题目内容
125-25×6÷30 | (+)×45 | 1.8+4.3+0.7+4.2 |
8.3×9.9+8.3×0.1 | 25×16×50×0.13 | +0.45÷0.9-. |
解:(1)125-25×6÷30
=125-150÷30,
=125-5,
=120;
(2)(+)×45
=+×45,
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)+0.45÷0.9-
=+0.5-,
=1-,
=.
分析:①(+)×45、8.3×9.9+8.3×0.1两式可据乘法分配律进行简便计算;
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
点评:完成本题要认真分析各组数据,尽量用简便方法计算.
=125-150÷30,
=125-5,
=120;
(2)(+)×45
=+×45,
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)+0.45÷0.9-
=+0.5-,
=1-,
=.
分析:①(+)×45、8.3×9.9+8.3×0.1两式可据乘法分配律进行简便计算;
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
点评:完成本题要认真分析各组数据,尽量用简便方法计算.
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