ÌâÄ¿ÄÚÈÝ
Âí¸ñÄáÌØ·¨Ò±Á¶Ã¾µÄ¹¤ÒÕÁ÷³ÌÈçÏÂͼ¡£Â¯ÁÏÖгýÓÐìÑÉÕ°×ÔÆÊ¯ºÍ¹èÌúÍ⣬»¹¼ÓÈëìÑÉÕ¹ýµÄÂÁÍÁ¿ó£¬¼ÓAl2O3µÄÖ÷ҪĿµÄÊǽµµÍÔüµÄÈ۵㣬±ãÓÚҺ̬ÅÅÔü¡£
ÒÑÖª°×ÔÆÊ¯µÄ³É·ÖΪCaCO3¡¤MgCO3,¹èÌúÊÇÖ¸º¬ÓÐ55%¹è×óÓÒµÄÌú[¿É±íʾΪSi(Fe)]£¬×÷»¹Ô¼Á,×îºóµÃµ½µÍƷλµÄ¹èÌú[¿É±íʾΪFe(Si)]£¬¼òÒ×Á÷³ÌͼÈçÏÂ![]()
ÊԻشðÏÂÁÐÎÊÌâ
£¨1£©·´Ó¦¢Ù£¬°×ÔÆÊ¯ìÑÉÕµÃCaO¡¤MgOµÄ»¯Ñ§·½³ÌʽΪ£º ¡£
£¨2£©·´Ó¦¢Ú£¬»¹Ô¯Öз¢Éú·´Ó¦Éú³ÉþºÍ¯ÔüµÄ»¯Ñ§·½³ÌʽΪ£º ¡£
£¨3£©¸Ã³É·ÖµÄ»¦ÔüÊÇÒ»ÖÖ¹¤ÒµÉú²úµÄÖØÒªÔÁÏ£¬¿É×÷ΪÉú²ú ÔÁÏ¡£
£¨4£©Âí¸ñÄáÌØ·¨Ò±Á¶Ã¾£¬Ò»Ì¨4500ǧÍߵį×Ó¿ÉÈÕ²úÔ¼7.2¶Öþ£¬Ò»ÌìÖÁÉÙÔ¼ÏûºÄº¬¹è60%µÄ¹èÌú ¶Ö¡£
£¨1£©CaCO3¡¤MgCO3
CaO¡¤MgO+2CO2¡ü
£¨2£©2(CaO¡¤MgO)£«Si(Fe)£«0.3Al2O3
2Mg£«2CaO¡¤SiO2¡¤0.3Al2O3£«Fe(Si)
[»ò£º2(CaO¡¤MgO)£«Si£«0.3Al2O3
2Mg£«2CaO¡¤SiO2¡¤0.3Al2O3]
£¨3£©Ë®Äà £¨4£©8.4t
½âÎö:
±¾Ì⿼²é¹¤ÒÕÁ÷³ÌÖÐþµÄÒ±Á¶¡££¨2£©ÓÉÌâÖÐËùÊöºÍÁ÷³ÌÖеÄÐÅÏ¢£¬»¹Ô¯ÖÐΪ°×ÔÆÊ¯ìÑÉÕ²úÎïÓë¹èÌú¡¢ÂÁÍÁ¿ó·¢ÉúÑõ»¯»¹Ô·´Ó¦£¬Éú³É¯Ôü¡¢Ã¾ÒÔ¼°µÍƷλµÄ¹èÌú£¬·½³ÌʽΪ£º2(CaO¡¤MgO)£«Si(Fe)£«0.3Al2O3
2Mg£«2CaO¡¤SiO2¡¤0.3Al2O3£«Fe(Si)£»£¨3£©¸Ã¯ÔüÖ÷Òª³É·ÖΪ¹èËáÑΣ¬¿ÉÒÔÓÃÀ´Éú³ÉË®ÄàµÈ¹èËáÑβúÆ·£»£¨4£©ÓɹØÏµ£º
2Mg¡«Si
48 28
7.2 x
X=4.2t
½ø¿óÔüµÄ¹èΪ4.2t¡£
ÉèÔÓйè0.6x£¬½øÈëµÍÆ·¹èÌúÖÐÓйè0.6x-4.2
·´Ó¦ºó£¬µÍƷλ¹èÌú±ä³ÉÁË£ºx-4.2£¬¿ÉµÃ£º =0.2£¬x=8.4t¡£