ÌâÄ¿ÄÚÈÝ

»¯Ñ§ÓÃÓï(¹²18·Ö)
(1)£¨6·Ö£©´Ó¸ø¶¨µÄ»¯ºÏ¼Û:¡¢¡¢¡¢¡¢¡¢ µÄÁùÖÖÔªËØÖÐ,Ñ¡ÔñÊʵ±µÄÁ½ÖÖÔªËØ,д³ö6¸ö»¯Ñ§Ê½:      ¢Ù            ¢Ú         
¢Û            ¢Ü         ¢Ý            ¢Þ          
(2) (6·Ö)ÏÂÁл¯Ñ§Ê½Êéд´íÎó£¬Çë¸ÄÕý£¬²¢ËµÃ÷Ô­Òò£º
¢ÙÂÈ»¯¸Æ£ºCaCl ¸ÄÕý        £¬Ô­Òò                                    £»
¢ÚÎåÑõ»¯¶þµª£ºN2O5 ¸ÄÕý         £¬Ô­Òò                               ¡£
(3) (6·Ö)ÏÂÁл¯Ñ§·½³ÌʽÊéд´íÎó£¬Çë¸ÄÕý£¬²¢ËµÃ÷Ô­Òò£º
¢ÙÑõ»¯¹¯¼ÓÈȷֽ⠠ HgO ="==" Hg  +  O2 ¡ü
¸ÄÕý                          £¬Ô­Òò                                 £»
¢ÚÁòÔÚÑõÆøÖÐȼÉÕ   S  +   O2 ¡ü  µãȼ   SO2  
 ¸ÄÕý                                       £¬
Ô­Òò                                                                  ¡£
£¨¸ÄÕýÿ¸ö2·Ö£¬Ô­Òòÿ¸ö1·Ö£¬¹²18·Ö£©
(1) (ÿ¸ö1·Ö£¬¹²6·Ö)
¢Ù H2O  ¢ÚMgO ¢ÛCO2  ¢Ü HCl   ¢Ý MgCl2    ¢ÞCCl4  (˳Ðò¿ÉÒÔ²»Í¬)
(2) (¸ÄÕýÿ¸ö2·Ö£¬Ô­Òòÿ¸ö1·Ö, ¹²6·Ö)
¢Ù CaCl2£¬   Õý¡¢¸º»¯ºÏ¼Û´úÊýºÍ²»ÎªÁã(»òÆäËûºÏÀíµÄ´ð°¸)
¢Ú N2O5£¬   »¯Ñ§Ê½ÖеÄÔ­×Ó¸öÊýҪдÔÚÔªËØ·ûºÅµÄÓÒϽÇ(»òÆäËûºÏÀíµÄ´ð°¸)
(3) (¸ÄÕýÿ¸ö2·Ö£¬Ô­Òòÿ¸ö1·Ö, ¹²6·Ö)
¢Ù2HgO 2Hg  +  O2 ¡ü £¬Ã»Åäƽ£¬Ò²Ã»×¢Ã÷·´Ó¦Ìõ¼þ
¢ÚS  +   O2  µãȼ   SO2
·´Ó¦ÎïÖеÄÆøÌå²»Óáü×¢Ã÷£¬µ±·´Ó¦ÎïÖÐÓÐÆøÌå²Î¼Óʱ£¬Éú³ÉµÄÆøÌåÒ²²»Óáü×¢Ã÷¡£½âÎö:
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø