ÌâÄ¿ÄÚÈÝ

ÇâäåËáÔÚÒ½Ò©ºÍʯ»¯¹¤ÒµÉÏÓй㷺ÓÃ;¡£ÏÂͼÊÇÄ£Ä⹤ҵÖƱ¸ÇâäåËá´ÖÆ·¼°¾«ÖƵÄÁ÷³Ì£º

ÒÑÖª£ºBr2ÊÇÒ×»Ó·¢¡¢Éîºì×ØÉ«µÄÒºÌ壻ÇâäåËáÊÇÒ×»Ó·¢¡¢ÎÞÉ«ÒºÌå¡£
¸ù¾ÝÉÏÊöÁ÷³Ì»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©·´Ó¦ÊÒ¢ÙÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ              ¡£
£¨2£©·´Ó¦ÊÒ¢ÙʹÓñùË®µÄÄ¿µÄ           ¡£
£¨3£©²Ù×÷IµÄÃû³Æ          £¬²Ù×÷¢òÓõ½µÄ²£Á§ÒÇÆ÷ÓР          ¡£
£¨4£©·´Ó¦ÊÒ¢ÚÖмÓÈëNa2SO3µÄÄ¿µÄÊÇ             ¡£
£¨5£©¹¤ÒµÉú²úÖÐÖƵõÄÇâäåËá´øÓе­µ­µÄ»ÆÉ«¡£ÓÚÊǼ×ÒÒÁ½Í¬Ñ§Éè¼ÆÁËʵÑé¼ÓÒÔ̽¾¿£º
¢Ù¼×ͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪº¬Fe3£«£¬ÔòÓÃÓÚÖ¤Ã÷¸Ã¼ÙÉèËùÓõÄÊÔ¼ÁΪ           £¬Èô¼ÙÉè³ÉÁ¢¿É¹Û²ìµ½µÄÏÖÏóΪ           ¡£
¢ÚÒÒͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪ        £¬ÆäÓÃÓÚÖ¤Ã÷¸Ã¼ÙÉè³ÉÁ¢µÄ·½·¨Îª              ¡£
£¨1£©SO2+Br2+2H2O=H2SO4+2HBr  £¨2£©·ÀÖ¹Br2ºÍHBr»Ó·¢
£¨3£©ÕôÁó£»Â©¶·¡¢²£Á§°ô¡¢ÉÕ±­¡£ £¨4£©»¹Ô­´ÖÆ·ÖеÄBr2
£¨5£©¢ÙKSCNÈÜÒº£¬ÇâäåËáÓöKSCNÈÜÒº±äºìÉ«£»¢ÚÇâäåËáÖк¬ÓÐBr2£¬Óò£Á§°ôպȡÖƵõÄÇâäåËᣬµãÔÚʪÈóµí·ÛKIÊÔÖ½ÉϱäÀ¶£¨»òÓýºÍ·µÎ¹ÜÈ¡ÖƵõÄÇâäåËáÓÚÊÔ¹ÜÖУ¬µÎ¼ÓCCl4¡¢Õñµ´¡¢¾²Ö¹£¬Ï²ã³Ê³ÈºìÉ«£©£¬Ö¤Ã÷Òòº¬Br2¶øÏÔ»ÆÉ«¡£

