ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ð´³öÏÂÁÐÐðÊöÉæ¼°µ½µÄ»¯Ñ§·½³Ìʽ¡£
£¨1£©ÇâÄÜÔ´ÒÔÈÈÖµ¸ß¡¢ÁãÎÛȾ¡¢ÖÆÇâÔÁϷḻ¶ø³ÉΪδÀ´×îÀíÏëȼÁÏ¡£
___________________________________ ¡£
£¨2£©ºìÁ×ȼÉÕʱÒòÆä°×ÑÌŨºñ£¬¾üÊÂÉϳ£½«ÆäÖƳÉÑÌÄ»µ¯¡£
___________________________________ ¡£
£¨3£©¹¤ÒµÉϳ£²ÉÓÃìÑÉÕʯ»ÒʯµÄ·½·¨ÖÆÈ¡Éúʯ»Ò¡£
___________________________________ ¡£
£¨4£©Ä³Ð©¹¤³§·ÏË®Öк¬ÓÐÁòËᣬ´¦Àíʱ¿ÉͨÈëÊÊÁ¿°±Ë®£¬·´Ó¦ºó»¹Äܵõ½µª·ÊÁòËá李£
___________________________________ ¡£
£¨5£©ÓÉÓÚijЩÈÜÒºÒ×Óë¿ÕÆøÖÐһЩÆøÌå·´Ó¦£¬¹ÊÓýºÍ·µÎ¹ÜÎüÈ¡ÈÜҺʱ£¬ÒªÔÚÒºÃæÉÏÏȼ·³ö½ºÍ·ÖпÕÆø£¬ÔÙÉìÈëÒºÌåÖÐÎüÈ¡£¬±ÈÈçÓýºÍ·µÎ¹ÜÎüÈ¡ÇâÑõ»¯ÄÆÈÜÒº¡£
___________________________________ ¡£
£¨6£©Ê³ÑγýÁËÄÜ×÷µ÷ζƷÍ⣬ÔÚÂȼҵÉÏͨ¹ýµç½âʳÑÎË®£¬¿ÉµÃµ½ÉռÂÈÆø¡¢ÇâÆøµÈÖØÒªµÄ¹¤ÒµÔÁÏ¡£
___________________________________ ¡£
¡¾´ð°¸¡¿ ÂÔ ÂÔ ÂÔ ÂÔ ÂÔ ÂÔ
¡¾½âÎö¡¿Êéд»¯Ñ§·½³ÌʽµÄÒÀ¾ÝÊÇÖÊÁ¿Êغ㶨ÂÉ£¬Êéд²½ÖèÊÇ£ºÒ»Ð´¶þÅäÈý±êËIJ顣£¨1£©ÇâÆøȼÉÕÉú³ÉË®£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2H2+O2µãȼ2H2O£»£¨2£©ºìÁ×ȼÉÕÉú³ÉÎåÑõ»¯¶þÁ×£º4P+5O2µãȼ2P2O5£»£¨3£©¸ßÎÂìÑÉÕʯ»ÒʯÉú³ÉÑõ»¯¸ÆºÍ¶þÑõ»¯Ì¼£ºCaCO3¸ßÎÂCaO+CO2¡ü£»£¨4£©ÁòËáÓ백ˮ·´Ó¦Éú³ÉÁòËá泥ºH2SO4+2NH3©qH2O==(NH4)2SO4+2H2O£»£¨5£©ÇâÑõ»¯ÄÆÒ×Óë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄƺÍË®£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2NaOH+CO2===Na2CO3+H2O£»£¨6£©µç½âʳÑÎË®£¬¿ÉµÃµ½ÉռÂÈÆø¡¢ÇâÆø£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾΪ£º2NaCl+2H2O==2NaOH+Cl2¡ü+H2¡ü¡£
![](http://thumb2018.1010pic.com/images/loading.gif)
¡¾ÌâÄ¿¡¿ÏÂÁÐʵÑéÖл¯Ñ§·½³ÌʽºÍ²¿·ÖÏÖÏó¶¼ÕýÈ·µÄÊÇ£¨ £©
Ñ¡Ïî | ʵÑé | »¯Ñ§·½³Ìʽ | ÏÖÏó |
A | ½«Ï¡ÑÎËá¼ÓÈëÌú·ÛÖÐ | 2Fe + 6HCl = 2FeCl3 + 3H2¡ü | ÈÜÒºÓÐÎÞÉ«±ä³É»ÆÉ« |
B | CO¸ßλ¹ÔÑõ»¯Ìú | 3CO + Fe2O3 £½ 2Fe + 3CO2¡ü | ºìÉ«¹ÌÌå±ä³ÉºÚÉ«¹ÌÌå |
C | Ìú¶¤ÖмÓÁòËáÍÈÜÒº | Fe + CuSO4 £½ Cu + FeSO4 | ÈÜÒºÓÉÀ¶É«±ä³ÉdzÂÌÉ« |
D | ³ýÈ¥NaClÖеÄNa2SO4 | Na2SO4+ Ca(OH)2£½CaSO4¡ý+ 2NaOH | Óа×É«³Áµí²úÉú |
A. A B. B C. C D. D
¡¾ÌâÄ¿¡¿»¯Ñ§¿Îºó£¬»¯Ñ§ÐËȤС×éµÄͬѧÔÚÕûÀíʵÑé×Àʱ£¬·¢ÏÖÓÐһƿÇâÑõ»¯ÄÆÈÜҺûÓÐÈûÏðƤÈû£¬Õ÷µÃÀÏʦͬÒâºó£¬¿ªÕ¹ÁËÒÔÏÂ̽¾¿£º
