题目内容
先化简,再求值.| 1 |
| x+1 |
| x+3 |
| x2-1 |
| x2-2x+1 |
| x2+4x+3 |
| 2 |
分析:先对x2-1,x2-2x+1,x2+4x+3分解因式后进行乘法运算,再通分进行化简求值.
解答:解:原式=
-
•
=
-
=
.
当x=
-1时,原式的值=
=1.
| 1 |
| x+1 |
| x+3 |
| (x+1)(x-1) |
| (x-1)2 |
| (x+1)(x+3) |
| 1 |
| x+1 |
| x-1 |
| (x+1)2 |
| 2 |
| (x+1)2 |
当x=
| 2 |
| 2 | ||
(
|
点评:本题主要考查分式的化简求值,把分式化到最简是解答的关键,通分、因式分解和约分是基本环节.
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