摘要:11.已知公差大于零的等差数列{an}的前n项和为Sn. 且满足a3·a4=117.a2+a5=22. (1)求通项an, (2)若bn=.数列{bn}是等差数列.求非零常数c. [解析] (1){an}为等差数列 ∴a3+a4=a2+a5=22.又a3·a4=117. 解得a3=9.a4=13(∵d>0.a3=13.a4=9舍去). ∴.∴.∴an=4n-3. 知Sn=·n=2n2-n. ∴bn==.∴b1=.b2=.b3=. ∵{bn}是等差数列.2b2=b1+b3,2·=+. 解得c=-(c=0舍去).

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