ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ð´³öÏÂÁÐÐðÊöÉæ¼°µ½µÄ»¯Ñ§·½³Ìʽ¡£

£¨1£©ÇâÄÜÔ´ÒÔÈÈÖµ¸ß¡¢ÁãÎÛȾ¡¢ÖÆÇâÔ­ÁϷḻ¶ø³ÉΪδÀ´×îÀíÏëȼÁÏ¡£

___________________________________ ¡£

£¨2£©ºìÁ×ȼÉÕʱÒòÆä°×ÑÌŨºñ£¬¾üÊÂÉϳ£½«ÆäÖƳÉÑÌÄ»µ¯¡£

___________________________________ ¡£

£¨3£©¹¤ÒµÉϳ£²ÉÓÃìÑÉÕʯ»ÒʯµÄ·½·¨ÖÆÈ¡Éúʯ»Ò¡£

___________________________________ ¡£

£¨4£©Ä³Ð©¹¤³§·ÏË®Öк¬ÓÐÁòËᣬ´¦Àíʱ¿ÉͨÈëÊÊÁ¿°±Ë®£¬·´Ó¦ºó»¹Äܵõ½µª·ÊÁòËá李£

___________________________________ ¡£

£¨5£©ÓÉÓÚijЩÈÜÒºÒ×Óë¿ÕÆøÖÐһЩÆøÌå·´Ó¦£¬¹ÊÓýºÍ·µÎ¹ÜÎüÈ¡ÈÜҺʱ£¬ÒªÔÚÒºÃæÉÏÏȼ·³ö½ºÍ·ÖпÕÆø£¬ÔÙÉìÈëÒºÌåÖÐÎüÈ¡£¬±ÈÈçÓýºÍ·µÎ¹ÜÎüÈ¡ÇâÑõ»¯ÄÆÈÜÒº¡£

___________________________________ ¡£

£¨6£©Ê³ÑγýÁËÄÜ×÷µ÷ζƷÍ⣬ÔÚÂȼҵÉÏͨ¹ýµç½âʳÑÎË®£¬¿ÉµÃµ½ÉռÂÈÆø¡¢ÇâÆøµÈÖØÒªµÄ¹¤ÒµÔ­ÁÏ¡£

___________________________________ ¡£

¡¾´ð°¸¡¿ ÂÔ ÂÔ ÂÔ ÂÔ ÂÔ ÂÔ

¡¾½âÎö¡¿Êéд»¯Ñ§·½³ÌʽµÄÒÀ¾ÝÊÇÖÊÁ¿Êغ㶨ÂÉ£¬Êéд²½ÖèÊÇ£ºÒ»Ð´¶þÅäÈý±êËIJ顣£¨1£©ÇâÆøȼÉÕÉú³ÉË®£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2H2+O2µãȼ2H2O£»£¨2£©ºìÁ×ȼÉÕÉú³ÉÎåÑõ»¯¶þÁ×£º4P+5O2µãȼ2P2O5£»£¨3£©¸ßÎÂìÑÉÕʯ»ÒʯÉú³ÉÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼£ºCaCO3¸ßÎÂCaO+CO2¡ü£»£¨4£©ÁòËáÓ백ˮ·´Ó¦Éú³ÉÁòËá泥ºH2SO4+2NH3©qH2O==(NH4)2SO4+2H2O£»£¨5£©ÇâÑõ»¯ÄÆÒ×Óë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄƺÍË®£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2NaOH+CO2===Na2CO3+H2O£»£¨6£©µç½âʳÑÎË®£¬¿ÉµÃµ½ÉռÂÈÆø¡¢ÇâÆø£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2NaCl+2H2O==2NaOH+Cl2¡ü+H2¡ü¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿»¯Ñ§¿Îºó£¬»¯Ñ§ÐËȤС×éµÄͬѧÔÚÕûÀíʵÑé×Àʱ£¬·¢ÏÖÓÐһƿÇâÑõ»¯ÄÆÈÜҺûÓÐÈûÏðƤÈû£¬Õ÷µÃÀÏʦͬÒâºó£¬¿ªÕ¹ÁËÒÔÏÂ̽¾¿£º

[Ìá³öÎÊÌâ1] ¸ÃÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊÁËÄØ£¿

[ʵÑé̽¾¿1]

ʵÑé²Ù×÷

ʵÑéÏÖÏó

ʵÑé½áÂÛ

È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓ___________£¬²¢²»¶ÏÕñµ´¡£

ÓÐÆøÅݲúÉú¡£

ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË¡£

[Ìá³öÎÊÌâ2] ¸ÃÇâÑõ»¯ÄÆÈÜÒºÊÇÈ«²¿±äÖÊ»¹ÊDz¿·Ö±äÖÊÄØ£¿

[²ÂÏëÓë¼ÙÉè]²ÂÏ룺1£ºÇâÑõ»¯ÄÆÈÜÒº²¿·Ö±äÖÊ¡£ ²ÂÏë2£ºÇâÑõ»¯ÄÆÈÜҺȫ²¿±äÖÊ¡£

[²éÔÄ×ÊÁÏ] £¨1£© ÂÈ»¯¸ÆÈÜÒº³ÊÖÐÐÔ¡£

£¨2£© ÂÈ»¯¸ÆÈÜÒºÄÜÓë̼ËáÄÆÈÜÒº·´Ó¦£ºCaCl2+Na2CO3=CaCO3¡ý+2NaCl

[ʵÑé̽¾¿2]

