题目内容

如图,在△ABC中,AD⊥AB,
BC
=
3
BD
|
AD
|=1
,则
AC
AD
=______.
AC
AD
=|
AC
|•|
AD
|cos∠DAC

|
AD
|=1

AC
AD
=|
AC
|•|
AD
|cos∠DAC=|
AC
|•cos∠DAC

∠BAC=
π
2
+∠DAC

∴cos∠DAC=sin∠BAC,
AC
AD
=|
AC
|•|
AD
|cos∠DAC=|
AC
|•cos∠DAC=|
AC
|sin∠BAC

在△ABC中,由正弦定理得
|AC|
sinB
=
|BC|
sin∠BAC
变形得|AC|sin∠BAC=|BC|sinB,
AC
AD
=|
AC
|•|
AD
|cos∠DAC=|
AC
|•cos∠DAC=|
AC
|sin∠BAC

=|BC|sinB=|BC|•
|AD|
|BD|
=
3

故答案为
3
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