ÌâÄ¿ÄÚÈÝ

£¨1£©2011ÄêÊÀ½çÆøºò´ó»áÔÚÄϷǾÙÐУ¬Ä¿Ç°£¬¡°µÍ̼¡±Õý³ÉΪ¹úÃñµÄ¹²Ê¶£®
¢ÙCO2º¬Á¿Ôö¶à£¬ÎÂÊÒЧӦÔöÇ¿£®´óÆøÖÐCO2º¬Á¿Ôö¶àµÄÖ÷ÒªÔ­ÒòÊÇ
 
£®
¢ÚΪ¼õÉÙ´óÆøÖÐCO2µÄº¬Á¿¿É½«¿ÕÆøÖеÄCO2ÊäË͵½±ùÀäµÄÉÖÐÖü²Ø£®CO2ÔÚÉÖеÄÈܽâ¶È±Èͨ³£Çé¿öÏÂÔÚË®ÖеÄÈܽâ¶È´ó£¬Ô­ÒòÊÇ£¨»Ø´ðÒ»ÖÖ¼´¿É£©
 
£»µ«ÓпÆѧ¼Òµ£ÐÄÕâÑù×ö»áÔö¼ÓË®µÄËá¶È£¬µ¼Öº£ÑóÉúÎïËÀÍö£¬CO2ʹº£Ë®Ëá¶ÈÔö¼ÓµÄÔ­ÒòÊÇ£¨Óû¯Ñ§·½³Ìʽ±íʾ£©
 
£®
£¨2£©ÇëÓÃËùѧµÄ֪ʶ»Ø´ðÏÂÁÐÎÊÌ⣺
¢Ù·þÓú¬ÇâÑõ»¯ÂÁµÄÒ©ÎïÀ´ÖÎÁÆθËá¹ý¶à£¬Æä·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
 

¢Ú¼ø±ð³£ÓõÄï§Ì¬µª·Ê¡¢Á×·Ê¡¢¼Ø·ÊÈýÖÖ»¯·Ê£¬Ê×ÏÈ¿´Íâ¹Û£¬
 
µÄÊÇÁ×·Ê£¬È»ºó½«ÁíÁ½ÖÖ»¯·Ê¸÷È¡ÉÙÐí£¬·Ö±ðºÍÉÙÁ¿µÄÊìʯ»Ò·ÛÄ©»ìºÏ£¬ÑÐÄ¥£¬ÄÜÐáµ½ÆøζµÄÊÇ
 