ʵÑé²½Öè

ʵÑéÏÖÏó

ʵÑé½áÂÛ

£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄ_______ÈÜÒº£¬²¢²»¶ÏÕñµ´¡£

ÓÐ__________Éú³É¡£

˵Ã÷Ô­ÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ¡£

£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº¡£

ÈÜÒº±äºìÉ«¡£

˵Ã÷Ô­ÈÜÒºÖÐÒ»¶¨ÓÐ________¡£

[ʵÑé½áÂÛ] ¸ÃÇâÑõ»¯ÄÆÈÜÒº____________£¨Ìî¡°²¿·Ö¡±»ò¡°È«²¿¡±£©±äÖÊ¡£

[·´Ë¼ÓëÆÀ¼Û]

£¨1£©ÇâÑõ»¯ÄÆÈÜҺ¶ÖÃÓÚ¿ÕÆøÖÐÈÝÒ×±äÖÊ£¬Çëд³öÏà¹Ø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________

£¨2£©ÔÚÉÏÊö[ʵÑé̽¾¿2]ÖУ¬Ð¡Ã÷Ìá³ö¿ÉÓÃÇâÑõ»¯¸ÆÈÜÒº´úÌæÂÈ»¯¸ÆÈÜÒº£¬ÄãÈÏΪ¸Ã·½°¸__________£¨Ìî¡°¿ÉÐС±»ò¡°²»¿ÉÐС±£©¡£

¡¾ÌâÄ¿¡¿£¨09·ðɽ£©ÒÑ֪ijºÏ½ð·ÛÄ©³ýÂÁÍ⣬»¹º¬ÓÐÌú¡¢Í­ÖеÄÒ»ÖÖ»òÁ½ÖÖ¡£Ä³ÐËȤС×éÔÚÀÏʦµÄÖ¸µ¼Ï£¬¶ÔºÏ½ð·ÛÄ©ÖÐÌú¡¢Í­µÄ´æÔÚÇé¿ö½øÐÐÁË̽¾¿¡£

¡¾²éÔÄ×ÊÁÏ¡¿ÂÁÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦·½³ÌʽΪ2Al+2NaOH+2H2O£½2NaAlO2+3H2¡ü£¨ ²úÎïNaAlO2ÈÜÓÚË®£©£»Fe¡¢Cu²»ÓëÇâÑõ»¯ÄÆÈÜÒº·´Ó¦¡£

¡¾²Â Ïë¡¿²ÂÏë1£º¸ÃºÏ½ð·ÛÄ©ÖгýÂÁÍ⣬»¹º¬ÓÐÌú¡£

²ÂÏë2£º¸ÃºÏ½ð·ÛÄ©ÖгýÂÁÍ⣬»¹º¬ÓÐ £¨ÌîÃû³Æ£©¡£

²ÂÏë3£º¸ÃºÏ½ð·ÛÄ©ÖгýÂÁÍ⣬»¹º¬ÓÐÌú¡¢Í­¡£

¡¾ÊµÑé̽¾¿¡¿ÏÂÁÐʵÑé½ö¹©Ñ¡ÔñµÄÊÔ¼Á£º10%ÑÎËá¡¢30%NaOHÈÜÒº¡£

ʵÑé·½°¸

ʵÏÖÏÖÏó

½áÂÛ

¢ÙÈ¡Ò»¶¨Á¿µÄºÏ½ð·ÛÄ©£¬¼Ó¹ýÁ¿µÄ

£¬³ä·Ö·´Ó¦ºó¹ýÂË£¬ÂËÔü±¸Óá£

·ÛÄ©²¿·ÖÈܽ⣬²¢ÓÐÆøÌå·Å³ö¡£

ºÏ½ðÖÐÒ»¶¨º¬ÓÐ ¡£

¢ÚÈ¡²½Öè¢ÙËùµÃÂËÔü£¬¼Ó¹ýÁ¿µÄ

£¬³ä·Ö·´Ó¦¡£

ÂËÔü²¿·ÖÈܽ⣬²¢ÓÐÆøÌå·Å³ö£¬ÈÜÒº³ÊdzÂÌÉ«¡£

ºÏ½ðÖÐÒ»¶¨º¬ÓÐ ¡£

¡¾Ì½¾¿½áÂÛ¡¿²ÂÏë3³ÉÁ¢¡£

¡¾·´Ë¼¡¿Ò»°ãÀ´Ëµ£¬»îÆýðÊôÄÜÓëÑÎËáµÈËá·´Ó¦£¬¶øÂÁÓëËá¡¢¼î¶¼ÄÜ·´Ó¦£¬ËµÃ÷ÂÁ¾ßÓÐÌØÊâµÄÐÔÖÊ¡£Ð´³öÂÁÓëÏ¡ÑÎËá·´Ó¦µÄ»¯Ñ§·½³Ìʽ ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø