题目内容

用递等式计算,能巧算得就要巧算:
81.7+36.57-(31.7-13.43)
14000÷56
56000÷125                          
8.1×18+18+8.1×81
40-12.78+7.22                      
1650÷[5×(98+12)].
分析:(1)将原式变形为(81.7-31.7)+(36.57+13.43),即可简便计算;
(2)将原式变形为14000÷7÷8,即可简便计算;
(3)将原式变形为(56000×8)÷(125×8),即可简便计算;
(4)根据乘法分配律简便计算;
(5)从左往右依次计算即可;
(6)先算括号里面的,再算括号外面的除法.
解答:解:81.7+36.57-(31.7-13.43),
=(81.7-31.7)+(36.57+13.43),
=50+50,
=100;

14000÷56,
=14000÷7÷8,
=2000÷8,
=250;

56000÷125,
=(56000×8)÷(125×8),
=448000÷1000,
=448;
                         
8.1×18+18+8.1×81,
=8.1×(18+1+81),
=8.1×100,
=810;

40-12.78+7.22,
=27.22+7.22,
=34.44;
                      
1650÷[5×(98+12)],
=1650÷[5×110],
=1650÷550,
=3.
点评:考查了小数四则混合运算,关键是熟练掌握计算法则,灵活运用运算定律简便计算.
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