ÌâÄ¿ÄÚÈÝ

(15·Ö)ijÖÐѧ¿ÎÍâÐËȤС×éÓöèÐԵ缫µç½â±¥ºÍʳÑÎË®£¨º¬ÉÙÁ¿Ca2+¡¢Mg2+)×÷ϵÁÐ̽¾¿£¬×°ÖÃÈçÏÂͼËùʾ£º

£¨1£©µç½âʱ£¬¼×ͬѧ·¢Ïֵ缫a¸½½üÈÜÒº³öÏÖ»ë×Ç,ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò

______________________________________________________________¡£

£¨2£©Ò»¶Îʱ¼äºó£¬ÄãÈÏΪCÖÐÈÜÒº¿ÉÄܳöÏÖµÄÏÖÏóÊÇ__________________£¬ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò___________________________________________________¡£

£¨3£©ÊµÑé½áÊøºó£¬ÒÒͬѧ½«AÖеÄÎïÖÊÀäÈ´ºó¼ÓÈëµ½H2SÈÜÒºÖз¢ÏÖÓÐÆøÅݳöÏÖ£¬µ«¼ÓÈ˵½Ï¡ÑÎËáÖÐȴûÓÐÈκÎÏÖÏó¡£ÇëÓû¯Ñ§·½³ÌʽºÍ¼òÒªµÄÎÄ×Ö½âÊÍÔ­Òò£º

____________________________________________________________________.

£¨4£©Ëæ×Å·´Ó¦µÄ½øÐУ¬ÐËȤС×éµÄͬѧÃǶ¼Ìرð×¢Òâµ½DÖÐÈÜÒººìÉ«Öð½¥ÍÊÈ¥¡£ËûÃǶÔÈÜÒººìÉ«ÍÊÈ¥Ö÷ÒªÔ­ÒòÌá³öÁËÈçϼÙÉ裬ÇëÄãÍê³É¼ÙÉè¶þ¡£

¼ÙÉèÒ»:BÖÐÒݳöÆøÌåÓëË®·´Ó¦Éú³ÉµÄÎïÖÊÓÐÇ¿Ñõ»¯ÐÔ£¬Ê¹ºìÉ«Öð½¥ÍÊÈ¥£»

¼ÙÉè¶þ£º__________________________________________¡£

£¨5£©ÇëÄãÉè¼ÆʵÑéÑéÖ¤ÉÏÊö¼ÙÉèÒ»£¬Ð´³öʵÑé²½Öè¼°½áÂÛ____________________________________________________________________¡£

 

 

£¨2£©Óе­»ÆÉ«³Áµí£¨2·Ö£©   Cl2+S2-=2Cl-+S¡ý£¨2·Ö£©

£¨3£©AgÖû»H2SµÄ·´Ó¦Ê½Îª£º2Ag+H2S=Ag2S+H2,±íÃ÷Ag2SµÄÈܽâ¶È±ÈAgClСºÜ¶à£¨3·Ö£©

£¨4£©¿ÉÄÜÊÇH+ÖкÍÁËOH-Ôì³ÉÍÊÉ«£¨2·Ö£©

£¨5£©1.È¡ÉÙÁ¿DÖÐÍÊÉ«ºóµÄÈÜÒºÓÚÊÔ¹ÜÖУ¨2·Ö£©

2.µÎ¼Ó1-2µÎ·Ó̪ÈÜÒº,Èç¹ûÓÖÏÔºìÉ«,Ôò¼ÙÉèÒ»ÕýÈ·£¨2·Ö£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

(15·Ö)ijÖÐѧ¿ÎÍâÐËȤС×éÓöèÐԵ缫µç½â±¥ºÍʳÑÎË®£¨º¬ÉÙÁ¿Ca2+¡¢Mg2+)×÷ϵÁÐ̽¾¿£¬×°ÖÃÈçÏÂͼËùʾ£º

