ÌâÄ¿ÄÚÈÝ

ÏÂÁÐÀë×Ó·½³ÌʽÕýÈ·µÄÊÇ

A£®0£®01mol/L NH4Al£¨SO4£©2ÈÜÒºÓë0£®02 mol/LBa£¨OH£©2ÈÜÒºµÈÌå»ý»ìºÏ²úÉú³Áµí£º
NH4++Al3++2SO42?+2Ba2++4OH?=2BaSO4¡ý+ Al£¨OH£©3¡ý+NH3¡¤H2O
B£®NH4HCO3ÈÜÒºÓë×ãÁ¿Ba£¨OH£©2ÈÜÒº»ìºÏ£ºHCO3£­£«Ba2£«£«OH£­£½BaCO3¡ý£«H2O
C£®ÏòNaHCO3ÈÜÒºÖмÓÈë¹ýÁ¿µÄ³ÎÇåʯ»ÒË®£¬³öÏÖ°×É«³Áµí£º 2HCO3-+Ca2++2OH-=CaCO3¡ý+CO32-+2H2O
D£®ÏòFeCl3ÈÜÒºÖмÓÈëNa2SÈÜÒº²úÉú³Áµí£º2Fe3++3S2-+6H2O=2Fe£¨OH£©3¡ý+3H2S¡ü

A

½âÎöÊÔÌâ·ÖÎö£ºA¡¢0£®01mol/L NH4Al£¨SO4£©2ÈÜÒºÓë0£®02 mol/LBa£¨OH£©2ÈÜÒºµÈÌå»ý»ìºÏÉú³ÉÁòËá±µ¡¢ÇâÑõ»¯ÂÁºÍһˮºÏ°±£¬AÕýÈ·£»B¡¢NH4HCO3ÈÜÒºÓë×ãÁ¿Ba£¨OH£©2ÈÜÒº»ìºÏÉú³É̼Ëá±µ¡¢Ò»Ë®ºÏ°±ºÍË®£¬B´íÎó£»C¡¢ÏòNaHCO3ÈÜÒºÖмÓÈë¹ýÁ¿µÄ³ÎÇåʯ»ÒË®Éú³É̼Ëá¸Æ¡¢ÇâÑõ»¯ÄƺÍË®£¬C´íÎó£»D¡¢ÏòFeCl3ÈÜÒºÖмÓÈëNa2SÈÜÒºµ¥ÖÊÁò¡¢ÂÈ»¯ÄƺÍÂÈ»¯ÑÇÌú£¬D´íÎ󣬴ð°¸Ñ¡A¡£
¿¼µã£º¿¼²éÀë×Ó·½³ÌʽµÄÕýÎóÅжÏ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

FeCl3ÊÇÒ»ÖÖÓÃ;±È½Ï¹ã·ºµÄÑΡ£
£¨1£©Ó¡Ë¢µç·°åÊÇÓɸ߷Ö×Ó²ÄÁϺÍÍ­²­¸´ºÏ¶ø³É¡£¿ÌÖÆÓ¡Ë¢µç·ʱ£¬ÒªÓÃFeCl3ÈÜÒº×÷Ϊ¡°¸¯Ê´Òº¡±£¬Éú³ÉCuCl2ºÍFeCl2¡£Çëд³ö·´Ó¦µÄÀë×Ó·½³Ìʽ                 ¡£
£¨2£©FeCl3ÔÚÌìȻˮÖпÉÉú³ÉÇâÑõ»¯Ìú½ºÌ壬Æä³Á½µË®ÖÐÐü¸¡ÎïµÄËٶȸßÓÚÂÁÑΣ¨ÈçÁòËáÂÁµÈ£©£¬ÊdzÇÊÐÎÛË®¼°¹¤Òµ·ÏË®´¦ÀíµÄ¸ßЧÐõÄý¼Á¡£ÊµÑéÊÒÖÆÈ¡ÇâÑõ»¯Ìú½ºÌåµÄ·½·¨ÊÇ       £¨Ìî×ÖĸÐòºÅ£©¡£

A£®½«±¥ºÍµÄFeCl3ÈÜÒºµÎÈë·ÐË®ÖУ¬Éú³É×Ø»ÆÉ«ÒºÌå¼´¿É¡£
B£®ÔÚFeCl3ÈÜÒºÖмÓÈë×ãÁ¿µÄNaOHÈÜÒº
C£®½«±¥ºÍµÄFeCl3ÈÜÒºµÎÈë·ÐË®£¬²¢¼ÌÐøÖó·ÐÖÁÉú³ÉºìºÖÉ«ÒºÌå
D£®½«±¥ºÍµÄFeCl3ÈÜÒºµÎÈë·ÐË®£¬²¢¼ÌÐøÖó·ÐÖÁÉú³ÉºìºÖÉ«³Áµí
Ö¤Ã÷´Ë½ºÌåÒѾ­ÖƳɵÄ×î¼òµ¥·½·¨Îª                                       ¡£
£¨3£©FeCl3¿ÉʹʪÈóµÄµí·Ûµâ»¯¼ØÊÔÖ½±äÀ¶£¬»¯Ñ§·½³ÌʽÈçÏ£º2FeCl3£« 2KI £½ 2FeCl2£« I2£«2KI£¬ÔÚÉÏʽÉÏÓÃË«ÏßÇÅ·¨±ê³ö¸Ã·´Ó¦µç×ÓתÒƵķ½ÏòºÍÊýÄ¿¡£Ïò·´Ó¦ºóµÄÈÜÒºÖмÓÈëCCl4ÈÜÒº£¬Õñµ´¡¢¾²Öúó»á·¢ÏÖϲãÒºÌåµÄÑÕɫΪ       É«£¬ÔÙ½«»ìºÏÒºµ¹Èë          £¨ÌîÒÇÆ÷Ãû³Æ£©ÖУ¬½«Á½²ãÒºÌå·ÖÀë¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø