ÌâÄ¿ÄÚÈÝ

»¯Ñ§ÐËȤС×éµÄͬѧÉè¼ÆÁËÓÃÒ»Ñõ»¯Ì¼ÆøÌ廹ԭÑõÆøÌúµÄʵÑé×°Öã¬ÈçͼËùʾ£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÎªÁ˱ÜÃâ²£Á§¹ÜaÔÚ¼ÓÈÈʱ¿ÉÄÜ·¢Éú±¬Õ¨£¬¼ÓÈÈÇ°Ó¦¡¡¡¡£®

£¨2£©a¹ÜÖÐFe2O3·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¡¡¡¡£®   

£¨3£©B×°ÖóýÁËÎüÊÕCO2ÆøÌåÍ⣬»¹¡¡¡¡£®Ð´³öB×°ÖÃÖÐNaOH·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡¡£®

£¨4£©Èôa¹ÜÖÐÑõ»¯ÌúÈ«²¿»¹Ô­³ÉÌú£¬ÀäÈ´ºó³ÆÁ¿ÌúµÄÖÊÁ¿±È·´Ó¦Ç°Ñõ»¯ÌúµÄÖÊÁ¿¼õÉÙÁË2.4g£¬Ôò¼ÓÈëa¹ÜÖеÄÑõ»¯ÌúµÄÖÊÁ¿ÊÇ¡¡¡¡g£®

·ÖÎö£º

£¨1£©¸ù¾ÝÒ»Ñõ»¯Ì¼¾ßÓпÉȼÐÔ£¬Óë¿ÕÆø»ìºÏ£¬¼ÓÈÈ¿ÉÄܻᷢÉú±¬Õ¨½øÐзÖÎö£»

£¨2£©Ò»Ñõ»¯Ì¼ÔÚ¸ßÎÂÏÂÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬¾Ý´ËÊéд·½³Ìʽ£»

£¨3£©¸ù¾ÝÇâÑõ»¯ÄƵÄÐÔÖÊ£¬×°ÖÃCÖеÄÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔ°ÑβÆøÖеĶþÑõ»¯Ì¼È«²¿³ýÈ¥£¬Í¬Ê±°ÑÊ£ÓàµÄÒ»Ñõ»¯Ì¼ÆøÌåÊÕ¼¯£¬ÒÔ·ÀÖ¹Ò»Ñõ»¯Ì¼Åųö¶øÎÛȾ¿ÕÆø£¬²¢¾Ý·´Ó¦Ô­ÀíÊéд·½³Ìʽ£»

£¨4£©Ò»Ñõ»¯Ì¼»¹Ô­Ñõ»¯Ìú·´Ó¦ºó¹ÌÌåÖÊÁ¿¼õÉÙµÄÖÊÁ¿¼´ÎªÑõ»¯ÌúÖÐÑõÔªËصÄÖÊÁ¿£¬ÀûÓÃÑõ»¯ÌúÖÐÌúÓëÑõÔªËصÄÖÊÁ¿¹Øϵ£¬ÓÉÑõÔªËصÄÖÊÁ¿¼ÆËã³öÉú³ÉÌúµÄÖÊÁ¿£¬²¢½ø¶ø¼ÆËãÑõ»¯ÌúµÄÖÊÁ¿»òͨ¹ýÑõ»¯ÌúÖÐÑõÔªËصÄÖÊÁ¿·ÖÊý¼ÆË㣮

½â´ð£º

½â£º£¨1£©Ò»Ñõ»¯Ì¼¾ßÓпÉȼÐÔ£¬Óë¿ÕÆø»ìºÏ£¬¼ÓÈÈ¿ÉÄܻᷢÉú±¬Õ¨£¬ËùÒÔÔÚ¼ÓÈÈÇ°ÒªÏÈͨһÑõ»¯Ì¼Åž¡²£Á§¹ÜÄÚ¿ÕÆø·ÀÖ¹Ò»Ñõ»¯Ì¼²»´¿·¢Éú±¬Õ¨£»

£¨2£©ÔÚ¸ßÎÂÌõ¼þÏ£¬Ò»Ñõ»¯Ì¼ÓëÑõ»¯Ìú·´Ó¦Éú³ÉÌúºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ3CO+Fe2O32Fe+3CO2£»

£¨3£©×°ÖÃCÄÚÊ¢ÓÐÇâÑõ»¯ÄÆÈÜÒº¿ÉÒÔ³ýȥβÆøÖеĶþÑõ»¯Ì¼£¬Í¬Ê±Ò»Ñõ»¯Ì¼ÆøÌåÅųö×°ÖÃÄÚµÄÈÜÒº¶ø±»ÊÕ¼¯£¬·ÀÖ¹Ôì³É¿ÕÆøÎÛȾ£»¶þÑõ»¯Ì¼ÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦Éú³É̼ËáÄƺÍË®£¬·½³ÌʽÊÇ£ºCO2+2NaOH═Na2CO3+H2O£»

