ÌâÄ¿ÄÚÈÝ

»ÆÌú¿óÊÇÎÒ¹ú´ó¶àÊýÁòËá³§ÖÆÈ¡ÁòËáµÄÖ÷ÒªÔ­ÁÏ¡£Ä³»¯Ñ§ÐËȤС×é¶Ôij»ÆÌú¿óʯ(Ö÷Òª³É·ÖΪFeS )½øÐÐÈçÏÂʵÑé̽¾¿¡£
[ʵÑéÒ»]£º²â¶¨ÁòÔªËØµÄº¬Á¿
I£®½«m g¸Ã»ÆÌú¿óÑùÆ··ÅÈëÈçÏÂͼËùʾװÖÃ(¼Ð³ÖºÍ¼ÓÈÈ×°ÖÃÊ¡ÂÔ)µÄʯӢ¹ÜÖУ¬´Óa´¦²»¶ÏµØ»º»ºÍ¨Èë¿ÕÆø£¬¸ßÎÂׯÉÕʯӢ¹ÜÖеĻÆÌú¿óÑùÆ·ÖÁ·´Ó¦ÍêÈ«µÃµ½ºìרɫ¹ÌÌåºÍÒ»Öִ̼¤ÐÔÆøÎ¶µÄÆøÌå¡£
£¨1£©Ð´³öʯӢ¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º________________________
¢ò£®·´Ó¦½áÊøºó£¬½«ÒÒÆ¿ÖеÄÈÜÒº½øÐÐÈçÏ´¦Àí£º
ÎÊÌâÌÖÂÛ£º
£¨2£©IÖУ¬¼×Æ¿ÄÚËùÊ¢ÊÔ¼ÁÊÇ__________ÈÜÒº¡£ÒÒÆ¿ÄÚ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÓÐ_________________________¡¢__________________________¡£   
£¨3£©¢òÖУ¬Ëù¼ÓH2O2ÈÜÒºÐè×ãÁ¿µÄÀíÓÉÊÇ________________________¡£     
£¨4£©¸Ã»ÆÌú¿óʯÖÐÁòÔªËØµÄÖÊÁ¿·ÖÊýΪ_____________________¡£
[ʵÑé¶þ]£ºÉè¼ÆÒÔÏÂʵÑé·½°¸²â¶¨ÌúÔªËØµÄº¬Á¿
ÎÊÌâÌÖÂÛ£º
£¨5£©¢ÚÖУ¬ÈôÑ¡ÓÃÌú·Û×÷»¹Ô­¼Á¡£ÄãÈÏΪºÏÀíÂð? __________¡£Èô²»ºÏÀí£¬»áÈçºÎÓ°Ïì²âÁ¿½á¹û_________________________£¨ÈôºÏÀí£¬´Ë¿Õ²»´ð£©¡£
£¨6£©¢ÛÖУ¬ÐèÒªÓõ½µÄÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜÍ⣬»¹ÓÐ___________________¡£
£¨7£©¢ÜÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________________________¡£
£¨1£©
£¨2£©ÇâÑõ»¯ÄÆ(»òÇâÑõ»¯¼ØµÈ)£»
£¨3£©Ê¹SO32-ÍêÈ«Ñõ»¯ÎªSO42-  
£¨4£©
£¨5£©²»ºÏÀí£»»áʹËù²âµÃµÄÌúÔªËØµÄÖÊÁ¿·ÖÊýÆ«´ó
£¨6£©250mLÈÝÁ¿Æ¿
£¨7£©5Fe2++MnO4-+8H+=Mn2++5Fe3++4H2O
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
»ÆÌú¿óÊÇÎÒ¹ú´ó¶àÊýÁòËá³§ÖÆÈ¡ÁòËáµÄÖ÷ÒªÔ­ÁÏ£®Ä³»¯Ñ§ÐËȤС×é¶Ôij»ÆÌú¿óʯ£¨Ö÷Òª³É·ÖΪFeS2£©½øÐÐÈçÏÂʵÑé̽¾¿£®
¡¾ÊµÑéÒ»¡¿£º²â¶¨ÁòÔªËØµÄº¬Á¿
I£®½«m1g¸Ã»ÆÌú¿óÑùÆ··ÅÈëÈçÏÂͼËùʾװÖ㨼гֺͼÓÈÈ×°ÖÃÊ¡ÂÔ£©µÄʯӢ¹ÜÖУ¬´Óa´¦²»¶ÏµØ»º»ºÍ¨Èë¿ÕÆø£¬¸ßÎÂׯÉÕʯӢ¹ÜÖеĻÆÌú¿óÑùÆ·ÖÁ·´Ó¦ÍêÈ«µÃµ½ºìרɫ¹ÌÌåºÍÒ»Öִ̼¤ÐÔÆøÎ¶µÄÆøÌ壮д³öʯӢ¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º
4FeS2+11O2
 ¸ßΠ
.
 