£¨1£©µç½âʱ£¬¼×ͬѧ·¢Ïֵ缫a¸½½üÈÜÒº³öÏÖ»ë×Ç,ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò
______________________________________________________________¡£
£¨2£©Ò»¶Îʱ¼äºó£¬ÄãÈÏΪCÖÐÈÜÒº¿ÉÄܳöÏÖµÄÏÖÏóÊÇ__________________£¬ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò___________________________________________________¡£
£¨3£©ÊµÑé½áÊøºó£¬ÒÒͬѧ½«AÖеÄÎïÖÊÀäÈ´ºó¼ÓÈëµ½H2SÈÜÒºÖз¢ÏÖÓÐÆøÅݳöÏÖ£¬µ«¼ÓÈ˵½Ï¡ÑÎËáÖÐȴûÓÐÈκÎÏÖÏó¡£ÇëÓû¯Ñ§·½³ÌʽºÍ¼òÒªµÄÎÄ×Ö½âÊÍÔ­Òò£º
____________________________________________________________________.
£¨4£©Ëæ×Å·´Ó¦µÄ½øÐУ¬ÐËȤС×éµÄͬѧÃǶ¼Ìرð×¢Òâµ½DÖÐÈÜÒººìÉ«Öð½¥ÍÊÈ¥¡£ËûÃǶÔÈÜÒººìÉ«ÍÊÈ¥Ö÷ÒªÔ­ÒòÌá³öÁËÈçϼÙÉ裬ÇëÄãÍê³É¼ÙÉè¶þ¡£
¼ÙÉèÒ»:BÖÐÒݳöÆøÌåÓëË®·´Ó¦Éú³ÉµÄÎïÖÊÓÐÇ¿Ñõ»¯ÐÔ£¬Ê¹ºìÉ«Öð½¥ÍÊÈ¥£»
¼ÙÉè¶þ£º__________________________________________¡£
£¨5£©ÇëÄãÉè¼ÆʵÑéÑéÖ¤ÉÏÊö¼ÙÉèÒ»£¬Ð´³öʵÑé²½Öè¼°½áÂÛ____________________________________________________________________¡£

(15·Ö)ijÖÐѧ¿ÎÍâÐËȤС×éÓöèÐԵ缫µç½â±¥ºÍʳÑÎË®£¨º¬ÉÙÁ¿Ca2+¡¢Mg2+)×÷ϵÁÐ̽¾¿£¬×°ÖÃÈçÏÂͼËùʾ£º

£¨1£©µç½âʱ£¬¼×ͬѧ·¢Ïֵ缫a¸½½üÈÜÒº³öÏÖ»ë×Ç,ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò

______________________________________________________________¡£

£¨2£©Ò»¶Îʱ¼äºó£¬ÄãÈÏΪCÖÐÈÜÒº¿ÉÄܳöÏÖµÄÏÖÏóÊÇ__________________£¬ÇëÓÃÀë×Ó·½³Ìʽ±íʾԭÒò___________________________________________________¡£

£¨3£©ÊµÑé½áÊøºó£¬ÒÒͬѧ½«AÖеÄÎïÖÊÀäÈ´ºó¼ÓÈëµ½H2SÈÜÒºÖз¢ÏÖÓÐÆøÅݳöÏÖ£¬µ«¼ÓÈ˵½Ï¡ÑÎËáÖÐȴûÓÐÈκÎÏÖÏó¡£ÇëÓû¯Ñ§·½³ÌʽºÍ¼òÒªµÄÎÄ×Ö½âÊÍÔ­Òò£º

____________________________________________________________________.

£¨4£©Ëæ×Å·´Ó¦µÄ½øÐУ¬ÐËȤС×éµÄͬѧÃǶ¼Ìرð×¢Òâµ½DÖÐÈÜÒººìÉ«Öð½¥ÍÊÈ¥¡£ËûÃǶÔÈÜÒººìÉ«ÍÊÈ¥Ö÷ÒªÔ­ÒòÌá³öÁËÈçϼÙÉ裬ÇëÄãÍê³É¼ÙÉè¶þ¡£

¼ÙÉèÒ»:BÖÐÒݳöÆøÌåÓëË®·´Ó¦Éú³ÉµÄÎïÖÊÓÐÇ¿Ñõ»¯ÐÔ£¬Ê¹ºìÉ«Öð½¥ÍÊÈ¥£»

¼ÙÉè¶þ£º__________________________________________¡£

£¨5£©ÇëÄãÉè¼ÆʵÑéÑéÖ¤ÉÏÊö¼ÙÉèÒ»£¬Ð´³öʵÑé²½Öè¼°½áÂÛ____________________________________________________________________¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø