍ
B£®·Ö×ÓµÄÖÊÁ¿µÈÓÚ¹¹³É·Ö×ӵĸ÷Ô×ÓµÄÖÊÁ¿µÄ×ܺÍ
C£®Ë®µÄÏà¶Ô·Ö×ÓÖÊÁ¿ÊÇ18 g
D£®ÒÔÒ»ÖÖ̼Ô×ÓÖÊÁ¿µÄ1/12×÷Ϊ»ù×¼£¬Ò»¸öÆäËû·Ö×ÓµÄÖÊÁ¿ÓëÕâÒ»»ù×¼µÄ±ÈÖµ£¬³ÆÎªÕâÖÖ·Ö×ÓµÄÏà¶Ô·Ö×ÓÖÊÁ¿
´ð°¸£ºC
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