题目内容
5 |
6 |
1 |
13 |
5 |
9 |
2 |
13 |
5 |
18 |
6 |
13 |
1
1 |
2 |
5 |
6 |
7 |
12 |
9 |
20 |
11 |
30 |
1 |
5 |
3 |
5 |
2 |
3 |
2 |
15 |
2 |
35 |
2 |
63 |
2 |
99 |
2 |
143 |
6.8×16.8+19.3×3.2
(1+
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
分析:①把
和
分别分解为:
×2和
×6,然后把公因数提出来,变为
乘以三个数的和再计算较为方便;
②把算式中的分数分别变为两个数的和,然后再逐步计算即可;
③把
变为
×3,然后采取①的方法逐步计算较为方便;
④把算式中的后6个分数分别变为两个分数的差,然后再逐步计算即可;
⑤先把19.3变为16.8+2.5,计算后再把公因数提出来,逐步计算即可;
⑥先把算式(1+
+
+
+
)×(
+
+
)变为:(1+
+
+
)×(
+
+
)-
×(
+
+
).然后把公因数(1+
+
+
)提出来,计算后再把公因数
提出来,逐步计算即可.
2 |
13 |
6 |
13 |
1 |
13 |
1 |
13 |
1 |
13 |
②把算式中的分数分别变为两个数的和,然后再逐步计算即可;
③把
3 |
5 |
1 |
5 |
④把算式中的后6个分数分别变为两个分数的差,然后再逐步计算即可;
⑤先把19.3变为16.8+2.5,计算后再把公因数提出来,逐步计算即可;
⑥先把算式(1+
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
解答:解:①
×
+
×
+
×
,
=
×(
+
+
),
=
×
,
=
;
②1
+
-
+
-
,
=1+
+
+
-
-
+
+
-
-
,
=2-
,
=1
;
③
×27+
×41,
=
×(27+123),
=
×150,
=30;
④
+
+
+
+
+
,
=1-
+
-
+
-
+
-
+
-
+
-
,
=1-
,
=
;
⑤6.8×16.8+19.3×3.2,
=6.8×16.8+(16.8+2.5)×3.2,
=6.8×16.8+16.8×3.2+2.5×3.2,
=16.8×﹙6.8+3.2﹚+2.5×8×0.4,
=168+8,
=176;
⑥(1+
+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
+
),
=(1+
+
+
)×(
+
+
+
)-(1+
+
+
)×(
+
+
)-
×(
+
+
),
=(1+
+
+
)×
-
×(
+
+
),
=
×1,
=
.
5 |
6 |
1 |
13 |
5 |
9 |
2 |
13 |
5 |
18 |
6 |
13 |
=
1 |
13 |
5 |
6 |
10 |
9 |
30 |
18 |
=
1 |
13 |
65 |
18 |
=
5 |
18 |
②1
1 |
2 |
5 |
6 |
7 |
12 |
9 |
20 |
11 |
30 |
=1+
1 |
2 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
4 |
1 |
4 |
1 |
5 |
1 |
5 |
1 |
6 |
=2-
1 |
6 |
=1
5 |
6 |
③
1 |
5 |
3 |
5 |
=
1 |
5 |
=
1 |
5 |
=30;
④
2 |
3 |
2 |
15 |
2 |
35 |
2 |
63 |
2 |
99 |
2 |
143 |
=1-
1 |
3 |
1 |
3 |
1 |
5 |
1 |
5 |
1 |
7 |
1 |
7 |
1 |
9 |
1 |
9 |
1 |
11 |
1 |
11 |
1 |
13 |
=1-
1 |
13 |
=
12 |
13 |
⑤6.8×16.8+19.3×3.2,
=6.8×16.8+(16.8+2.5)×3.2,
=6.8×16.8+16.8×3.2+2.5×3.2,
=16.8×﹙6.8+3.2﹚+2.5×8×0.4,
=168+8,
=176;
⑥(1+
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
=(1+
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
=(1+
1 |
2 |
1 |
3 |
1 |
4 |
1 |
5 |
1 |
5 |
1 |
2 |
1 |
3 |
1 |
4 |
=
1 |
5 |
=
1 |
5 |
点评:计算此题的关键是:根据算式中各个数的特点,把算式中的一个数,变为两个数的和或积,然后根据运算定律再逐步计算.
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