题目内容
若全集I={x|x≤9,x∈N},M={1,7,8},N={2,3,5,7},S={1,4,7},则(M∪N)∩?IS=( )
分析:根据M与N求出两集合的并集,由全集I求出S的补集,找出并集与补集的交集即可.
解答:解:∵全集I={x|x≤9,x∈N}={0,1,2,3,4,5,6,7,8,9},M={1,7,8},N={2,3,5,7},S={1,4,7},
∴M∪N={1,2,3,5,7,8},?IS={0,2,3,5,6,8,9},
则(M∪N)∩?IS={2,3,5,8}.
故选C
∴M∪N={1,2,3,5,7,8},?IS={0,2,3,5,6,8,9},
则(M∪N)∩?IS={2,3,5,8}.
故选C
点评:此题考查了交、并、补集的混合运算,熟练掌握各自的定义是解本题的关键.
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