ÌâÄ¿ÄÚÈÝ

ÏÂͼÊÇÒ»¸öÒÒ´¼È¼ÁÏµç³Ø¹¤×÷ʱµÄʾÒâͼ£¬ÒÒ³ØÖеÄÁ½¸öµç¼«Ò»¸öÊÇʯīµç¼«£¬Ò»¸öÊÇÌúµç¼«£¬¹¤×÷ʱM¡¢NÁ½¸öµç¼«µÄÖÊÁ¿¶¼²»¼õÉÙ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Mµç¼«µÄ²ÄÁÏÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡ £¬µç¼«Ãû³ÆÊÇ¡¡¡¡¡¡¡¡¡¡ £¬NµÄµç¼«·´Ó¦Ê½Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬Í¨ÈëÒÒ´¼µÄ²¬µç¼«µÄµç¼«·´Ó¦Ê½Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

£¨2£©Ôڴ˹ý³ÌÖУ¬ÒÒ³ØÖÐijһµç¼«Îö³ö½ðÊôÒø4.32gʱ£¬¼×³ØÖÐÀíÂÛÉÏÏûºÄÑõÆøÎª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡L£¨±ê×¼×´¿öÏ£©£»Èô´ËʱÒÒ³ØÈÜÒºµÄÌå»ýΪ400mL£¬ÔòÒÒ³ØÖÐÈÜÒºµÄpHΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

£¨3£©ÈôÔÚ³£Î³£Ñ¹Ï£¬1g C2H5OHȼÉÕÉú³ÉCO2ºÍҺ̬H2Oʱ·Å³ö29.71kJÈÈÁ¿£¬±íʾ¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡ ¡£

 

£¨1£©Ìú Òõ¼«  4OH¡ª£­4e¡ª£½2H2O+O2¡ü

    C2H5OH£­12e+16OH¡ª=2CO32¡ª+11H2O

£¨2£©0.224;1

£¨3£©C2H5OH£¨l£©+3O2£¨g£©£½2CO2£¨g£©+3H2O£¨l£©¡÷H=£­1366.7kJ/mol

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø