ÌâÄ¿ÄÚÈÝ
»·¾³ÎÊÌâÊÇ2012Äê¡°Á½»áÉÏ¡±µÄÈÈÃÅ»°ÌâÖ®Ò»¡££¨1£©È¼Æø°²È«ÊǼÒÍ¥Éú»îÖеÄÍ·µÈ´óÊ¡£ÎªÁË·ÀֹȼÆøй©£¬³£ÔÚȼÆøÖмÓÈëÉÙÁ¿ÓÐÌØÊâÆøζµÄÒÒÁò´¼£¨C2H5SH£©¡£Ò»µ©È¼Æøй©¼´¿ÉÎŵ½Æø棬´Ó΢¹ÛµÄ½Ç¶È·ÖÎöÆäÔÒòÊÇ £»ÒÒÁò´¼³ä·ÖȼÉÕʱÉú³É¶þÑõ»¯Ì¼¡¢¶þÑõ»¯ÁòºÍË®£¬ÒÒÁò´¼È¼ÉյĻ¯Ñ§·½³ÌʽΪ £»
£¨2£©º¬ÁòúȼÉÕºó£¬Åŷŵ½¿ÕÆøÖеÄÓж¾ÆøÌåÖ÷ÒªÊÇSO2£¬ËüÓöµ½ÓêË®ºó¿ÉÐγÉËáÓê½µÂäµ½µØÃæÔì³É¼«´óΣº¦¡£ÎªÁ˼õÉÙ»·¾³ÎÛȾ£¬¶Ô¹¤³§ÅŷŵķÏÆøÖеÄSO2¿ÉÓÃ×ãÁ¿ÉÕ¼îÈÜÒºÎüÊÕ´¦Àí£¬Æ仯ѧ·´Ó¦·½³ÌʽΪ ¡£
£¨2£©º¬ÁòúȼÉÕºó£¬Åŷŵ½¿ÕÆøÖеÄÓж¾ÆøÌåÖ÷ÒªÊÇSO2£¬ËüÓöµ½ÓêË®ºó¿ÉÐγÉËáÓê½µÂäµ½µØÃæÔì³É¼«´óΣº¦¡£ÎªÁ˼õÉÙ»·¾³ÎÛȾ£¬¶Ô¹¤³§ÅŷŵķÏÆøÖеÄSO2¿ÉÓÃ×ãÁ¿ÉÕ¼îÈÜÒºÎüÊÕ´¦Àí£¬Æ仯ѧ·´Ó¦·½³ÌʽΪ ¡£
£¨1£©·Ö×ÓÔÚ²»¶ÏÔ˶¯ 2C2H5SH+9O24CO2+6H2O+2SO2
£¨2£©SO2+2NaOH=Na2SO3+ H2O
£¨2£©SO2+2NaOH=Na2SO3+ H2O
£¨1£©Ð¹Â©µÄÒÒÁò´¼·Ö×Ó²»¶ÏÔ˶¯¶øÔÚ¿ÕÆøÀ©É¢£»ÒÒÁò´¼³ä·ÖȼÉÕ¼´ÒÒÁò´¼ÓëÑõÆøÔÚµãȼµÄÌõ¼þÏ·¢Éú·´Ó¦£¬²úÉú¶þÑõ»¯Ì¼¡¢¶þÑõ»¯ÁòºÍË®£»
£¨2£©ÉÕ¼îÈÜÒºÎüÊÕÓж¾ÆøÌåSO2£¬Éú³ÉÑÇÁòËáÄÆNa2SO3ºÍË®£¬¼õÉÙ»·¾³ÎÛȾ
£¨2£©ÉÕ¼îÈÜÒºÎüÊÕÓж¾ÆøÌåSO2£¬Éú³ÉÑÇÁòËáÄÆNa2SO3ºÍË®£¬¼õÉÙ»·¾³ÎÛȾ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