ÌâÄ¿ÄÚÈÝ
(10·Ö)Na2S2O3¡¤5H2O(Ë׳ƺ£²¨)ÊÇÕÕÏàÒµ³£ÓõÄÒ»ÖÖ¶¨Ó°¼Á£¬³£²ÉÓÃÏ·¨ÖƱ¸£º½«ÑÇÁòËáÄÆÈÜÒºÓëÁò·Û»ìºÏ¹²ÈÈ£¬Éú³ÉÁò´úÁòËáÄÆNa2SO3+S£½Na2S2O3£¬ÂËÈ¥Áò·Û£¬ÔÙ½«ÂËҺŨËõ¡¢ÀäÈ´£¬¼´ÓÐNa2S2O3¡¤5H2O¾§ÌåÎö³ö¡£¸Ã·¨ÖƵõľ§ÌåÖг£»ìÓÐÉÙÁ¿Na2SO3ºÍNa2SO4µÄÔÓÖÊ.
Ϊ²â¶¨Ò»ÖÖº£²¨¾§ÌåÑùÆ·µÄ³É·Ö£¬Ä³Í¬Ñ§³ÆÈ¡Èý·ÝÖÊÁ¿²»Í¬µÄ¸ÃÑùÆ·£¬·Ö±ð¼ÓÈëÏàͬŨ¶ÈµÄÏ¡H2SO4ÈÜÒº20mL£¬³ä·Ö·´Ó¦ºóÂ˳öÁò£¬²¢½«ÂËҺ΢ÈÈ(¼Ù¶¨Éú³ÉµÄSO2È«²¿Òݳö)£¬²âµÃÓйØÊµÑéÊý¾ÝÈçÏÂ(±ê×¼×´¿ö)£º
|
|
µÚÒ»·Ý |
µÚ¶þ·Ý |
µÚÈý·Ý |
|
ÑùÆ·µÄÖÊÁ¿/g |
12.60 |
18.90 |
28.00 |
|
¶þÑõ»¯ÁòµÄÌå»ý/L |
1.12 |
1.68 |
2.24 |
|
ÁòµÄÖÊÁ¿/g |
1.28 |
1.92 |
2.56 |
(1)ÑùÆ·ÓëÏ¡ÁòËá¿ÉÄÜ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________£»
_____________________________________________¡£
(2)¸ù¾ÝÉϱíÊý¾Ý·ÖÎö£¬¸ÃÑùÆ·_________________________(ÌîÑ¡Ïî×Öĸ)£»
A£®º¬ÓÐNa2S2O3¡¤5H2OºÍNa2SO4Á½ÖֳɷÖ
B£®º¬ÓÐNa2S2O3¡¤5H2OºÍNa2SO3Á½ÖֳɷÖ
C£®º¬ÓÐNa2S2O3¡¤5H2O¡¢Na2SO3ºÍNa2SO4ÈýÖֳɷÖ
(3)¸ÃÑùÆ·Öи÷³É·ÖµÄÎïÖʵÄÁ¿Ö®±ÈΪ___________________________£»
(4)Ëù¼ÓÁòËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ___________________________mol/L¡£
(10·Ö)
(1)£¨¸÷2·Ö£¬¹²4·Ö£©S2O32-+2H+£½S¡ý+SO2¡ü+H2O SO32-+2H+£½SO2¡ü+H2O
(2)£¨2·Ö£©C
(3)£¨2·Ö£©n(Na2S2O3):n(Na2SO3):n(Na2SO4) = 4:1:1
(4)£¨2·Ö£©5mol¡¤L-1
¡¾½âÎö¡¿ÂÔ
(10·Ö)Na2S2O3¡¤5H2O(Ë׳ƺ£²¨)ÊÇÕÕÏàÒµ³£ÓõÄÒ»ÖÖ¶¨Ó°¼Á£¬³£²ÉÓÃÏ·¨ÖƱ¸£º½«ÑÇÁòËáÄÆÈÜÒºÓëÁò·Û»ìºÏ¹²ÈÈ£¬Éú³ÉÁò´úÁòËáÄÆNa2SO3+S£½Na2S2O3£¬ÂËÈ¥Áò·Û£¬ÔÙ½«ÂËҺŨËõ¡¢ÀäÈ´£¬¼´ÓÐNa2S2O3¡¤5H2O¾§ÌåÎö³ö¡£¸Ã·¨ÖƵõľ§ÌåÖг£»ìÓÐÉÙÁ¿Na2SO3ºÍNa2SO4µÄÔÓÖÊ.
Ϊ²â¶¨Ò»ÖÖº£²¨¾§ÌåÑùÆ·µÄ³É·Ö£¬Ä³Í¬Ñ§³ÆÈ¡Èý·ÝÖÊÁ¿²»Í¬µÄ¸ÃÑùÆ·£¬·Ö±ð¼ÓÈëÏàͬŨ¶ÈµÄÏ¡H2SO4ÈÜÒº20mL£¬³ä·Ö·´Ó¦ºóÂ˳öÁò£¬²¢½«ÂËҺ΢ÈÈ(¼Ù¶¨Éú³ÉµÄSO2È«²¿Òݳö)£¬²âµÃÓйØÊµÑéÊý¾ÝÈçÏÂ(±ê×¼×´¿ö)£º
|
| µÚÒ»·Ý | µÚ¶þ·Ý | µÚÈý·Ý |
| ÑùÆ·µÄÖÊÁ¿/g | 12.60 | 18.90 | 28.00 |
| ¶þÑõ»¯ÁòµÄÌå»ý/L | 1.12 | 1.68 | 2.24 |
| ÁòµÄÖÊÁ¿/g | 1.28 | 1.92 | 2.56 |
(1)ÑùÆ·ÓëÏ¡ÁòËá¿ÉÄÜ·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________________£»
_____________________________________________¡£
(2)¸ù¾ÝÉϱíÊý¾Ý·ÖÎö£¬¸ÃÑùÆ·_________________________(ÌîÑ¡Ïî×Öĸ)£»
A£®º¬ÓÐNa2S2O3¡¤5H2OºÍNa2SO4Á½ÖֳɷÖ
B£®º¬ÓÐNa2S2O3¡¤5H2OºÍNa2SO3Á½ÖֳɷÖ
C£®º¬ÓÐNa2S2O3¡¤5H2O¡¢Na2SO3ºÍNa2SO4ÈýÖֳɷÖ
(3)¸ÃÑùÆ·Öи÷³É·ÖµÄÎïÖʵÄÁ¿Ö®±ÈΪ___________________________£»
(4)Ëù¼ÓÁòËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ___________________________mol/L¡£
(10·Ö) Na2S2O3?5H2O£¨Ë׳ƺ£²¨£©ÊÇÕÕÏàÒµ³£ÓõÄÒ»ÖÖ¶¨Ó°¼Á¡£¹¤ÒµÉÏÖÆµÃµÄNa2S2O3?5H2O¾§ÌåÖпÉÄܺ¬ÓÐNa2SO3¡£Îª²â¶¨Ä³º£²¨ÑùÆ·µÄ³É·Ö£¬³ÆÈ¡Èý·ÝÖÊÁ¿²»Í¬µÄ¸ÃÑùÆ·£¬·Ö±ð¼ÓÈëÏàͬŨ¶ÈµÄÁòËáÈÜÒº30 mL£¬³ä·Ö·´Ó¦£¨Na2S2O3£«H2SO4=Na2SO4£«SO2¡ü£«S¡ý£«H2O£©ºóÂ˳öÁò£¬Î¢ÈÈÂËҺʹSO2È«²¿Òݳö¡£²âµÃÓйØÊµÑéÊý¾ÝÈçÏÂ±í£¨ÆøÌåÌå»ýÒÑ»»ËãΪ±ê×¼×´¿ö£©¡£
| µÚÒ»·Ý | µÚ¶þ·Ý | µÚÈý·Ý |
ÑùÆ·µÄÖÊÁ¿/g | 6.830 | 13.660 | 30.000 |
¶þÑõ»¯ÁòÆøÌåµÄÌå»ý/L | 0.672 | 1.344 | 2.688 |
ÁòµÄÖÊÁ¿/g | 0.800 | 1.600 | 3.200 |
ÊÔ¼ÆË㣺
£¨1£©ËùÓÃÁòËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ ¡£
£¨2£©ÑùÆ·ÖÐn(Na2S2O3?5H2O)£ºn(Na2SO3)= ¡£
£¨3£©Ä³»·¾³¼à²âС×éÓÃÉÏÊöº£²¨ÑùÆ·ÅäÖÆº¬Na2S2O3 0.100 mol?L-1µÄº£²¨ÈÜÒº£¬²¢ÀûÓÃËü²â¶¨Ä³¹¤³§·ÏË®ÖÐBa2+µÄŨ¶È¡£ËûÃÇÈ¡·ÏË®50.00 mL£¬¿ØÖÆÊʵ±µÄËá¶È¼ÓÈë×ãÁ¿µÄK2Cr2O7ÈÜÒº£¬µÃBaCrO4³Áµí£»³Áµí¾Ï´µÓ¡¢¹ýÂ˺ó£¬ÓÃÊÊÁ¿µÄÏ¡ÑÎËáÈܽ⣬´ËʱCrO42-È«²¿×ª»¯ÎªCr2O72-£»ÔÙ¼Ó¹ýÁ¿KIÈÜÒº£¬³ä·Ö·´Ó¦ºó£¬ÓÃÉÏÊöÅäÖÆµÄº£²¨ÈÜÒº½øÐе樣¬·´Ó¦Íêȫʱ£¬²âµÃÏûºÄº£²¨ÈÜÒºµÄÌå»ýΪ36.00 mL¡£ÒÑÖªÓйط´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
¢ÙCr2O72- + 6I- + 14H+ 2Cr3+ + 3I2 + 7H2O
¢ÚI2 + 2S2O32- 2I- + S4O62-
¢ÛI2 + SO32- + H2O 2I- + SO42- + 2H+
ÔòµÎ¶¨¹ý³ÌÖпÉÓà ×÷ָʾ¼Á¡£¼ÆËã¸Ã¹¤³§·ÏË®ÖÐBa2+µÄÎïÖʵÄÁ¿Å¨¶È¡£