题目内容
计算.
|
|
36×(
|
分析:(1)(3)运用乘法分配律解答,
(2)化原式为:
×
+
×
,再运用乘法分配律解答.
(2)化原式为:
3 |
7 |
11 |
7 |
4 |
7 |
11 |
7 |
解答:解:(1)
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)
÷
+
÷
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=1
;
(3)36×(
+
)÷
,
=(36×
+36×
)÷
,
=(28+30)÷
,
=58÷
,
=10.
7 |
13 |
3 |
4 |
3 |
4 |
6 |
13 |
=(
7 |
13 |
6 |
13 |
3 |
4 |
=1×
3 |
4 |
=
3 |
4 |
(2)
3 |
7 |
7 |
11 |
4 |
7 |
7 |
11 |
=
3 |
7 |
11 |
7 |
4 |
7 |
11 |
7 |
=(
3 |
7 |
4 |
7 |
11 |
7 |
=1×
11 |
7 |
=1
4 |
7 |
(3)36×(
7 |
9 |
5 |
6 |
29 |
5 |
=(36×
7 |
9 |
5 |
6 |
29 |
5 |
=(28+30)÷
29 |
5 |
=58÷
29 |
5 |
=10.
点评:本题主要考查学生运用乘法分配律解决问题的能力.
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