[Ìá³öÎÊÌâ1] ¸ÃÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊÁËÄØ£¿
[ʵÑé̽¾¿1]
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμÓ___________£¬²¢²»¶ÏÕñµ´¡£ | ÓÐÆøÅݲúÉú¡£ | ÇâÑõ»¯ÄÆÈÜÒºÒ»¶¨±äÖÊÁË¡£ |
[Ìá³öÎÊÌâ2] ¸ÃÇâÑõ»¯ÄÆÈÜÒºÊÇÈ«²¿±äÖÊ»¹ÊDz¿·Ö±äÖÊÄØ£¿
[²ÂÏëÓë¼ÙÉè]²ÂÏ룺1£ºÇâÑõ»¯ÄÆÈÜÒº²¿·Ö±äÖÊ¡£ ²ÂÏë2£ºÇâÑõ»¯ÄÆÈÜҺȫ²¿±äÖÊ¡£
[²éÔÄ×ÊÁÏ] £¨1£© ÂÈ»¯¸ÆÈÜÒº³ÊÖÐÐÔ¡£
£¨2£© ÂÈ»¯¸ÆÈÜÒºÄÜÓë̼ËáÄÆÈÜÒº·´Ó¦£ºCaCl2+Na2CO3=CaCO3¡ý+2NaCl
[ʵÑé̽¾¿2]
ʵÑé²½Öè | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
£¨1£©È¡ÉÙÁ¿¸ÃÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏòÈÜÒºÖеμӹýÁ¿µÄ_______ÈÜÒº£¬²¢²»¶ÏÕñµ´¡£ | ÓÐ__________Éú³É¡£ | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ̼ËáÄÆ¡£ |
£¨2£©È¡²½Ö裨1£©ÊÔ¹ÜÖеÄÉÙÁ¿ÉϲãÇåÒº£¬µÎ¼Ó·Ó̪ÈÜÒº¡£ | ÈÜÒº±äºìÉ«¡£ | ˵Ã÷ÔÈÜÒºÖÐÒ»¶¨ÓÐ________¡£ |
[ʵÑé½áÂÛ] ¸ÃÇâÑõ»¯ÄÆÈÜÒº____________£¨Ìî¡°²¿·Ö¡±»ò¡°È«²¿¡±£©±äÖÊ¡£
[·´Ë¼ÓëÆÀ¼Û]
£¨1£©ÇâÑõ»¯ÄÆÈÜҺ¶ÖÃÓÚ¿ÕÆøÖÐÈÝÒ×±äÖÊ£¬Çëд³öÏà¹Ø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º_________
£¨2£©ÔÚÉÏÊö[ʵÑé̽¾¿2]ÖУ¬Ð¡Ã÷Ìá³ö¿ÉÓÃÇâÑõ»¯¸ÆÈÜÒº´úÌæÂÈ»¯¸ÆÈÜÒº£¬ÄãÈÏΪ¸Ã·½°¸__________£¨Ìî¡°¿ÉÐС±»ò¡°²»¿ÉÐС±£©¡£
¡¾ÌâÄ¿¡¿ÓÐÒ»°×É«¹ÌÌ壬ֻ֪ËüÊÇCaCO3¡¢ÎÞË®CuSO4¡¢Ca(OH)2¡¢Na2CO3¡¢NaOHÖеÄÒ»ÖÖ»ò¼¸ÖÖ¡£Ä³ÐËȤС×éͬѧΪ̽¾¿°×É«¹ÌÌåµÄ³É·Ý£¬ÊµÑéÈçÏ£ºÈ¡Ñù£¬¼ÓÊÊÁ¿Ë®³ä·Ö½Á°è£¬¹ýÂË£¬µÃ°×É«³ÁµíºÍÎÞÉ«ÈÜÒº¡£¾Ý´ËÅжϣ¬¸Ã°×É«¹ÌÌåÖÐÒ»¶¨Ã»ÓÐ______________¡£
¸ÃС×éͬѧ¶ÔËùµÃ°×É«³Áµí¼ÌÐø½øÐÐʵÑé̽¾¿£º
¡¾Ìá³öÎÊÌâ¡¿ËùµÃ°×É«³ÁµíµÄ³É·ÝÊÇʲô£¿
¡¾²ÂÏëÓë¼ÙÉè¡¿ÇëÄã°ïÖúÍê³É²ÂÏëÈý¡£
²ÂÏëÒ»£ºCa(OH)2 ²ÂÏë¶þ£ºCaCO3 ²ÂÏëÈý£º________________________
¡¾ÊµÑéÑéÖ¤¡¿ÇëÄãÍê³ÉÌî¿Õ¡£
ʵÑé²Ù×÷ | ʵÑéÏÖÏó | ʵÑé½áÂÛ |
È¡°×É«³ÁµíÉÙÁ¿£¬¼ÓÈë×ãÁ¿ ___________________ | ___________________ | ²ÂÏëÒ»³ÉÁ¢¡£ ´Ó¶øÈ·¶¨Á˸ð×É«¹ÌÌåÖÐÒ»¶¨ÓÐCa(OH)2 |
¡¾·´Ë¼ÓëÍØÕ¹¡¿
£¨1£©ËùµÃ°×É«³ÁµíÊÇCa(OH)2 µÄÔÒò¿ÉÄÜÊÇ______________________________¡£
£¨2£©·ÖÎöµÃ³ö¸Ã°×É«¹ÌÌåÖÐûÓÐNa2CO3 £¬ÀíÓÉÊÇ______________________¡£
£¨3£©·ÖÎöµÃ³ö¸Ã°×É«¹ÌÌåÖпÉÄÜÓÐNaOH£¬ÇëÄãÉè¼ÆÒ»¸öʵÑé·½°¸£¬Ö¤Ã÷ËüÊÇ·ñ´æÔÚ£¿
______________________________________________________¡£