ÌâÄ¿ÄÚÈÝ
»¯Ñ§ÐËȤС×éµÄͬѧÉè¼ÆÁËÓÃÒ»Ñõ»¯Ì¼ÆøÌ廹ÔÑõÆøÌúµÄʵÑé×°Öã¬ÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÎªÁ˱ÜÃâ²£Á§¹ÜaÔÚ¼ÓÈÈʱ¿ÉÄÜ·¢Éú±¬Õ¨£¬¼ÓÈÈÇ°Ó¦¡¡¡¡£®
£¨2£©a¹ÜÖÐFe2O3·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¡¡¡¡£®
£¨3£©B×°ÖóýÁËÎüÊÕCO2ÆøÌåÍ⣬»¹¡¡¡¡£®Ð´³öB×°ÖÃÖÐNaOH·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡¡£®
£¨4£©Èôa¹ÜÖÐÑõ»¯ÌúÈ«²¿»¹Ô³ÉÌú£¬ÀäÈ´ºó³ÆÁ¿ÌúµÄÖÊÁ¿±È·´Ó¦Ç°Ñõ»¯ÌúµÄÖÊÁ¿¼õÉÙÁË2.4g£¬Ôò¼ÓÈëa¹ÜÖеÄÑõ»¯ÌúµÄÖÊÁ¿ÊÇ¡¡¡¡g£®
£¨1£©¸ù¾ÝÒ»Ñõ»¯Ì¼¾ßÓпÉȼÐÔ£¬Óë¿ÕÆø»ìºÏ£¬¼ÓÈÈ¿ÉÄܻᷢÉú±¬Õ¨½øÐзÖÎö£» £¨2£©Ò»Ñõ»¯Ì¼ÔÚ¸ßÎÂÏÂÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬¾Ý´ËÊéд·½³Ìʽ£» £¨3£©¸ù¾ÝÇâÑõ»¯ÄƵÄÐÔÖÊ£¬×°ÖÃCÖеÄÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔ°ÑβÆøÖеĶþÑõ»¯Ì¼È«²¿³ýÈ¥£¬Í¬Ê±°ÑÊ£ÓàµÄÒ»Ñõ»¯Ì¼ÆøÌåÊÕ¼¯£¬ÒÔ·ÀÖ¹Ò»Ñõ»¯Ì¼Åųö¶øÎÛȾ¿ÕÆø£¬²¢¾Ý·´Ó¦ÔÀíÊéд·½³Ìʽ£» £¨4£©Ò»Ñõ»¯Ì¼»¹ÔÑõ»¯Ìú·´Ó¦ºó¹ÌÌåÖÊÁ¿¼õÉÙµÄÖÊÁ¿¼´ÎªÑõ»¯ÌúÖÐÑõÔªËصÄÖÊÁ¿£¬ÀûÓÃÑõ»¯ÌúÖÐÌúÓëÑõÔªËصÄÖÊÁ¿¹Øϵ£¬ÓÉÑõÔªËصÄÖÊÁ¿¼ÆËã³öÉú³ÉÌúµÄÖÊÁ¿£¬²¢½ø¶ø¼ÆËãÑõ»¯ÌúµÄÖÊÁ¿»òͨ¹ýÑõ»¯ÌúÖÐÑõÔªËصÄÖÊÁ¿·ÖÊý¼ÆË㣮 | |
½â´ð£º | ½â£º£¨1£©Ò»Ñõ»¯Ì¼¾ßÓпÉȼÐÔ£¬Óë¿ÕÆø»ìºÏ£¬¼ÓÈÈ¿ÉÄܻᷢÉú±¬Õ¨£¬ËùÒÔÔÚ¼ÓÈÈÇ°ÒªÏÈͨһÑõ»¯Ì¼Åž¡²£Á§¹ÜÄÚ¿ÕÆø·ÀÖ¹Ò»Ñõ»¯Ì¼²»´¿·¢Éú±¬Õ¨£» £¨2£©ÔÚ¸ßÎÂÌõ¼þÏ£¬Ò»Ñõ»¯Ì¼ÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ3CO+Fe2O32Fe+3CO2£» £¨3£©×°ÖÃCÄÚÊ¢ÓÐÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔ³ýȥβÆøÖеĶþÑõ»¯Ì¼£¬Í¬Ê±Ò»Ñõ»¯Ì¼ÆøÌåÅųö×°ÖÃÄÚµÄÈÜÒº¶ø±»ÊÕ¼¯£¬·ÀÖ¹Ôì³É¿ÕÆøÎÛȾ£»¶þÑõ»¯Ì¼ÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³É̼ËáÄƺÍË®£¬·½³ÌʽÊÇ£ºCO2+2NaOH═Na2CO3+H2O£» £¨4£©Ñõ»¯ÌúFe2O3ÖÐFeÓëOÔªËصÄÖÊÁ¿±È=£¨56¡Á2£©£º£¨16¡Á3£©=7£º3£¬Òò´Ë£¬Ñõ»¯ÌúÖÐÑõÔªËØÖÊÁ¿Îª2.4gʱ£¬ÌúÔªËصÄÖÊÁ¿=2.4g¡Á=5.6g£¬ÔòÑõ»¯ÌúµÄÖÊÁ¿Îª£º2.4g+5.6g=8g£» ¹Ê´ð°¸Îª£º£¨1£©ÏÈͨһÑõ»¯Ì¼Åž¡²£Á§¹ÜÄÚ¿ÕÆø£» £¨2£©3CO+Fe2O32Fe+3CO2£» £¨3£©¿ÉÊÕ¼¯´¿¾»µÄÒ»Ñõ»¯Ì¼£¬·ÀÖ¹Ò»Ñõ»¯Ì¼ÒݳöÎÛȾ¿ÕÆø£»CO2+2NaOH═Na2CO3+H2O£» £¨4£©8£® |