£®
·ÖÎö£º£¨1£©¸ù¾Ý´óÆøÖÐCO2º¬Á¿Ôö¶àµÄÖ÷ÒªÔ­ÒòÊÇ´óÁ¿µÄ¿óʯȼÁÏȼÉÕÔì³ÉµÄ¡¢CO2µÄÈܽâ¶ÈËæζȽµµÍºÍѹǿÔö´ó¶øÔö´óÒÔ¼°¶þÑõ»¯Ì¼ºÍË®·´Ó¦Éú³É̼Ëá½øÐнâ´ð£»
£¨2£©¸ù¾ÝθËáµÄÖ÷Òª³É·ÖÊÇÑÎËᣬÇâÑõ»¯ÂÁºÍÑÎËá·´Ó¦Éú³ÉÂÈ»¯ÂÁºÍË®ÒÔ¼°ÈýÀ໯·ÊµÄÐÔÖÊ£¬ÀûÓÃʵÑé¼ø±ðÈýÀ໯·Ê½øÐнâ´ð£®
½â´ð£º½â£º£¨1£©¢ÙÈËÀà´óÁ¿Ê¹ÓÃú¡¢Ê¯Ó͵Ȼ¯Ê¯È¼ÁÏ£¬ÊÇÔì³É´óÆøÖжþÑõ»¯Ì¼º¬Á¿Ôö¼ÓµÄÖ÷ÒªÔ­Òò£»
¢ÚÀûÓÃÆøÌåÈܽâ¶ÈÓëζȵĹØϵ½â¾ö£¬ÉζȽϵͶþÑõ»¯Ì¼Èܽâ¶ÈÉý¸ß£¬ÇÒ¶þÑõ»¯Ì¼ÄÜÓëË®·´Ó¦Éú³É̼ËᣬʹÈÜÒº³ÊËáÐÔ£¬Ê¹º£Ë®ËáÐÔÔöÇ¿£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪCO2+H2O=H2CO3£»¹Ê´ð°¸Îª£º¢Ù»¯Ê¯È¼ÁϵĴóÁ¿Ê¹Ó㻢ÚCO2µÄÈܽâ¶ÈËæζȽµµÍºÍѹǿÔö´ó¶øÔö´ó£»CO2+H2O=H2CO3£»
£¨2£©¢ÙθËá¼´ÑÎËáÄÜÓëÇâÑõ»¯ÂÁ·¢ÉúÖкͷ´Ó¦£¬Éú³ÉÂÈ»¯ÂÁºÍË®£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪAl£¨OH£©3+3HCl=AlCl3+3H2O£»
¢ÚÁ×·Êͨ³£Îª»Ò°×É«£¬²»Í¬ÓÚµª·Ê¡¢¼Ø·Ê£¬¿É¹Û²ìÑÕÉ«¼ø±ð³öÁ×·Ê£»¶øï§Ì¬µª·ÊÖк¬ÓÐ笠ù£¬Óö¼îÊͷųöÄÜʹºìɫʯÈïÊÔÖ½±äÀ¶µÄ°±³ôζµÄ°±Æø£»
¹Ê´ð°¸Îª£º£¨2£©¢ÙAl£¨OH£©3+3HCl=AlCl3+3H2O£»¢Ú»Ò°×É«·Ûĩ״£»ï§Ì¬µª·Ê£®
µãÆÀ£º±¾ÌâÖ÷Òª¿¼²éÎÂÊÒÆøÌå¶þÑõ»¯Ì¼£¬Í¬Ñ§ÃÇÁ˽âÁ˶þÑõ»¯Ì¼ÆøÌå²úÉúµÄÖ÷ÒªÔ­Òò£¬ÒÔ¼°ÈçºÎ¼õÉÙ¶þÑõ»¯Ì¼ÆøÌ壬¾Í»á×öºÃ´ËÌ⣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÔĶÁÏÂÁÐ×ÊÁÏ£º1£©2011Äê3ÔÂ22ÈÕÊÀ½çË®ÈÕÖ®Ö÷Ìâ--³ÇÊÐÓÃË®£ºÓ¦¶Ô¶¼Êл¯ÌôÕ½£¬Ë®ÊÇÒ»ÖÖÖØÒªµÄÎïÖÊ£¬ÔÚʵÑéÊÒºÍÈÕ³£Éú»îÖÐÓÐ×ÅÊ®·ÖÖØÒªµÄ×÷Óã»2£©2010Äê4ÔÂ14ÈÕ07ʱ49·Ö£¬ÇຣÓñÊ÷·¢ÉúÁË7.1¼¶µØÕð£¬Õðºóµ±µØÉú̬»·¾³ºÍÉú»îÌõ¼þÊܵ½¼«´óÆÆ»µ£¬Ë®Ô´Êܵ½Ò»¶¨³Ì¶ÈÎÛȾ£»3£©È¥ÄêÈ붬ÒÔÀ´£¬ÎÒ¹ú±±·½¶àÊ¡Çø´óºµ£¬¶àÈÕδÓнµÑ©£¬¸øÅ©×÷Îï´øÀ´½Ï´óÓ°Ï죬×î½ü²¿·ÖµØÇøʵʩÁËÈ˹¤ÔöÓ꣨ѩ£©£®¸ù¾Ý×ÊÁϻشðÎÊÌ⣺
£¨1£©ÔÖÇøÈËÃÇÈÕ³£Éú»îÓÃË®±ØÐè¾­¹ýһϵÁеĴ¦Àí²ÅÄÜʹÓãºÏòË®ÑùÖмÓÈëÃ÷·¯£¬¾­Èܽ⡢¾²ÖᢳÁµí¡¢ÔÙ
¹ýÂË
¹ýÂË
£¨Ìî²Ù×÷Ãû³Æ£©£¬³ýÈ¥²»ÈÜÐÔÔÓÖÊ£¬¸Ã²Ù×÷Óõ½²£Á§°ô£¬²£Á§°ô×÷ÓÃÊÇ
ÒýÁ÷ÒºÌå
ÒýÁ÷ÒºÌå
£¬È»ºó¼ÓÈë»îÐÔÌ¿£¬ÀûÓÃÆä
Îü¸½
Îü¸½
ÐÔ³ýÈ¥Òì棬ÔÙɱ¾úÏû¶¾£¬µÃµ½Éú»îÓÃË®£»ËùµÃ³ÎÇåµÄÉú»îÓÃË®ÊôÓÚ
»ìºÏÎï
»ìºÏÎï
£¨¡°´¿¾»Î»ò¡±»ìºÏÎ£©
£¨2£©ÓûÅжϵõ½µÄÉú»îÓÃË®ÊÇӲˮ»¹ÊÇÈíË®£¬¿É¼ÓÈë
·ÊÔíË®
·ÊÔíË®
½øÐмìÑ飬Éú»îÖг£Í¨¹ý
Öó·Ð
Öó·Ð
µÄ·½·¨½µµÍË®µÄÓ²¶È£»
£¨3£©Óû³ÎÇåµÄÉú»îÓÃË®±ä³ÉÕôÁóË®£¬¿É¾­¹ýÕôÁó£¬ÆäÖзÅÈë·ÐʯĿµÄÊÇ
·ÀÖ¹¼ÓÈÈʱˮ±©·Ð
·ÀÖ¹¼ÓÈÈʱˮ±©·Ð
£®
£¨4£©È˹¤½µÓê¶Ô¿¹ºµ·¢»ÓÁ˺ܴó×÷Ó㮳£ÓõÄÈ˹¤½µÓê¼ÁÓе⻯Òø£¨AgI£©ºÍ¸É±ù£®µâ»¯ÒøÊôÓÚ
»¯ºÏÎï
»¯ºÏÎï
£¨Ìî¡°µ¥ÖÊ¡±»ò¡°»¯ºÏÎ£©£¬¸É±ùÓÃÓÚÈ˹¤½µÓêÖ÷ÒªÊÇÀûÓøɱùÉý»ªÊ±»á
ÎüÊÕ
ÎüÊÕ
£¨Ìî¡°ÎüÊÕ¡±»ò¡°·Å³ö¡±£©´óÁ¿ÈÈ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø