ÌâÄ¿ÄÚÈÝ

2009Äê9ÔÂ7ÈÕΫ·»ÊÐÕþ¸®ÓëÖйúº£ÑóʯÓÍ×ܹ«Ë¾¾ÙÐÐʯÓÍ»¯¹¤¡¢Ñλ¯¹¤Ò»Ì廯¹¤³ÌÆô¶¯ÒÇʽ£®Ê¯ÓÍ»¯¹¤Éú²úÖУ¬¿Éͨ¹ý·´Ó¦ÖƵü×Íé¡¢ÒÒÏ©¡¢±ûÏ©¡¢±½µÈÖØÒªÓлúÎÇë»Ø´ð£º
£¨1£©ÓлúÎïÖж¼º¬ÓÐ̼ԪËØ£¬Ì¼ÔªËصÄÔ­×ӽṹʾÒâͼÊÇ
£®
£¨2£©ÌìÈ»Æø£¨Ö÷Òª³É·ÖÊǼ×Í飩¿É×ö»·±£Æû³µµÄȼÁÏ£¬ËüÍêȫȼÉյĻ¯Ñ§·½³ÌʽÊÇ
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
CH4+2O2
 µãȼ 
.
 
CO2+2H2O
£®¿ÉȼÎïҪȼÉÕ±ØÐë¾ß±¸µÄÌõ¼þÊÇ
ÓëÑõÆø»ò¿ÕÆø½Ó´¥£»Î¶ȴﵽ×Å»ðµã
ÓëÑõÆø»ò¿ÕÆø½Ó´¥£»Î¶ȴﵽ×Å»ðµã
£®
£¨3£©Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃϵªµÄÑõ»¯ÎÓÃNO±íʾ£©ÓëCO·´Ó¦Éú³É¶þÑõ»¯Ì¼ºÍµªÆøµÄ»¯Ñ§·½³Ìʽ
2NO+2CO
 ´ß»¯¼Á 
.
 
N2+2CO2
2NO+2CO
 ´ß»¯¼Á 
.
 
N2+2CO2
£®
£¨4£©×ÔÈ»½çÖÐÏûºÄ¶þÑõ»¯Ì¼µÄÖ÷Ҫ;¾¶ÊǹâºÏ×÷Óúͺ£Ë®ÎüÊյȣ¬º£Ë®ÖеÄË®Óë¶þÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
CO2+H2O¨TH2CO3
CO2+H2O¨TH2CO3
£¬ÓÃÇâÑõ»¯ÄÆÈÜÒºÎüÊÕ¶þÑõ»¯Ì¼µÄ»¯Ñ§·½³ÌʽΪ
2NaOH+CO2¨TNa2CO3+H2O
2NaOH+CO2¨TNa2CO3+H2O
£®
·ÖÎö£º¸ù¾Ý·´Ó¦ÎïºÍÉú³ÉÎï¼°ÆäÖÊÁ¿Êغ㶨ÂÉ¿ÉÒÔÊéд»¯Ñ§·½³Ìʽ£»¿ÉȼÎïȼÉÕµÄÌõ¼þÊÇÓëÑõÆø½Ó´¥£¬Î¶ȴﵽ¿ÉȼÎïµÄ×Å»ðµã£®
½â´ð£º½â£º£¨1£©Ì¼ÔªËصÄÔ­×ӽṹʾÒâͼÊÇ£º£®
£¨2£©ÌìÈ»ÆøÍêȫȼÉյĻ¯Ñ§·½³ÌʽÊÇ£ºCH4+2O2
 µãȼ 
.
 
CO2+2H2O£®
¿ÉȼÎïҪȼÉÕ±ØÐë¾ß±¸µÄÌõ¼þÊÇÓëÑõÆø»ò¿ÕÆø½Ó´¥£¬Î¶ȴﵽ×Å»ðµã£®¹ÊÌÓëÑõÆø»ò¿ÕÆø½Ó´¥£¬Î¶ȴﵽ×Å»ðµã£®
£¨3£©ÔÚ´ß»¯¼Á×÷ÓÃϵªµÄÑõ»¯ÎÓÃNO±íʾ£©ÓëCO·´Ó¦Éú³É¶þÑõ»¯Ì¼ºÍµªÆøµÄ»¯Ñ§·½³ÌʽΪ£º2NO+2CO
 ´ß»¯¼Á 
.
 
