题目内容
计算.
(1)(7y+3x+z2)-(5y+3x-z2)
(2)(-a+
b)(-a-
b)-(3a-2b)(3a+2b)
(1)(7y+3x+z2)-(5y+3x-z2)
(2)(-a+
| 1 |
| 2 |
| 1 |
| 2 |
分析:(1)先去括号,再合并同类项即可解答.
(2)先将两个乘法算式利用平方差公式计算,在合并同类项即可解答.
(2)先将两个乘法算式利用平方差公式计算,在合并同类项即可解答.
解答:解:(1)(7y+3x+z2)-(5y+3x-z2)
=7y+3x+z2-5y-3x+z2
=2y+2z2
(2)(-a+
b)(-a-
b)-(3a-2b)(3a+2b)
=a2-
b2-9a2+4b2
=-8a2+
b2.
=7y+3x+z2-5y-3x+z2
=2y+2z2
(2)(-a+
| 1 |
| 2 |
| 1 |
| 2 |
=a2-
| 1 |
| 4 |
=-8a2+
| 15 |
| 4 |
点评:本题主要考查平方差公式与合并同类项,熟练掌握上述知识点是解答本题的关键.
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