ÌâÄ¿ÄÚÈÝ
̼ԪËØÐγɵÄÎïÖʵÄÖÖÀàÊÇ×î¶àµÄ£¬¹Ê¶Ô̼¼°Æ仯ºÏÎïµÄÑо¿ÊǺÜÓмÛÖµµÄ¡£
(1)̼Ô×ӵĽṹʾÒâͼΪ£¬Ì¼Ô×ÓµÄ×îÍâ²ãµç×ÓÊýΪ______£¬Ð´³öÒ»ÖÖÄãÖªµÀµÄ̼µÄµ¥ÖʵÄÃû³Æ________¡£
(2)¾Æ¾«(C2H5OH)ÊÇÒ»ÖÖº¬Ì¼ÔªËصĻ¯ºÏÎ½«100mL¾Æ¾«ºÍ100mLË®»ìºÏʱ£¬ËùµÃÌå»ýСÓÚ200mL£¬ÔÒòÊÇ________________¡£
(3)ÔÚ̽¾¿¶þÑõ»¯Ì¼µÄÐÔÖÊʱ£¬ÎÒÃÇÔøÓÃËĶäʯÈïȾ³É×ÏÉ«µÄ¸ÉÔïС»¨£¬½øÐÐÁËÏÂͼµÄʵÑ飬ÈÃÎÒÃÇÌåÑéÁ˶Աȡ¢·ÖÎö¡¢¹éÄÉ¡¢¸ÅÀ¨µÈ¿Æѧ·½·¨ºÍÊֶεÄÔËÓá£
(1)̼Ô×ӵĽṹʾÒâͼΪ£¬Ì¼Ô×ÓµÄ×îÍâ²ãµç×ÓÊýΪ______£¬Ð´³öÒ»ÖÖÄãÖªµÀµÄ̼µÄµ¥ÖʵÄÃû³Æ________¡£
(2)¾Æ¾«(C2H5OH)ÊÇÒ»ÖÖº¬Ì¼ÔªËصĻ¯ºÏÎ½«100mL¾Æ¾«ºÍ100mLË®»ìºÏʱ£¬ËùµÃÌå»ýСÓÚ200mL£¬ÔÒòÊÇ________________¡£
(3)ÔÚ̽¾¿¶þÑõ»¯Ì¼µÄÐÔÖÊʱ£¬ÎÒÃÇÔøÓÃËĶäʯÈïȾ³É×ÏÉ«µÄ¸ÉÔïС»¨£¬½øÐÐÁËÏÂͼµÄʵÑ飬ÈÃÎÒÃÇÌåÑéÁ˶Աȡ¢·ÖÎö¡¢¹éÄÉ¡¢¸ÅÀ¨µÈ¿Æѧ·½·¨ºÍÊֶεÄÔËÓá£
±¾ÊµÑéµÃ³öµÄ½áÂÛÊÇ________¡£
(4)COÔÚÒ±½ð¹¤ÒµÖÐÓÐ×ÅÖØÒªµÄ×÷Óá£ÈôCOÖлìÓÐÉÙÁ¿µÄCO2£¬Òª³ýÈ¥ÉÙÁ¿CO2£¬ÄãµÄ·½·¨ÊÇ______________£¨Óû¯Ñ§·½³Ìʽ±íʾ£©¡£
(4)COÔÚÒ±½ð¹¤ÒµÖÐÓÐ×ÅÖØÒªµÄ×÷Óá£ÈôCOÖлìÓÐÉÙÁ¿µÄCO2£¬Òª³ýÈ¥ÉÙÁ¿CO2£¬ÄãµÄ·½·¨ÊÇ______________£¨Óû¯Ñ§·½³Ìʽ±íʾ£©¡£
(1)4£»½ð¸Õʯ£¨»òʯī£©
(2)·Ö×Ó¼äÓмä¸ô
(3)¶þÑõ»¯Ì¼ÄܺÍË®·´Ó¦Éú³É̼Ëá
(4)CO2+ 2NaOH==Na2CO3+H2O
(2)·Ö×Ó¼äÓмä¸ô
(3)¶þÑõ»¯Ì¼ÄܺÍË®·´Ó¦Éú³É̼Ëá
(4)CO2+ 2NaOH==Na2CO3+H2O
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