N2+2CO2£®
£¨4£©Ë®Óë¶þÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ£ºCO2+H2O¨TH2CO3£®ÇâÑõ»¯ÄÆÈÜÒºÎüÊÕ¶þÑõ»¯Ì¼µÄ»¯Ñ§·½³ÌʽΪ£º2NaOH+CO2¨TNa2CO3+H2O£®
¹Ê´ð°¸Îª£º£¨1£©£»
£¨2£©CH4+2O2 
 µãȼ 
.
 
CO2+2H2O£»
ÓëÑõÆø»ò¿ÕÆø½Ó´¥£»Î¶ȴﵽ×Å»ðµã£»£¨3£©2NO+2CO
 ´ß»¯¼Á 
.
 
N2+2CO2£»
£¨4£©CO2+H2O¨TH2CO3£»2NaOH+CO2¨TNa2CO3+H2O£®
µãÆÀ£º½â´ð±¾ÌâÒªÕÆÎÕ»¯Ñ§·½³ÌʽµÄÊéд·½·¨ºÍȼÉÕÌõ¼þµÈ·½ÃæµÄÄÚÈÝ£¬Ö»ÓÐÕâÑù²ÅÄܶÔÏà¹Ø·½ÃæµÄÎÊÌâ×ö³öÕýÈ·µÄÅжϣ®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¾«Ó¢¼Ò½ÌÍø2009Äê9ÔÂ7ÈÕΫ·»ÊÐÕþ¸®ÓëÖйúº£ÑóʯÓÍ×ܹ«Ë¾¾ÙÐÐʯÓÍ»¯¹¤¡¢Ñλ¯¹¤Ò»Ì廯¹¤³ÌÆô¶¯ÒÇʽ£®Ê¯ÓÍ»¯¹¤Éú²úÖУ¬¿Éͨ¹ý·´Ó¦ÖƵü×Íé¡¢ÒÒÏ©¡¢±ûÏ©¡¢±½µÈÖØÒªÓлúÎÇë»Ø´ð£º
£¨1£©ÓлúÎïÖж¼º¬ÓÐ̼ԪËØ£¬Ì¼ÔªËصÄÔ­×ӽṹʾÒâͼÊÇ
 
£®
£¨2£©ÌìÈ»Æø£¨Ö÷Òª³É·ÖÊǼ×Í飩¿É×ö»·±£Æû³µµÄȼÁÏ£¬ËüÍêȫȼÉյĻ¯Ñ§·½³ÌʽÊÇ
 
£®¿ÉȼÎïҪȼÉÕ±ØÐë¾ß±¸µÄÌõ¼þÊÇ
 
£®
£¨3£©Ä¿Ç°Æû³µÎ²Æø¶à²ÉÓô߻¯×ª»¯µÄ·½·¨¼ÓÒÔÖÎÀí£¬Ð´³öÔÚ´ß»¯¼Á×÷ÓÃϵªµÄÑõ
»¯ÎÓÃNOx±íʾ£©ÓëCO·´Ó¦Éú³É¶þÑõ»¯Ì¼ºÍµªÆøµÄ»¯Ñ§·½³Ìʽ
 
£®
£¨4£©ÔÚÒ»¶¨Ìõ¼þÏ£¬±ûÏ©£¨»¯Ñ§Ê½ÎªC3H8£©ÏñÒÒÏ©Ò»Ñù¿ÉÒÔÖƵþ۱ûÏ©£¨Ëõд´úºÅPP£©£®ÉϺ£ÊÀ²©»á¼ªÏéÎﺣ±¦µÄÌîÁÏÊÇÓÅÖÊPPÃÞ£¬¾Û±ûÏ©ÊôÓÚ
 
£®
A£®Ñõ»¯Îï    B£®¾ÛºÏÎï    C£®ÌìÈ»Óлú¸ß·Ö×Ó²ÄÁÏ
£¨5£©×ÔÈ»½çÖÐÏûºÄ¶þÑõ»¯Ì¼µÄÖ÷Ҫ;¾¶ÊǹâºÏ×÷Óúͺ£Ë®ÎüÊյȣ¬º£Ë®ÖеÄË®Óë¶þÑõ»¯Ì¼·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
 
£¬ÓÃÇâÑõ»¯ÄÆÈÜÒºÎüÊÕ¶þÑõ»¯Ì¼µÄ»¯Ñ§·½³ÌʽΪ
 
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø