ÌâÄ¿ÄÚÈÝ

ÕðÔÖ¹ýºó£¬ÒûÓÃË®µÄÏû¶¾É±¾ú³ÉΪÒÖÖÆ´ó¹æÄ£´«È¾ÐÔ¼²²¡±¬·¢µÄÓÐЧ·½·¨Ö®Ò»¡£Æ¯°×·ÛÊdz£ÓõÄÏû¶¾¼Á¡£Æ¯°×·ÛµÄÖ÷Òª³É·ÖÊÇ´ÎÂÈËá¸Æ[Ca(ClO)2]ºÍÂÈ»¯¸Æ£¬ÓÐЧ³É·ÖÊÇ´ÎÂÈËá¸Æ¡£Æ¯°×·ÛµÄƯ°×Ô­ÀíÊÇ´ÎÂÈËá¸ÆÓëËá·´Ó¦²úÉúÓÐƯ°×ÐÔµÄÎïÖÊ´ÎÂÈË᣺¡¡¡¡
£¨1£©¹¤ÒµÉϽ«ÂÈÆøͨÈëʯ»ÒÈé[Ca(OH)2]ÖÆȡƯ°×·Û£¬Í¬Ê±ÓÐË®Éú³É£¬Æä·´Ó¦»¯Ñ§·½³ÌʽΪ£º¡¡                   ¡£
£¨2£©Æ¯°×·ÛÈÜÓÚË®ºó£¬ÊÜ¿ÕÆøÖеÄCO2×÷Ó㬼´²úÉúÓÐƯ°×¡¢É±¾ú×÷ÓõĴÎÂÈËᣬ»¯Ñ§·½³ÌʽΪ£º¡¡                   ¡£

£¨1£©2Cl2+2Ca(OH)2=Ca(ClO)2+CaCl2+2H2O£»£¨2£©Ca(ClO)2+CO2+H2O=CaCO3¡ý+2HClO 

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨8·Ö£©ÎÒÊÐij»¯¹¤³§ÅŷŵķÏÒºÖк¬ÓÐÁòËáÍ­ºÍÁòËáÑÇÌú£®Ä³»¯Ñ§ÐËȤС×éµÄͬѧȡÁËÊÊÁ¿µÄÉÏÊö·ÏÒºÑùÆ·£¬½«Ò»¶¨Á¿Ð¿·Û¼ÓÈëÑùÆ·ÖУ¬³ä·Ö·´Ó¦ºó¹ýÂË£¬µÃµ½ÂËÒºAºÍ¹ÌÌåB£®Çë»Ø´ðÏÂÁÐÓйØÎÊÌ⣺
£¨1£©¹ØÓÚÂËÒºAËùº¬ÈÜÖʵIJÂÏëÖУ¬²»ºÏÀíµÄÊÇ       £¨ÌîдÐòºÅ£©£®
¢Ù²ÂÏëÒ»£ºÖ»ÓÐÁòËáп£»                       ¢Ú²ÂÏë¶þ£ºÁòËáп¡¢ÁòËáÑÇÌú£»
¢Û²ÂÏëÈý£ºÁòËáп¡¢ÁòËáÑÇÌú¡¢ÁòËáÍ­£»         ¢Ü²ÂÏëËÄ£ºÁòËáп¡¢ÁòËáÍ­
£¨2£©Éè¼Æ¼òµ¥ÊµÑ飬ȷ¶¨¡°²ÂÏë¶þ¡±¶ÔÓ¦µÄ¹ÌÌåBµÄ³É·Ö£º
ʵÑé²Ù×÷£º                                                                                             
ʵÑéÏÖÏóºÍ½áÂÛ£º                                                                                                                                            
£¨3£©Ð´³öËùÉæ¼°µ½µÄ»¯Ñ§·´Ó¦·½³Ìʽ
                                                                         
                                                                        
£¨4£©·´Ó¦ºóÎö³ö½ðÊôµÄÖÊÁ¿     £¨Ñ¡Ìî¡°Ò»¶¨¡±»ò¡°²»Ò»¶¨¡±£©±È²Î¼Ó·´Ó¦µÄ½ðÊôÖÊÁ¿Ð¡£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø