ÌâÄ¿ÄÚÈÝ

£¨2011Äê½­ËÕÎÞÎý£¬29Ì⣩ÓÒͼΪÈÕ±¾¸£µººËµçվй©Ê¹Êͼ½â¡£
£¨1£©µØÕð·¢ÉúºóÒò¶Ïµçº£Ë®Àäȴϵͳֹͣ¹¤×÷£¬·´Ó¦¶Ñζȹý¸ßʹˮÕôÆøÓë¸Ö¿Ç·´Ó¦Éú³ÉËÄÑõ»¯ÈýÌúºÍÇâÆø£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                            ¡£
£¨2£©¸ßÎÂÌõ¼þÏÂÇâÆøºÍ¿ÕÆø»ìºÏ±¬Õ¨£¬ÕâÒ»±¬Õ¨¹ý³ÌÊôÓÚ    £¨Ìî¡°ÎïÀí¡±»ò¡°»¯Ñ§¡±£©±ä»¯¡£±¬Õ¨ÒýÆðºËй©£¬Ôì³Éï¤137É¢Òݵ½¿ÕÆøÖС£ï¤µÄºËµçºÉÊýÊÇ55£¬Ôò蘆ÄÖÊ×ÓÊýÊÇ     ¡£
£¨3£©ÏÂÁÐ˵·¨´íÎóµÄÊÇ      ¡£
A£®¿Æѧ¡¢°²È«µØÀûÓúËÄÜ
B£®³ä·ÖÀûÓ÷çÄÜ¡¢µØÈÈÄܺÍÌ«ÑôÄÜ
C£®¾¡¿ÉÄܶàʹÓÃʯÓÍ¡¢ÃºµÈ»¯Ê¯ÄÜÔ´
D£®Ñ°ÕÒ¿ÉÑ­»·ÀûÓõÄÉúÎïÄÜÔ´
£¨1£©  4H2O + 3Fe 4H2 + 3Fe3O4                       
£¨2£© »¯Ñ§   55  £¨3£©      BD
(1)·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ4H2O+3Fe4H2+3Fe3O4£¬(2)±¬Õ¨Éæ¼°µ½ÇâÆøµÄȼÉÕ£¬ÊôÓÚ»¯Ñ§±ä»¯£»ºËµçºÉÊý¼´ÖÊ×ÓÊý£¬ºËµçºÉÊýΪ55£¬ÖÊ×ÓÊýΪ55¡£(3)»¯Ê¯ÄÜÔ´ÊDz»¿ÉÔÙÉú×ÊÔ´£¬ÒªºÏÀíµÄʹÓ㬹ÊC²»ÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
(6·Ö)ÈËÀàÉú´æÀë²»¿ªÄÜÔ´¡£
(1)±±¾©¼ÒÓÃȼÁϵĸüйý³ÌÈçÏ£º

¢Ùú¡¢Òº»¯Ê¯ÓÍÆø¡¢¹ÜµÀúÆø¾ùÊôÓÚ        (Ìî¡°»ìºÏÎ»ò¡°´¿¾»Î)¡£
¢Ú¹ÜµÀúÆøµÄÖ÷Òª³É·ÖÊÇÒ»Ñõ»¯Ì¼¡£Ò»Ñõ»¯Ì¼ÔÚ¿ÕÆøÖÐȼÉյĻ¯Ñ§·½³ÌʽÊÇ_____¡£
¢ÛÏÂÁÐÓйؼÒÓÃȼÁϸüеÄÀíÓÉ£¬ÕýÈ·µÄÊÇ_____(Ìî×ÖĸÐòºÅ)¡£
A£®ÌìÈ»ÆøÊô¿ÉÔÙÉúÄÜÔ´
B£®ÆøÌåȼÁϱȹÌÌåȼÁÏÀûÓÃÂʸü¸ß
C£®¼õÉÙȼÉÕ¹ý³ÌÖвúÉúµÄÎÛȾÎï
D£®ÆøÌåȼÁϱãÓڹܵÀÊäËÍ
¢ÜΪÁË°²È«Æð¼û£¬×îºÃÔÚ³ø·¿°²×°±¨¾¯Æ÷£¬Èç¹û±¨¾¯Æ÷ÏÔʾÓÐÒº»¯Æøй©£¬Ó¦Á¢¼´²ÉÈ¡µÄ´ëÊ©ÊÇ                ¡££¨»Ø´ðÒ»ÖÁÁ½µã¼´¿É£©
(2)ÒÒ´¼(C2H5OH)ÊÇÒ»ÖÖÂÌɫȼÁÏ¡£½«Ò»¶¨Á¿µÄÒÒ´¼ºÍÑõÆøÖÃÓÚÒ»¸ö·â±ÕµÄÈÝÆ÷ÖÐÒýȼ£¬²âµÃ·´Ó¦Ç°ºó¸÷ÎïÖʵÄÖÊÁ¿ÈçÏÂ±í£º
ÎïÖÊ
ÒÒ´¼
ÑõÆø
Ë®
¶þÑõ»¯Ì¼
X
·´Ó¦Ç°ÖÊÁ¿/g
4.6
8
0
0
0
·´Ó¦ºóÖÊÁ¿/g
0
0
5.4
4.4
a
ÏÂÁÐÅжÏÕýÈ·µÄÊÇ
A£®±íÖÐaµÄֵΪ2.8         B£®X¿ÉÄÜÊÇÕâ¸ö·´Ó¦ÖеĴ߻¯¼Á
C£®X¿ÉÄܺ¬ÓÐÇâÔªËØ         D£®ÈôÆðʼʱÑõÆøµÄÖÊÁ¿ÊÇ9.6g£¬ÔòÎÞXÉú³É

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø