题目内容
怎样简便怎样算:
(1)
(2)[1-(
)
(4)0.625×36+
×36-36
(4)
(5)
+
+
+
+
+
+
+
.
解:(1)(1)
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)[1-(
)]
,
=[1-
]×4,
=
×4,
=
;
(3)0.625×36+
×36-36,
=(0.625+0.375-1)×36,
=0×36,
=0;
(4)(
+
+
+
)×
,
=[(
+
)+(
+
)]×
,
=[1+1]×
,
=2×
,
=
;
(5)
+
+
+
+
+
+
+
,
=1-
+
-
+
-
+
-
+
-
+
-
+
-
+
-
,
=1-
,
=
.
分析:(1)把除法改为乘法,运用乘法分配律简算;
(2)先算小括号内的,再算中括号内的,最后算括号外的;
(3)运用乘法分配律简算;
(4)括号内运用加法交换律与结合律;
(5)把每个分数拆成两个分数相减的形式,然后通过加减相抵消的方法,求出结果.
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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=
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=(
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=1×
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=
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(2)[1-(
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=[1-
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=
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=
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(3)0.625×36+
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=(0.625+0.375-1)×36,
=0×36,
=0;
(4)(
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=[(
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=[1+1]×
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=2×
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=
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(5)
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=1-
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=1-
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=

分析:(1)把除法改为乘法,运用乘法分配律简算;
(2)先算小括号内的,再算中括号内的,最后算括号外的;
(3)运用乘法分配律简算;
(4)括号内运用加法交换律与结合律;
(5)把每个分数拆成两个分数相减的形式,然后通过加减相抵消的方法,求出结果.
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.

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