£¨4£©Ñõ»¯ÌúFe2O3ÖÐFeÓëOÔªËصÄÖÊÁ¿±È=£¨56¡Á2£©£º£¨16¡Á3£©=7£º3£¬Òò´Ë£¬Ñõ»¯ÌúÖÐÑõÔªËØÖÊÁ¿Îª2.4gʱ£¬ÌúÔªËصÄÖÊÁ¿=2.4g¡Á=5.6g£¬ÔòÑõ»¯ÌúµÄÖÊÁ¿Îª£º2.4g+5.6g=8g£»

¹Ê´ð°¸Îª£º£¨1£©ÏÈͨһÑõ»¯Ì¼Åž¡²£Á§¹ÜÄÚ¿ÕÆø£»

£¨2£©3CO+Fe2O32Fe+3CO2£»

£¨3£©¿ÉÊÕ¼¯´¿¾»µÄÒ»Ñõ»¯Ì¼£¬·ÀÖ¹Ò»Ñõ»¯Ì¼ÒݳöÎÛȾ¿ÕÆø£»CO2+2NaOH═Na2CO3+H2O£»

£¨4£©8£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2008?¾£ÖÝ£©Ä³¹¤³§ÅŷŵÄβÆøÖÐÖ»¿ÉÄÜ´æÔÚCOºÍCO2Á½ÖÖÆøÌ壮ΪÁ˽øÒ»²½È·ÈÏ£¬Ä³»¯Ñ§ÐËȤС×éµÄͬѧÉèÈçÈçͼËùʾµÄ×°ÖýøÐмìÑ飮ʵÑéÖпɹ©Ñ¡ÔñµÄÒ©Æ·ÓУºNa2CO3ÈÜÒº¡¢Ï¡H2SO4¡¢Å¨H2SO4¡¢¡¢NaOHŨÈÜÒº¡¢³ÎÇåµÄʯ»ÒË®£®
Çë½áºÏÌâÒâºÍ×°Öüäͼ£¬»Ø´ðÌá³öµÄÏÂÁÐÎÊÌ⣺

£¨1£©Ö¤Ã÷βÆøÖдæÔÚCO2µÄÏÖÏóÊÇ
³ÎÇåʯ»ÒË®±ä»ë×Ç
³ÎÇåʯ»ÒË®±ä»ë×Ç
£®ÈôβÆøÖв»´æÔÚCO2£¬ÉÏÊö×°ÖÃ×éºÏÖпÉÒÔ³·³ýµÄÊÇ
ABCD
ABCD
£¨ÌîÐòºÅ£©£»ÈôβÆøÖдæÔÚCO2£¬ÉÏÊö×°Öö¼²»Äܳ·³ý£¬Çë¼ÌÐø»Ø´ðÎÊÌ⣮
£¨2£©B×°ÖÃÖÐӦʢװµÄÒ©Æ·ÊÇ
NaOHŨÈÜÒº
NaOHŨÈÜÒº
£®Æä×÷ÓÃÊÇ
ÎüÊÕ¶þÑõ»¯Ì¼
ÎüÊÕ¶þÑõ»¯Ì¼
£»
£¨3£©C×°ÖõÄ×÷Óü°¶ÔʵÑéµÄÖ¸µ¼ÒâÒåÊÇ
¼ìÑé¶þÑõ»¯Ì¼ÊÇ·ñ±»ÍêÈ«ÎüÊÕ
¼ìÑé¶þÑõ»¯Ì¼ÊÇ·ñ±»ÍêÈ«ÎüÊÕ
£»
£¨4£©D×°ÖÃÖÐӦʢװµÄÒ©Æ·ÊÇ
NaOHŨÈÜÒº
NaOHŨÈÜÒº
£¬Æä×÷ÓÃÊÇ
ÎüÊÕÊ£ÓàµÄ¶þÑõ»¯Ì¼
ÎüÊÕÊ£ÓàµÄ¶þÑõ»¯Ì¼
£»
£¨5£©Ö¤Ã÷βÆøÖдæÔÚCOµÄÓйØÏÖÏóÊÇ
EÖÐCuOÓɺÚÉ«±ä³ÉºìÉ«£¬FÖгÎÇåʯ»ÒË®±ä»ë×Ç
EÖÐCuOÓɺÚÉ«±ä³ÉºìÉ«£¬FÖгÎÇåʯ»ÒË®±ä»ë×Ç
£»
£¨6£©³öÓÚ¶Ô»·¾³±£»¤µÄ¿¼ÂÇ£¬ÇëÄãÌá³öÍêÉƸÃ×°ÖõĽ¨Ò飺
Óþƾ«µÆµãȼβÆø
Óþƾ«µÆµãȼβÆø
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø