题目内容
递等式计算.(能巧算的要巧算)
380+120÷4
20×(91÷7)
120÷5×4
625÷5-48
465+217-165
130×8-650.
380+120÷4
20×(91÷7)
120÷5×4
625÷5-48
465+217-165
130×8-650.
分析:(1)先算除法,再算加法;
(2)先算小括号里面的除法,再算括号外的乘法;
(3)按照从左到右的顺序计算;
(4)先算除法,再算减法;
(5)运用加法交换律简算;
(6)先算乘法,再算减法.
(2)先算小括号里面的除法,再算括号外的乘法;
(3)按照从左到右的顺序计算;
(4)先算除法,再算减法;
(5)运用加法交换律简算;
(6)先算乘法,再算减法.
解答:解:(1)380+120÷4,
=380+30,
=410;
(2)20×(91÷7),
=20×13,
=260;
(3)120÷5×4,
=24×4,
=96;
(4)625÷5-48,
=125-48,
=77;
(5)465+217-165,
=465-165+217,
=300+217,
=517;
(6)130×8-650,
=1040-650,
=390.
=380+30,
=410;
(2)20×(91÷7),
=20×13,
=260;
(3)120÷5×4,
=24×4,
=96;
(4)625÷5-48,
=125-48,
=77;
(5)465+217-165,
=465-165+217,
=300+217,
=517;
(6)130×8-650,
=1040-650,
=390.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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