题目内容
(2009•宣武区二模)(理)
(
+
)=
lim |
x→1 |
x |
x-1 |
x-3 |
x2-1 |
2
2
.分析:
=
+
=
,消除零因子x-1后可求答案.
lim |
x→1 |
x |
x-1 |
x-3 |
x2-1 |
lim |
x→1 |
x2+2x-3 |
x2-1 |
解答:解:
=
+
=
=
=2
故答案为:2
lim |
x→1 |
x |
x-1 |
x-3 |
x2-1 |
lim |
x→1 |
x2+2x-3 |
x2-1 |
lim |
x→1 |
x+3 |
x+1 |
故答案为:2
点评:本题主要考查了
型的极限的求解,解题的关键是要消除灵因子,属于基础试题
0 |
0 |
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