题目内容
(2010?保靖县)用递等式计算(能简算的要简算)
(1)2842÷14+74×3;
(2)
+
-
+
;
(3)88+99×88;
(4)(
+
)÷
+
.
(1)2842÷14+74×3;
(2)
3 |
7 |
5 |
13 |
3 |
7 |
5 |
13 |
(3)88+99×88;
(4)(
4 |
5 |
1 |
4 |
7 |
3 |
7 |
10 |
分析:(1)同时运算除法和乘法,再算加法;
(2)运用加法交换律和结合律简算;
(3)运用乘法分配律简算;
(4)先算小括号里面的加法,再算括号外的除法,最后算括号外的加法.
(2)运用加法交换律和结合律简算;
(3)运用乘法分配律简算;
(4)先算小括号里面的加法,再算括号外的除法,最后算括号外的加法.
解答:解:(1)2842÷14+74×3,
=203+222,
=425;
(2)
+
-
+
,
=(
-
)+(
+
),
=0+
,
=
;
(3)88+99×88,
=88×(1+99),
=88×100,
=8800;
(4)(
+
)÷
+
,
=
×
+
,
=
+
,
=
.
=203+222,
=425;
(2)
3 |
7 |
5 |
13 |
3 |
7 |
5 |
13 |
=(
3 |
7 |
3 |
7 |
5 |
13 |
5 |
13 |
=0+
10 |
13 |
=
10 |
13 |
(3)88+99×88,
=88×(1+99),
=88×100,
=8800;
(4)(
4 |
5 |
1 |
4 |
7 |
3 |
7 |
10 |
=
21 |
20 |
3 |
7 |
7 |
10 |
=
9 |
20 |
14 |
20 |
=
23 |
20 |
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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