ÌâÄ¿ÄÚÈÝ

£¨08ÎߺþÄ£Ä⣩Öпƴó³ÂǬÍú½ÌÊÚµÈÈË·¢ÏÖÁËÈ˹¤ºÏ³É½ð¸ÕʯµÄз½·¨£¬Æ仯ѧԭÀíΪ£º

¢ÙNa+CO2  C(½ð¸Õʯ)+C(ʯī)+Na2CO3(δÅäƽ)¡£

¸Ã·¨±È1955ÄêÈ˹¤Ê×´ÎÖƵýð¸ÕʯµÄ·½·¨ÈÝÒ׵ö࣬Æ仯ѧԭÀíÊÇ£º

 
 

 


ÒÔÏÂÓйرíÊöÖÐÕýÈ·µÄÊÇ£¨£©

A£®·´Ó¦¢ÙºÍ¢Ú¶¼´æÔھɻ¯Ñ§¼üµÄ¶ÏÁÑÓëл¯Ñ§¼üµÄÐγÉ

B£®Ð·¨ÀûÓõÄÊÇ»¯Ñ§±ä»¯£¬¾É·¨ÀûÓõÄÊÇÎïÀí±ä»¯

C£®ÔÚ·´Ó¦¢ÙÖÐÿÉú³É12g½ð¸ÕʯÐèÒªÏûºÄ23g½ðÊôÄÆ

D£®·´Ó¦¢ÙºÍ¢ÚÖУ¬½ð¸Õʯ¶¼ÊÇ»¹Ô­²úÎNa2CO3ÊÇÑõ»¯²úÎï

´ð°¸£ºA
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

2(08Õã½­Ê¡¿ª»¯ÖÐѧģÄâ)ʵÑéÊÒÖиù¾Ý2SO2£«O22SO3£»¦¤H=-393.2 kJ?mol-1Éè¼ÆÈçÏÂͼËùʾʵÑé×°ÖÃÀ´ÖƱ¸SO3¹ÌÌå¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£  

 
 

 


£¨1£©ÊµÑéÇ°£¬±ØÐë½øÐеIJÙ×÷ÊÇ£¨Ìî²Ù×÷Ãû³Æ£¬²»±Øд¾ßÌå¹ý³Ì£©¡¡¡¡¡¡¡¡¡¡¡¡

£¨2£©ÔÚA×°ÖÃÖмÓÈëNa2SO3¹ÌÌåµÄͬʱ£¬»¹Ðè¼Ó¼¸µÎË®£¬È»ºóÔٵμÓŨÁòËá¡£¼Ó¼¸µÎË®µÄ×÷ÓÃÊÇ                           ¡¡                            

£¨3£©Ð¡ÊÔ¹ÜCµÄ×÷ÓÃÊÇ                                                   

£¨4£©¹ã¿ÚÆ¿DÄÚÊ¢µÄÊÔ¼ÁÊÇ                ¡£×°ÖÃDµÄÈý¸ö×÷ÓÃÊÇ       ¢Ù¡¡¡¡ ¡¡¡¡

            ¢Ú                   ¢Û                      

£¨5£©ÊµÑéÖе±Cr2O3±íÃæºìÈÈʱ£¬Ó¦½«¾Æ¾«µÆÒÆ¿ªÒ»»á¶ùÔÙ¼ÓÈÈ£¬ÒÔ·Àζȹý¸ß£¬ÕâÑù×öµÄÔ­ÒòÊÇ                          ¡¡                                   ¡¡

£¨6£©×°ÖÃFÖÐUÐ͹ÜÄÚÊÕ¼¯µ½µÄÎïÖʵÄÑÕÉ«¡¢×´Ì¬ÊÇ                         

£¨7£©×°ÖÃGµÄ×÷ÓÃÊÇ                                                      

£¨8£©´ÓG×°Öõ¼³öµÄβÆø´¦Àí·½·¨ÊÇ                                        

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø