题目内容
计算下面各题,能用简便方法计算的用简便方法计算.
1.25×2.5×32 | (
|
101×110-73-37 | ||||||||||||||||||||||
2
|
|
3
|
分析:(1)先把32分解成4×8,再运用乘法结合律简算;
(2)先把125×25结合在一起,再运用乘法分配律简算;
(3)先把101分解成100+1,再运用乘法分配律简算,然后根据减法的性质简算;
(4)先算小括号里面的减法,再算中括号里面的除法,最后算括号外的乘法;
(5)先把除法变成乘法,再运用乘法交换律简算;
(6)根据加法结合律和减法的性质简算.
(2)先把125×25结合在一起,再运用乘法分配律简算;
(3)先把101分解成100+1,再运用乘法分配律简算,然后根据减法的性质简算;
(4)先算小括号里面的减法,再算中括号里面的除法,最后算括号外的乘法;
(5)先把除法变成乘法,再运用乘法交换律简算;
(6)根据加法结合律和减法的性质简算.
解答:解:(1)1.25×2.5×32,
=1.25×2.5×4×8,
=(1.25×8)×(2.5×4),
=10×10,
=100;
(2)(
+
)×125×25,
=(
+
)×(125×25),
=(
×25×125)×(
×125×25),
=(8×125)×(4×25),
=1000×100,
=10000;
(3)101×110-73-37,
=(100+1)×110-73-37,
=100×110+1×110-73-37,
=11000+110-73-37,
=11000+[110-(73+37)],
=11000+[110-110],
=11000+0,
=11000.
(4)2
×[
÷(
-
)],
=2
×[
÷
],
=
×
,
=
;
(5)
÷
×
,
=
×
×
,
=
×
,
=
;
(6)3
-2
+5
-1
,
=(3
+5
)-(1
+2
),
=9-4,
=5.
=1.25×2.5×4×8,
=(1.25×8)×(2.5×4),
=10×10,
=100;
(2)(
8 |
25 |
4 |
125 |
=(
8 |
25 |
4 |
125 |
=(
8 |
25 |
4 |
125 |
=(8×125)×(4×25),
=1000×100,
=10000;
(3)101×110-73-37,
=(100+1)×110-73-37,
=100×110+1×110-73-37,
=11000+110-73-37,
=11000+[110-(73+37)],
=11000+[110-110],
=11000+0,
=11000.
(4)2
2 |
3 |
1 |
3 |
3 |
8 |
1 |
4 |
=2
2 |
3 |
1 |
3 |
1 |
8 |
=
8 |
3 |
8 |
3 |
=
64 |
9 |
(5)
4 |
7 |
7 |
9 |
3 |
4 |
=
4 |
7 |
3 |
4 |
9 |
7 |
=
3 |
7 |
9 |
7 |
=
27 |
49 |
(6)3
3 |
4 |
7 |
12 |
1 |
4 |
5 |
12 |
=(3
3 |
4 |
1 |
4 |
5 |
12 |
7 |
12 |
=9-4,
=5.
点评:此题主要考查分数的四则混合运算的运算顺序,以及应用运算定律进行简便计算的能力.
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