ÌâÄ¿ÄÚÈÝ

ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¡¢FÊǺ¬ÓÐͬһÖÖÔªËصĻ¯ºÏÎÆäÖÐFÄÜʹʪÈóºìɫʯÈïÊÔÖ½±äÀ¶É«£¬ËüÃÇÖ®¼äÄÜ·¢ÉúÈçÏ·´Ó¦£º

¢ÙA£«H2O¡úB£«C ¢ÚC£«F¡úD ¢ÛD£«NaOH¡úF£«E£«H2O

£¨1£©Ð´³öBµÄ»¯Ñ§Ê½_________¡£

£¨2£©¹¤ÒµÉú²úCµÄ¹ý³ÌÖÐÓÐÈçÏÂÒ»²½·´Ó¦£º¼´F¾­´ß»¯Ñõ»¯Éú³ÉBºÍH2O£¬Ð´³ö¸Ã²½·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________________________¡£

£¨3£©Ä³Í¬Ñ§ÓÃͼʾװÖ㨹̶¨¡¢¼ÓÈÈÒÇÆ÷ºÍÏ𽺹ÜÂÔ£©½øÐÐÓйØFµÄÖÆȡʵÑé̽¾¿£¬»Ø´ðÏÂÁÐÎÊÌ⣺

£¨i£©ÈôÓÃ×°ÖâÙÖÆÈ¡F£¬ÆäÊÕ¼¯×°ÖÃΪ__________£¨Ìî×°ÖÃÐòºÅ£©£¬·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ______________________¡£

£¨¢¢£©ÈôÓÃ×°ÖâÚÖÆÈ¡F£¬·ÖҺ©¶·ÖÐÊ¢×°µÄÊÔ¼ÁΪ__________£¬Ô²µ×ÉÕÆ¿ÖÐÊ¢×°µÄÊÔ¼ÁΪ______________¡££¨ÈÎдһÖÖ£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÄòËØ/H2O2ÈÜÒº¿ÉÓÃÓÚÑÌÆøµÄÍÑÁòÍÑÏõ¡£

(1)ÒÑÖªT¡æʱ£¬2SO2(g)+O2(g) 2SO3(g) ¡÷H1

2H2O2(I)=2H2O(I)+O2(g) ¡÷H2

SO3(g)+H2O(I))=H2SO4(I) ¡÷H3

ÔòSO2(g)+H2O2(I))=H2SO4(I) ¡÷H4=__________ (Óú¬¡÷H1¡¢¡÷H2¡¢¡÷H3µÄ´úÊýʽ±íʾ)

(2)ÄòËØ[CO(NH2)2]ÈÜÒº¶ÔNOx¼°SO2ÓÐÒ»¶¨µÄÍѳýÂÊ¡£½«SO2ºÍNOx (N©–Ô¼Õ¼90%)ͨÈëÑõÆøµÄÌå»ý·ÖÊýΪ7%¡¢ÄòËØŨ¶ÈΪ5%µÄ·´Ó¦Æ÷ÖнøÐз´Ó¦¡£

¢ÙÑÌÆøÖÐSO2×îÖÕת»¯ÎªÒ»ÖÖÕýÑΣ¬Æ仯ѧʽΪ______________£»NOºÍNO2ÒÔÎïÖʵÄÁ¿Ö®±È1:1ÓëCO(NH2)2·´Ó¦Éú³ÉÎÞ¶¾ÆøÌåµÄ»¯Ñ§·½³ÌʽΪ_______________¡£

¢Ú°±»ù¼×Ëáï§(H2NCOONH4)ÊÇÄòËصÄË®½â²úÎ½«Ò»¶¨Á¿µÄ°±»ù¼×Ëáï§ÖÃÓÚºãÈÝÃܱÕÈÝÆ÷ÖУ¬·¢Éú·´Ó¦£ºNH2COONH4(s)2NH3(g)£«CO2(g) ¡÷H£¬ÊµÑé²âµÃ²»Í¬Î¶ÈÏÂƽºâʱÆøÌåµÄ×ÜŨ¶ÈÈçÏÂ±í£º

ζÈ/K

338

343

348

353

ƽºâʱÆøÌåµÄ×ÜŨ¶È/mol • L-1

0.36

0.48

0.60

0.72

¸Ã·´Ó¦µÄ¡÷H__________(Ìî¡°>¡±»ò¡°<¡±)0£»348Kʱ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýK__________________¡£

(3)ÆäËûÌõ¼þ²»±ä£¬ÏòÄòËØÈÜÒºÖÐÌí¼ÓH2O2ÈÜÒº£¬²âµÃ²»Í¬ pHϵªÑõ»¯ÎïµÄÍѳýÂÊÓëʱ¼äµÄ¹ØϵÈçͼËùʾ¡£

¢ÙNOÓëH2O2·¢Éú·´Ó¦Éú³ÉÑÇÏõËáʱ£¬Ñõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ____________¡£

(2)ÍÑÏõʱ£¬×î¼ÑpHΪ_________£»ÔÚ¼îÐÔ½Ïǿʱ£¬NOxÍѳýÂʽµµÍ£¬ÆäÔ­ÒòÊÇ___________(ÈÎдһµã)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø