ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÏÖÓÐÈçͼËùʾµÄʵÑé×°Öãº
£¨1£©Ð´³ö±êºÅÒÇÆ÷XµÄÃû³Æ£º_____________¡£
£¨2£©A×°ÖÿÉÓÃÓÚÖƶþÑõ»¯Ì¼µÄ»¯Ñ§·½³ÌʽΪ£º_________________¡£¸Ã·¢Éú×°Öû¹¿ÉÒÔÓÃÀ´ÖÆÈ¡µÄÆøÌåÊÇ________£¬Ð´·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º___________________¡£
£¨3£©ÓÃD×°ÖÃÊÕ¼¯¶þÑõ»¯Ì¼ÆøÌåʱ£¬ÈçºÎÑéÂú£º___________________¡£
£¨4£©ÊµÑéÊÒÐèÉÙÁ¿¼×ÍéÆø£¬¿ÉÓüÓÈÈÎÞË®´×ËáÄÆÓë¼îʯ»ÒµÄ¹ÌÌå»ìºÏÎïÖƵá£ÖƼ×ÍéÆøµÄ·¢Éú×°ÖÃӦѡÓÃ_______£¨Ìî×Öĸ£©×°Öã»ÊÕ¼¯¼×ÍéÆø¿ÉÑ¡ÓÃC»òE×°Öã¬ÓÉ´ËÍƶϼ×ÍéÆøÌå¾ßÓеÄÎïÀíÐÔÖÊÊÇ_____________¡£
¡¾´ð°¸¡¿¼¯ÆøÆ¿ CaCO3+2HCl=CaCl2+H2O+CO2 O2 ½«È¼×ŵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú B ²»Ò×ÈÜÓÚË®ÇÒÃܶȱȿÕÆøС
¡¾½âÎö¡¿
£¨1£©ÒÇÆ÷XµÄÃû³ÆΪ£º¼¯ÆøÆ¿¡£
£¨2£©ÖƶþÑõ»¯Ì¼ÓÃ̼Ëá¸ÆºÍÏ¡ÑÎËá·´Ó¦Éú³ÉÂÈ»¯¸ÆºÍ¶þÑõ»¯Ì¼£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º¡£¸Ã·¢Éú×°Öû¹¿ÉÒÔÓÃÀ´ÖÆÈ¡µÄÆøÌåÊÇÑõÆø£¬¶þÑõ»¯ÃÌ´ß»¯¹ýÑõ»¯Çâ·´Ó¦Éú³ÉË®ºÍÑõÆø£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º¡£
£¨3£©ÓÃD×°ÖÃÊÕ¼¯¶þÑõ»¯Ì¼ÆøÌåʱ£¬ÑéÂú¿ÉÒÔ£º½«È¼×ŵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬Ä¾ÌõϨÃð£¬ÔòÂú¡£
£¨4£©¼ÓÈÈÎÞË®´×ËáÄÆÓë¼îʯ»ÒµÄ¹ÌÌå»ìºÏÎïÖƵü×Í飬ÊôÓÚ¹Ì-¹Ì»ìºÏ¼ÓÈÈÐÍ£¬·¢Éú×°ÖÃӦѡÓÃB×°Öã»ÊÕ¼¯¼×ÍéÆø¿ÉÑ¡ÓÃC»òE×°Öã¬ÓÉ´ËÍƶϼ×ÍéÆøÌå¾ßÓеÄÎïÀíÐÔÖÊÊDz»Ò×ÈÜÓÚË®ÇÒÃܶȱȿÕÆøС¡£
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÀïÓÐһƿ³£ÓõÄÎÞÉ«ÈÜÒº£¬Òò±£¹Ü²»µ±£¬Æä²ÐȱµÄ±êÇ©ÖÐֻʣÏ¡°Na¡±ºÍ¡°10%¡±×ÖÑù(ÈçͼËùʾ)¡£Ð¡Ç¿ºÍС»ªÍ¬Ñ§ºÜ¸ÐÐËȤ£¬¾ö¶¨¶ÔÆä³É·Ö½øÐÐ̽¾¿¡£
£¨Ìá³öÎÊÌ⣩ÕâÆ¿ÊÔ¼Á¿ÉÄÜÊÇʲôÈÜÒºÄØ£¿
£¨½»Á÷ÌÖÂÛ£©¸ù¾ÝÊÜËð±êÇ©µÄÇé¿öÅжϣ¬ÕâÆ¿ÊÔ¼Á²»¿ÉÄÜÊÇ____¡£(ÌîÐòºÅ)
A Ëá B ¼î C ÑÎ
£¨²éÔÄ×ÊÁÏ£©¢ñ³õÖг£¼ûº¬ÄƵĻ¯ºÏÎïÓУºNaCl¡¢NaOH¡¢Na2CO3¡¢NaHCO3¡£
¢òNa2CO3ºÍNaHCO3µÄË®ÈÜÒº¶¼³Ê¼îÐÔ¡£
¢óÊÒÎÂ()ʱ£¬²â¶¨ËÄÖÖÎïÖʵÄÈܽâ¶ÈÊý¾ÝÈçÏ£º
ÎïÖÊ | NaCl | NaOH | Na2CO3 | NaHCO3 |
Èܽâ¶Èg | 36 | 109 | 215 | 9.6 |
С»ª¸ù¾ÝÊÔ¼ÁÆ¿±ê×¢µÄÖÊÁ¿·ÖÊýΪ10%ºÍÉϱíÖеÄÈܽâ¶ÈÊý¾ÝÅжϣ¬ÕâÆ¿ÊÔ¼Á²»¿ÉÄÜÊÇ___¡£
£¨×÷³ö²ÂÏ룩¢Ù¿ÉÄÜÊÇNaCl£»¢Ú¿ÉÄÜÊÇNa2CO3£»¢Û¿ÉÄÜÊÇ____¡£
£¨ÊµÑé̽¾¿£©(1)СǿÓýྻµÄ²£Á§°ôպȡÊÔÒºÓÚpHÊÔÖ½ÉÏ£¬²âµÃpH7£¬ÔòÕâÆ¿ÊÔ¼Á²»¿ÉÄÜÊÇ____¡£
(2)СǿΪÁ˼ìÑé¸ÃÈÜÒºÊÇNaOHÈÜÒº»¹ÊÇNa2CO3ÈÜÒº£¬ËûÓÖ½øÐÐÁËÈçÏÂʵÑé¡£
ʵÑé²½Öè | ʵÑéÏÖÏó | ½áÂÛ¼°»¯Ñ§·½³Ìʽ |
¢ÙÈ¡ÉÙÁ¿ÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼Ó____¡£ | ²úÉú´óÁ¿ÆøÅÝ | ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º___¡£ |
¢Ú°Ñ²úÉúµÄÆøÌåͨÈë³ÎÇåµÄʯ»ÒË®ÖС£ | ³ÎÇåµÄʯ»ÒË®±ä»ë×Ç | ²ÂÏë¢ÚÕýÈ·¡£·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____¡£ |
£¨ÍØÕ¹ÑÓÉ죩ÇëÄãÑ¡ÔñÓëСǿ²»Í¬Àà±ðµÄÊÔ¼Á£¬À´¼ø±ðNaOHÈÜÒººÍNa2CO3ÈÜÒº£¬ÄãÑ¡ÔñµÄÊÔ¼ÁÊÇ____¡£