题目内容

计算下面各题,能简算的要简算.
①0.65×101
②76.43-5.33-4.67 ③3.4÷[7.8-(3.9+2.2)]
④13.7÷12.5÷0.8 ⑤3.25×8.4+6.75×8.4 ⑥[1.4×2-(0.65+0.55)]÷40.
分析:①0.65×101,应把101拆成(100+1);
②76.43-5.33-4.67,应用减法的性质把此式变为76.43-(5.33+4.67);
③3.4÷[7.8-(3.9+2.2)],不能简算,按运算顺序进行;
④13.7÷12.5÷0.8,应用除法的性质,把原式变为
13.7÷(12.5×0.8);
⑤3.25×8.4+6.75×8.4,应用乘法分配律的逆运算进行简算;
⑥[1.4×2-(0.65+0.55)]÷40,按运算顺序进行计算.
解答:解:①0.65×101,
=0.65×(100+1),
=0.65×100+0.65,
=65+0.65,
=65.65;
②76.43-5.33-4.67,
=76.43-(5.33+4.67),
=76.43-10,
=66.43;
③3.4÷[7.8-(3.9+2.2)],
=3.4÷[7.8-6.1],
=3.4÷1.7,
=2;
④13.7÷12.5÷0.8,
=13.7÷(12.5×0.8),
=13.7÷10,
=1.37;
⑤3.25×8.4+6.75×8.4,
=(3.25+6.75)×8.4,
=10×8.4,
=84;
⑥[1.4×2-(0.65+0.55)]÷40,
=[2.8-1.2]÷40,
=1.6÷40,
=0.04.
点评:此题重点考查学生的运算定律及其运算顺序,特别注意减法和除法性质的运用,即a-b-c=a-(b+c);a÷b÷c=a÷(b×c).
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