ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Îª²â¶¨Ä³µª·ÊÖÐÁòËá淋Ĵ¿¶È£¨¼°ÖÊÁ¿·ÖÊý£©ÊÇ·ñÓëÏÂͼ±êÇ©Ïà·ûºÏ£¬Ð¡ÁÖÈ¡Ò»¶¨Á¿¸Ãµª·ÊÑùÆ·ÓÚÉÕ±ÖÐÅä³ÉÈÜÒºÓë×ãÁ¿ÂÈ»¯±µÈÜÒº·´Ó¦£¬¼Ç¼ÓйØÊý¾ÝÈçÏÂ±í£º
¡¾·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£¨NH4£©2SO4+BaCl2 =BaSO4¡ý+2NH4Cl£¬ÆäËû³É·ÖÄÜÈÜÓÚË®µ«²»²Î¼Ó·´Ó¦¡¿
£¨1£©·´Ó¦¹²Éú³ÉBaSO4µÄÖÊÁ¿Îª_____________g¡£
£¨2£©ÈôËùÈ¡µª·ÊÑùÆ·µÄÖÊÁ¿Îª15g£¬ÊÔͨ¹ý¼ÆËãÈ·¶¨¸Ãµª·ÊÖÐÁòËá淋Ĵ¿¶ÈÊÇ·ñÓë±êÇ©Ïà·û¡££¨Çëд³ö¼ÆËã¹ý³Ì£©
£¨3£©·´Ó¦Ç°ºó£¬ÈÜÒºÖÐÁòÔªËصÄÖÊÁ¿ÊÇ_______________£¨Ìî¡°²»±ä¡±¡¢¡°Ôö´ó¡±»ò¡°¼õС¡±£©¡£
¡¾´ð°¸¡¿£¨1£©23.3
£¨2£©
£¨3£©¼õС
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©¸ù¾ÝÖÊÁ¿Êغ㶨ÂÉ¿ÉÖª·´Ó¦Ç°ºóÈÜÒºµÄÖÊÁ¿²îֵΪÉú³ÉµÄ²»ÈÜÎïÁòËá±µ¡£ËùÒÔ·´Ó¦¹²Éú³ÉBaSO4µÄÖÊÁ¿Îª45g+55g-76.7g=23.3g¡£
£¨2£©¸ù¾ÝÌâÒâ¿ÉÖª£ºÒÑÖªÁ¿ÎªÁòËá±µµÄÖÊÁ¿£¬Î´ÖªÁ¿ÎªÁòËá淋ÄÖÊÁ¿¡£¿Éͨ¹ý»¯Ñ§·½³ÌʽÖжþÕߵĹØϵ½øÐÐÇó½â¡£¾ßÌå¹ý³ÌÈçÏ£º
£¨3£©ÓÉÓÚÁòÔªËØת»¯Îª³ÁµíBaSO4ÖУ¬Òò´ËÈÜÒºÖеÄÁòÔªËØÖÊÁ¿¼õС¡£