ÌâÄ¿ÄÚÈÝ
Сº£Í¬Ñ§ÔÚʵÑéÊÒÀï·¢ÏÖһƿƿ¸Çû¸ÇºÃµÄÇâÑõ»¯ÄÆÈÜÒº£®£¨1£©ËûºÍѧϰС×éµÄͬѧһÆð¾ö¶¨¶ÔÕâÆ¿ÈÜÒºÊÇ·ñ±äÖʽøÐÐ̽¾¿£¬ÇëÄã°ïËûÃÇÍê³ÉʵÑ鱨¸æ£®
Ìá³öÎÊÌâ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£¿ |
²ÂÏëÓë¼ÙÉè | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® ±äÖÊÀíÓÉÊÇ£º______£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£® |
ʵÑé̽¾¿ | ²Ù×÷²½Ö裺ȡ³öÉÙÁ¿¸ÃÈÜÒºÓÚÒ»Ö§ÊÔ¹ÜÖУ¬ÔÙÍùÊÔ¹ÜÖеμÓ______£® ʵÑéÏÖÏ󣺹۲쵽ÓÐ______£® ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º______£® |
½áÂÛ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® |
·´Ë¼ | ÇâÑõ»¯ÄƱØÐë______±£´æ£® |
¡¾´ð°¸¡¿·ÖÎö£º£¨1£©ÇâÑõ»¯ÄÆÄÜÓë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦£¬·½³ÌʽΪ£ºCO2 +2NaOH=Na2CO3 +H2O£¬ÓÉ´Ë¿ÉÖªÇâÑõ»¯ÄƱäÖʺó»áÉú³É̼ËáÄÆ£¬Ö»Òª¼ìÑéÊÇ·ñº¬ÓÐCO32-£¬¾ÍÄÜÅжÏÊÇ·ñ±äÖÊÁË£»
£¨2£©¸ù¾Ý̼ËáÄƺÍÇâÑõ»¯ÄƵÄÐÔÖÊ·ÖÎö£®
½â´ð£º½â£º£¨1£©ÓÉÓÚÇâÑõ»¯ÄÆÄÜÓë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³ÉÁË̼ËáÄÆ£¬Ì¼ËáÄÆÄÜÓëÏ¡ÑÎËá·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬ËùÒÔ£¬Ì½¾¿ÊµÑéÈçÏ£º
£¨2£©ÓÉÓÚ̼ËáÄÆÄÜÓëÇâÑõ»¯¸Æ·´Ó¦Éú³É̼Ëá¸ÆºÍÇâÑõ»¯ÄÆ£®ËùÒÔ£¬Ê¹Ëü±ä³É´¿¾»µÄÇâÑõ»¯ÄÆÈÜÒº£¬Ð¡º£ËûÃÇӦѡÓõÄÊÔ¼ÁÊÇʯ»ÒË®£¬·´Ó¦µÄ·½³ÌʽÊÇ£ºNa2CO3+Ca£¨OH£©2=2NaOH+CaCO3¡ý£®
¹Ê´ðΪ£º£¨1£©¼ûÉÏ±í£®£¨2£©Ê¯»ÒË®£¬Na2CO3+Ca£¨OH£©2=2NaOH+CaCO3¡ý£®
µãÆÀ£º¸ÃÌâ×÷Ϊһ¸öʵÑéÉè¼ÆÌ⣬Ö÷Òª¿¼²éÁ˼îµÄÓйØÐÔÖÊ£¬Ì¼Ëá¸ùÀë×ӵļìÑéµÈ£¬Öص㿼ÂÇ̼Ëá¸ùÀë×ÓºÍÇâÑõ¸ùÀë×ӵļìÑ飬´ð°¸¾ßÓпª·ÅÐÔ£®
£¨2£©¸ù¾Ý̼ËáÄƺÍÇâÑõ»¯ÄƵÄÐÔÖÊ·ÖÎö£®
½â´ð£º½â£º£¨1£©ÓÉÓÚÇâÑõ»¯ÄÆÄÜÓë¿ÕÆøÖеĶþÑõ»¯Ì¼·´Ó¦Éú³ÉÁË̼ËáÄÆ£¬Ì¼ËáÄÆÄÜÓëÏ¡ÑÎËá·´Ó¦Éú³É¶þÑõ»¯Ì¼ÆøÌ壬ËùÒÔ£¬Ì½¾¿ÊµÑéÈçÏ£º
Ìá³öÎÊÌâ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£¿ |
²ÂÏëÓë¼ÙÉè | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® ±äÖÊÀíÓÉÊÇ£ºÇâÑõ»¯ÄÆÔÚ¿ÕÆøÖÐÄÜÓë¶þÑõ»¯Ì¼·´Ó¦Éú³É̼ËáÄƺÍË®£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2NaOH+CO2=Na2CO3+H2O£® |
