题目内容

14.单位换算:
(1)0.5°=30′=1800″;
(2)($\frac{1}{60}$)°=1′=60″;
(3)32.81°=32°48′36″;
(4)45°12′36″=45.21°.

分析 (1)根据1°=60′,1′=60″求出即可;
(2)根据1°=60′,1′=60″求出即可;
(3)先把0.81°化成分,再把0.6′化成秒即可;
(4)先把36″化成分,再把12.6′化成秒即可.

解答 解:(1)0.5°=(0.5×60)′=30′,30′=(30×60)″=1800″,
故答案为:30,1800;

(2)($\frac{1}{60}$)°=($\frac{1}{60}$×60)′=1′,1′=60″,
故答案为:1,60;

(3)∵0.81°=(0.81×60)′=48.6′,0.6′=(0.6×60)″=36″,
∴32.81°=32°48′36″,
故答案为:32,48,36;

(4)∵36″=(36÷60)′=0.6′,
12.6′=(12.6÷60)°=0.21°,
∴45°12′36″=45.21°,
故答案为:45.21.

点评 本题考查了度、分、秒之间的换算的应用,能正确进行度、分、秒之间的换算是解此题的关键,注意:1°=60′,1′=60″.

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