ÌâÄ¿ÄÚÈÝ

ϱíÊÇij³ÇÊоÓÃñ³£ÓõÄÆøÌåȼÁϼ۸ñºÍÈÈÖµ£¬Í¨¹ý·ÖÎö»Ø´ðÏÂÁÐÎÊÌ⣺
ȼÁÏ ¼Û¸ñ ÈÈÖµ
úÆø 1.25Ôª/©K 1.56¡Á107kJ/©K
ʯÓÍÒº»¯Æø 2.50Ôª/©K 4.5¡Á107kJ/©K
ÌìÈ»Æø 1.4Ôª/©K 3.9¡Á107kJ/©K
£¨1£©´Ó¾­¼Ã½Ç¶È¿¼ÂÇ£¬Ñ¡ÄÄÖÖȼÁϸüÊʺϣ¿______£»Ô­ÒòÊÇ______£®
£¨2£©ÊµÑéÖ¤Ã÷£ºÍ¬ÎÂͬѹÏ£¬ÏàͬÌå»ýµÄÈκÎÆøÌåÖлáÓÐÏàͬµÄ·Ö×ÓÊý£®¾Ý´Ë½áÂۻشð
ÎÊÌ⣺
¢Ù½«Í¬Ìå»ýµÄCOºÍCH4»ìºÏ£¬ËùµÃ»ìºÏÆøÌåÖÐC¡¢H¡¢OÔªËصÄÔ­×Ó¸öÊý±ÈΪ______£¬C¡¢HÔªËØÖÊÁ¿±ÈΪ______£®
¢Ú·Ö±ðд³öCOºÍCH4ȼÉյĻ¯Ñ§·½³Ìʽ£º______£»______£®
£¨1£©µ¥Î»¼Û¸ñ¹ºÂòµÄúÆø¡¢Òº»¯Ê¯ÓÍÆø¡¢ÌìÈ»ÆøµÄȼÁÏ·Ö±ðΪ£º1.56¡Á107kJ/©K¡Â1.25Ôª/©K=1.25¡Á107kJ/Ôª£¬4.5¡Á107kJ/©K¡Â2.50Ôª/©K=1.80kJ/Ôª£¬
3.9¡Á107kJ/©K¡Â1.4Ôª/©K=2.79kJ/Ôª£»
ÓɼÆËã¿ÉÖª£¬´Ó¾­¼Ã½Ç¶È¿¼ÂÇ£¬¹ºÂòʹÓÃÌìÈ»Æø×î¾­¼Ã£®¹ÊÌÌìÈ»Æø£»µ¥Î»¼Û¸ñ¹ºÂòµÄÌìÈ»ÆøȼÉÕʱÊͷŵÄÈÈÁ¿×î¶à£®
£¨2£©¢ÙͬÌå»ýµÄCOºÍCH4Öк¬ÓÐÏàͬµÄ·Ö×ÓÊý£¬ËùµÃ»ìºÏÆøÌåÖÐC¡¢H¡¢OÔªËصÄÔ­×Ó¸öÊý±ÈΪ£º2£º4£º1£¬C¡¢HÔªËØÖÊÁ¿±ÈΪ£º£¨12¡Á2£©£º£¨1¡Á4£©=6£º1£®¹ÊÌ2£º4£º1£»6£º1£®
¢ÚÒ»Ñõ»¯Ì¼È¼ÉյĻ¯Ñ§·½³ÌʽΪ£º2CO+O2
µãȼ
.
.
 2CO2£®
¼×ÍéȼÉյĻ¯Ñ§·½³ÌʽΪ£ºCH4+2O2
µãȼ
.
.
CO2+2H2O£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø