题目内容
解方程.
X:1.2=3:4
=30%
X-
X=
.
解:(1)x:1.2=3:4,
4x=1.2×3,
4x÷4=3.6÷4,
x=0.9,
(2)
=30%,
x:4=3:10,
10x=4×3,
10x÷10=12÷10,
x=1.2,
(3)
x-
x=
,
x=
,
x×
=
×
,
x=2.
分析:(1)根据比例的基本性质:两内项之积等于两外项之积可得4x=1.2×3,再利用等式的性质两边同时除以4即可解答;
(2)可以写成x:4=3:10,根据比例的基本性质:两内项之积等于两外项之积可,10x=4×3,再利用等式的性质两边同时除以10即可解答;
(3)先把左边计算出来得:
x=
,再利用等式的性质,两边同时乘
,即可解答.
点评:此题考查了利用比例的基本性质解比例和利用等式的性质解方程的方法.
4x=1.2×3,
4x÷4=3.6÷4,
x=0.9,
(2)
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x:4=3:10,
10x=4×3,
10x÷10=12÷10,
x=1.2,
(3)

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x=2.
分析:(1)根据比例的基本性质:两内项之积等于两外项之积可得4x=1.2×3,再利用等式的性质两边同时除以4即可解答;
(2)可以写成x:4=3:10,根据比例的基本性质:两内项之积等于两外项之积可,10x=4×3,再利用等式的性质两边同时除以10即可解答;
(3)先把左边计算出来得:



点评:此题考查了利用比例的基本性质解比例和利用等式的性质解方程的方法.

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