题目内容
曲线y=x3+2x在点A(1,3)处的切线方程是________.
曲线y=x3-2x在点(1,-1)处的切线方程是
A.x-y-2=0
B.x-y+2=0
C.x+y+2=0
D.x+y-2=0
曲线y=x3-2x+4在点(1,3)处的切线的倾斜角为
A.30°
B.45°
C.60°
D.120°
曲线y=x3+2x在点A(2,10)处的切线的斜率k是
14
12
8
6
曲线y=x3-2x+3在x=1处的切线方程为_____