2Fe2O3+8SO2
4FeS2+11O2
 ¸ßΠ
.
 
2Fe2O3+8SO2
£®

¢ò£®·´Ó¦½áÊøºó£¬½«ÒÒÆ¿ÖеÄÈÜÒº½øÐÐÈçÏ´¦Àí£º

ÎÊÌâÌÖÂÛ£º
£¨1£©IÖУ¬¼×ÖÐËùÊ¢ÊÔ¼ÁÊÇ
¼îʯ»Ò
¼îʯ»Ò
£®
£¨2£©¢òÖУ¬Ëù¼ÓH2O2ÈÜÒºÐè×ãÁ¿µÄÀíÓÉÊÇ
ʹSO32-ÍêÈ«Ñõ»¯ÎªSO42-
ʹSO32-ÍêÈ«Ñõ»¯ÎªSO42-
£»
·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ
SO32-+H2O2=SO42-+H2O
SO32-+H2O2=SO42-+H2O
£®
£¨3£©¸Ã»ÆÌú¿óʯÖÐÁòÔªËØµÄÖÊÁ¿·ÖÊýΪ
32m2
233m1
¡Á100%
32m2
233m1
¡Á100%
£®
¡¾ÊµÑé¶þ¡¿£ºÉè¼ÆÒÔÏÂʵÑé·½°¸²â¶¨ÌúÔªËØµÄº¬Á¿

ÎÊÌâÌÖÂÛ£º
£¨4£©¢ÚÖУ¬ÈôÓÃÌú·Û×÷»¹Ô­¼Á£¬ÔòËù²âµÃµÄÌúÔªËØµÄº¬Á¿
Æ«´ó
Æ«´ó
£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족£¬ÏÂͬ£©£»Èô½«Ï¡ÊÍÒº¾ÃÖúóÔÙÓÃËáÐÔKMnO4µÎ¶¨£¬ÔòËù²âµÃµÄÌúÔªËØµÄº¬Á¿
ƫС
ƫС
£®
£¨5£©¢ÛÖУ¬ÐèÒªÓõ½µÄÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜÍ⣬»¹ÓÐ
250mLÈÝÁ¿Æ¿
250mLÈÝÁ¿Æ¿
£®
£¨6£©Ä³Í¬Ñ§Ò»¹²½øÐÐÁËÈý´ÎµÎ¶¨ÊµÑ飬Èý´ÎʵÑé½á¹û¼Ç¼ÈçÏ£º
ʵÑé´ÎÊý µÚÒ»´Î µÚ¶þ´Î µÚÈý´Î
ÏûºÄKMnO4ÈÜÒºÌå»ý/mL 26.42 25.05 24.95
¸ù¾ÝËù¸øÊý¾Ý£¬¼ÆËã¸ÃÏ¡ÊÍÒºÖÐFe2+µÄÎïÖʵÄÁ¿Å¨¶ÈΪc=
0.5mol/L
0.5mol/L
£®£¨Ìáʾ£º5Fe2++MnO4-+8H+=Mn2++5Fe3++4H2O£©
£¨2011?Ôæ×¯Ä£Ä⣩»ÆÌú¿óÊÇÎÒ¹ú´ó¶àÊýÁòËá³§ÖÆÈ¡ÁòËáµÄÖ÷ÒªÔ­ÁÏ£®Ä³»¯Ñ§ÐËȤС×é¶Ôij»ÆÌú¿óʯ£¨Ö÷Òª³É·ÖΪFeS2£©½øÐÐÈçÏÂʵÑé̽¾¿£®
[ʵÑéÒ»]²â¶¨»ÆÌú¿óÖÐÁòÔªËØµÄº¬Á¿
¢ñ£®½«m1 g¸Ã»ÆÌú¿óÑùÆ··ÅÈëÈçÏÂͼËùʾװÖ㨼гֺͼÓÈÈ×°ÖÃÊ¡ÂÔ£©µÄʯӢ¹ÜÖУ¬´Óa´¦²»¶ÏµØ»º»ºÍ¨Èë¿ÕÆø£¬¸ßÎÂׯÉÕʯӢ¹ÜÖеĻÆÌú¿óÑùÆ·ÖÁ·´Ó¦ÍêÈ«£®

¢ò£®·´Ó¦½áÊøºó£¬½«ÒÒÆ¿ÖеÄÈÜÒº½øÐÐÈçÏ´¦Àí£º

ÎÊÌâÌÖÂÛ£º
£¨1£©¢ñÖУ¬Ê¯Ó¢¹ÜÖз¢ÉúµÄ·´Ó¦·½³ÌʽΪ
4FeS2+11O2
 ¸ßΠ
.
 
2Fe2O3+8SO2
4FeS2+11O2
 ¸ßΠ
.
 
2Fe2O3+8SO2
£®
£¨2£©¢òÖУ¬ÎªÅжÏËù¼ÓBaCl2ÊÇ·ñ¹ýÁ¿£¬ÓÐͬѧÉè¼ÆÁËÈçÏÂʵÑé·½°¸£¬ÆäÖкÏÀíµÄÊÇ
C
C

A£®È¡ÉÙÁ¿ÉϲãÇåÒº£¬¼ÌÐøµÎ¼ÓBaCl2£¬ÈôÎÞ³Áµí²úÉúÔò˵Ã÷BaCl2ÒѹýÁ¿£®
B£®È¡ÉÙÁ¿ÉϲãÇåÒº£¬¼ÌÐøµÎ¼ÓÏ¡H2SO4£¬Èô³Áµí²úÉúÔò˵Ã÷BaCl2ÒѹýÁ¿£®
C£®´ý×ÇÒº³ÎÇåºó£¬¼ÌÐøµÎ¼ÓBaCl2£¬ÈôÎÞ³Áµí²úÉúÔò˵Ã÷BaCl2ÒѹýÁ¿£®
D£®´ý×ÇÒº³ÎÇåºó£¬¼ÌÐøµÎ¼ÓÏ¡H2SO4£¬Èô³Áµí²úÉúÔò˵Ã÷BaCl2ÒѹýÁ¿£®
£¨3£©¸Ã»ÆÌú¿óÖÐÁòÔªËØµÄÖÊÁ¿·ÖÊýΪ
32m2
233m1
¡Á100%
32m2
233m1
¡Á100%
£®
[ʵÑé¶þ]²â¶¨»ÆÌú¿óÖÐÌúÔªËØµÄº¬Á¿
¢ÙÓÃ×ãÁ¿Ï¡ÁòËáÈܽâʯӢ¹ÜÖеĹÌÌå²ÐÔü£»
¢Ú¼Ó»¹Ô­¼ÁʹÈÜÒºÖеÄFe3+Íêȫת»¯ÎªFe2+ºó£¬¹ýÂË¡¢Ï´µÓ£»
¢Û½«ÂËҺϡÊÍÖÁ250mL£»
¢ÜȡϡÊÍÒº25.00mL£¬ÓÃŨ¶ÈΪ0.10mol/LµÄËáÐÔKMnO4ÈÜÒºµÎ¶¨£¬ÊµÑ鯽¾ùÏûºÄKMnO4ÈÜÒºÌå»ýΪV mL£®
ÎÊÌâÌÖÂÛ£º
£¨4£©¢ÜÖУ¬ÐèÒªÓõ½µÄÖ÷ÒªÒÇÆ÷ÓÐ
Ìú¼Ų̈¡¢ËáÐԵζ¨¹Ü¡¢ÉÕ±­¡¢µÎ¶¨¹Ü¼Ð¡¢×¶ÐÎÆ¿
Ìú¼Ų̈¡¢ËáÐԵζ¨¹Ü¡¢ÉÕ±­¡¢µÎ¶¨¹Ü¼Ð¡¢×¶ÐÎÆ¿
£»
£¨5£©¢ÚÖУ¬ÈôÑ¡ÓÃÌú·Û×÷»¹Ô­¼Á£®ÄãÈÏΪºÏÀíÂð£¿
²»ºÏÀí
²»ºÏÀí
£¬ÀíÓÉÊÇ
ÓÃÌú×÷»¹Ô­¼Á»áÔö¼ÓÌúÔªËØµÄÁ¿
ÓÃÌú×÷»¹Ô­¼Á»áÔö¼ÓÌúÔªËØµÄÁ¿
£®
£¨6£©»ÆÌú¿óÖÐÌúÔªËØµÄÖÊÁ¿·ÖÊýΪ
28V
m1
%
28V
m1
%
£®

£¨14·Ö£©»ÆÌú¿óÊÇÎÒ¹ú´ó¶àÊýÁòËá³§ÖÆÈ¡ÁòËáµÄÖ÷ÒªÔ­ÁÏ¡£Ä³»¯Ñ§ÐËȤС×é¶Ôij»ÆÌú¿óʯ£¨Ö÷Òª³É·ÖΪFeS£©½øÐÐÈçÏÂʵÑé̽¾¿¡£

       [ʵÑéÒ»]£º²â¶¨ÁòÔªËØµÄº¬Á¿

       I£®½«mg¸Ã»ÆÌú¿óÑùÆ·£¨ÔÓÖÊÖв»º¬ÁòºÍÌú£©·ÅÈëÈçÏÂͼËùʾװÖ㨼гֺͼÓÈÈ×°ÖÃÊ¡ÂÔ£©µÄʯӢ¹ÜÖУ¬´Óa´¦²»¶ÏµØ»º»ºÍ¨ÈË¿ÕÆø£¬¸ßÎÂׯÉÕʯӢ¹ÜÖеĻÆÌú¿óÑùÆ·ÖÁ·´Ó¦ÍêÈ«¡£Ê¯Ó¢¹ÜÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º

       ¢ò£®·´Ó¦½áÊøºó£¬½«ÒÒÆ¿ÖеÄÈÜÒº½øÐÐÈçÏ´¦Àí£º

       ÎÊÌâÌÖÂÛ£º

   £¨1£©IÖУ¬¼×Æ¿ÄÚËùÊ¢ÊÔ¼ÁÊǣߣߣߣߣߣߣߣßÈÜÒº¡£ÒÒÆ¿ÄÚ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽÓУߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߡ¢£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

   £¨2£©¢òÖС£Ëù¼ÓHOÈÜÒºÐè×ãÁ¿µÄÀíÓÉÊǣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߣߡ£

   £¨3£©¸Ã»ÆÌú¿óʯÖÐÁòÔªËØµÄÖÊÁ¿·ÖÊýΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

       [ʵÑé¶þ]£ºÉè¼ÆÒÔÏÂʵÑé·½°¸²â¶¨ÌúÔªËØµÄº¬Á¿

       ÎÊÌâÌÖÂÛ£º

   £¨4£©¢ÚÖУ¬ÈôÑ¡ÓÃÌú·Û×÷»¹Ô­¼Á¡£ÄãÈÏΪºÏÀíÂð? £ß£ß£ß£ß£ß£ß£ß£ß¡£Èô²»ºÏÀí£¬»áÈçºÎÓ°Ïì²âÁ¿½á¹û£º£ß£ß£ß£ß£ß£ß£ß£ß£¨ÈôºÏÀí£¬´Ë¿Õ²»´ð£©¡£

   £¨5£©¢ÛÖУ¬ÐèÒªÓõ½µÄÒÇÆ÷³ýÉÕ±­¡¢²£Á§°ô¡¢½ºÍ·µÎ¹ÜÍ⣬»¹ÓУߣߣߣߣߣߣߣߡ£

   £¨6£©¢ÜÖиßÃÌËá¼ØÈÜÒºÓ¦·ÅÔڣߣߣߣߣߵζ¨¹ÜÖУ»Åжϵζ¨ÖÕµãµÄÏÖÏóΪ£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß£ß¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø