题目内容
(2013•天津)在△ABC中,
,则sin∠BAC=( )
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A.![]() | B.![]() | C.![]() | D.![]() |
C
∵∠ABC=
,AB=
,BC=3,
∴由余弦定理得:AC2=AB2+BC2﹣2AB•BC•cos∠ABC=2+9﹣6=5,
∴AC=
,
则由正弦定理
=
得:sin∠BAC=
=
.
故选C
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∴由余弦定理得:AC2=AB2+BC2﹣2AB•BC•cos∠ABC=2+9﹣6=5,
∴AC=
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则由正弦定理
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故选C
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