题目内容
(2012•亭湖区一模)先化简,再求值:(
-
)÷
,其中x=2
-2.
| x2-4 |
| x2-4x+4 |
| x-2 |
| x+2 |
| x |
| x-2 |
| 3 |
分析:把括号内第一个分式的分子分母分解因式并约分,然后通分并进行同分母分式相加减,再把括号外的除法转化为乘法运算,最后把x的值代入进行计算即可得解.
解答:解:(
-
)÷
,
=(
-
)×
,
=(
-
)×
,
=
×
,
=
×
,
=
,
当x=2
-2时,原式=
=
.
| x2-4 |
| x2-4x+4 |
| x-2 |
| x+2 |
| x |
| x-2 |
=(
| (x+2)(x-2) |
| (x-2)2 |
| x-2 |
| x+2 |
| x-2 |
| x |
=(
| x+2 |
| x-2 |
| x-2 |
| x+2 |
| x-2 |
| x |
=
| x2+4x+4-x2+4x-4 |
| (x-2)(x+2) |
| x-2 |
| x |
=
| 8x |
| (x-2)(x+2) |
| x-2 |
| x |
=
| 8 |
| x+2 |
当x=2
| 3 |
| 8 | ||
2
|
4
| ||
| 3 |
点评:本题考查了分式的化简求值,解题的关键是把分式的分子分母分解因式化到最简,然后代值计算,最后计算结果要分母有理化.
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