ʵÑé̽¾¿ | ²Ù×÷²½Ö裺ȡ³öÉÙÁ¿¸ÃÈÜÒºÓÚÒ»Ö§ÊÔ¹ÜÖУ¬ÔÙÍùÊÔ¹ÜÖеμÓÏ¡ÑÎËᣮ ʵÑéÏÖÏ󣺹۲쵽ÓÐÆøÅݲúÉú£® ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºNa2CO3+2HCl=2NaCl+H2O+CO2¡ü£® |
½áÂÛ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® |
·´Ë¼ | ÇâÑõ»¯ÄƱØÐëÃÜ·â±£´æ£® |
¹Ê´ðΪ£º£¨1£©¼ûÉÏ±í£®£¨2£©Ê¯»ÒË®£¬Na2CO3+Ca£¨OH£©2=2NaOH+CaCO3¡ý£®
µãÆÀ£º¸ÃÌâ×÷Ϊһ¸öʵÑéÉè¼ÆÌ⣬Ö÷Òª¿¼²éÁ˼îµÄÓйØÐÔÖÊ£¬Ì¼Ëá¸ùÀë×ӵļìÑéµÈ£¬Öص㿼ÂÇ̼Ëá¸ùÀë×ÓºÍÇâÑõ¸ùÀë×ӵļìÑ飬´ð°¸¾ßÓпª·ÅÐÔ£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Сº£Í¬Ñ§ÔÚʵÑéÊÒÀï·¢ÏÖһƿƿ¸Çû¸ÇºÃµÄÇâÑõ»¯ÄÆÈÜÒº£®
£¨1£©ËûºÍѧϰС×éµÄͬѧһÆð¾ö¶¨¶ÔÕâÆ¿ÈÜÒºÊÇ·ñ±äÖʽøÐÐ̽¾¿£¬ÇëÄã°ïËûÃÇÍê³ÉʵÑ鱨¸æ£®
Ìá³öÎÊÌâ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£¿ |
²ÂÏëÓë¼ÙÉè | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® ±äÖÊÀíÓÉÊÇ£º________£¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º________£® |
ʵÑé̽¾¿ | ²Ù×÷²½Ö裺ȡ³öÉÙÁ¿¸ÃÈÜÒºÓÚÒ»Ö§ÊÔ¹ÜÖУ¬ÔÙÍùÊÔ¹ÜÖеμÓ________£® ʵÑéÏÖÏ󣺹۲쵽ÓÐ________£® ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º________£® |
½áÂÛ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ£® |
·´Ë¼ | ÇâÑõ»¯ÄƱØÐë________±£´æ£® |
Сº£Í¬Ñ§ÔÚʵÑéÊÒÀï·¢ÏÖһƿƿ¸Çû¸ÇºÃµÄÇâÑõ»¯ÄÆÈÜÒº¡£
£¨1£©ËûºÍѧϰС×éµÄͬѧһÆð¾ö¶¨¶ÔÕâÆ¿ÈÜÒºÊÇ·ñ±äÖʽøÐÐ̽¾¿£¬ÇëÄã°ïËûÃÇÍê³ÉʵÑ鱨¸æ¡£
Ìá³öÎÊÌâ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÊÇ·ñ±äÖÊ£¿ |
²ÂÏëÓë¼ÙÉè | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ¡£ ±äÖÊÀíÓÉÊÇ£º £¬Óйط´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º ¡£ |
ʵÑé̽¾¿ | ²Ù×÷²½Ö裺ȡ³öÉÙÁ¿¸ÃÈÜÒºÓÚÒ»Ö§ÊÔ¹ÜÖУ¬ÔÙÍùÊÔ¹ÜÖÐµÎ¼Ó ¡£ ʵÑéÏÖÏ󣺹۲쵽ÓÐ ¡£ ·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º ¡£ |
½áÂÛ | ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÒѾ±äÖÊ¡£ |
·´Ë¼ | ÇâÑõ»¯ÄƱØÐë ±£´æ¡£ |
£¨2£©ÈôÒª³ýÈ¥ÕâÆ¿ÇâÑõ»¯ÄÆÈÜÒºÖеÄÔÓÖÊ£¬Ê¹Ëü±ä³É´¿¾»µÄÇâÑõ»¯ÄÆÈÜÒº£¬Ð¡º£ËûÃÇӦѡÓõÄÊÔ¼ÁÊÇ £¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º