ÊÔÌâ·ÖÎö£º£¨1£©·´Ó¦ÊÒ¢ÙÖÐSO2ºÍBr2ÔÚ±ùË®Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪSO2+Br2+2H2O=H2SO4+2HBr¡££¨2£©·´Ó¦ÊÒ¢ÙʹÓñùË®µÄÄ¿µÄÊÇΪÁË·ÀÖ¹Br2ºÍHBr»Ó·¢¶øÎÛȾ¿ÕÆø£¬Ó°Ïì²Ù×÷¡££¨3£©²Ù×÷IÊÇ·ÖÀ뻥Èܵķе㲻ͬµÄÒºÌåÎïÖʵIJÙ×÷¡£Ãû³ÆÊÇÕôÁó¡£²Ù×÷¢òÓõ½µÄ²£Á§ÒÇÆ÷ÓЩ¶·¡¢²£Á§°ô¡¢ÉÕ±­¡££¨4£©·´Ó¦ÊÒ¢ÚÖмÓÈëNa2SO3µÄÄ¿µÄÊÇΪÁËÏûºÄΪ·´Ó¦µÄBr2£¬Ìá¸ßÎïÖʵĴ¿¶È¡££¨5£©¹¤ÒµÉú²úÖÐÖƵõÄÇâäåËá´øÓе­µ­µÄ»ÆÉ«¡£¢Ù¼×ͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪº¬Fe3£«¡£¼ìÑéµÄ·½·¨ÊÇÈ¡ÉÙÁ¿µÄÈÜÒº£¬ÏòÆäÖеμӼ¸µÎKSCNÈÜÒº£¬Èô¹¤ÒµÇâäåËáÓöKSCNÈÜÒº±äºìÉ«£»¾ÍÖ¤Ã÷º¬ÓÐFe3£«£»·ñÔò¾Í°Éº¬ÓÐFe3£«¡£¢ÚÒÒͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪº¬ÓÐBr2¡£¼ìÑéµÄ·½·¨ÊÇÀûÓÃÆäÇ¿Ñõ»¯ÐÔ¡£Óò£Á§°ôպȡÖƵõÄÇâäåËᣬµãÔÚʪÈóµí·ÛKIÊÔÖ½ÉϱäÀ¶£¨Ò²¿ÉÒÔÀûÓÃÆäÔÚÓлúÈܼÁÖеÄÈܽâ¶È´óµÄÐÔÖÊ¡£ÓýºÍ·µÎ¹ÜÈ¡ÖƵõÄÇâäåËáÓÚÊÔ¹ÜÖУ¬µÎ¼ÓCCl4¡¢Õñµ´¡¢¾²Ö¹£¬Ï²ã³Ê³ÈºìÉ«£©£¬Ö¤Ã÷Òòº¬Br2¶øÏÔ»ÆÉ«¡£2ºÍBr2µÄÐÔÖÊ¡¢»ìºÏÎïµÄ·ÖÀë·½·¨¡¢²Ù×÷¡¢Fe3£«ºÍBr2µÄ¼ìÑé·½·¨µÄ֪ʶ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
±½¼×Ëá¹ã·ºÓ¦ÓÃÓÚÖÆÒ©ºÍ»¯¹¤ÐÐÒµ£¬Ä³ÐËȤС×éͬѧÀûÓøßÃÌËá¼ØÑõ»¯¼×±½ÖƱ¸±½¼×ËᣨKMnO4ÖÐÐÔÌõ¼þÏ»¹Ô­²úÎïΪMnO2£¬ËáÐÔÌõ¼þÏÂΪMn2+£©

ÒÑÖª£º±½¼×ËáÏà¶Ô·Ö×ÓÁ¿122£¬ÈÛµã122.4¡æ£¬ÔÚ25¡æºÍ95¡æʱÈܽâ¶È·Ö±ðΪ0.3 gºÍ6.9 g¡£

ʵÑéÁ÷³Ì£º
¢ÙÍù×°ÖÃAÖмÓÈë2.7mL£¨2.3 g£©¼×±½ºÍ125 mLË®£¬È»ºó·ÖÅú´Î¼ÓÈë8.5 gÉÔ¹ýÁ¿µÄKMnO4¹ÌÌ壬¿ØÖÆ·´Ó¦Î¶ÈÔ¼ÔÚ100¡æ£¬µ±¼×±½²ã½üºõÏûʧ£¬»ØÁ÷²»ÔÙ³öÏÖÓÍÖéʱ£¬Í£Ö¹¼ÓÈÈ¡£
¢Ú½«·´Ó¦»ìºÏÎï³ÃÈȹýÂË£¬ÓÃÉÙÁ¿ÈÈˮϴµÓÂËÔü£¬ºÏ²¢ÂËÒºÓëÏ´µÓÒº£¬ÀäÈ´ºó¼ÓÈëŨÑÎËᣬ¾­²Ù×÷IµÃ°×É«½Ï¸ÉÔï´Ö²úÆ·¡£
¢Û´¿¶È²â¶¨£º³ÆÈ¡1.220g°×É«ÑùÆ·£¬Åä³É100mL,¼×´¼ÈÜÒº£¬È¡25.00mLÈÜÒº£¬ÓÃ0.1000mol/L KOH±ê×¼ÈÜÒºµÎ¶¨£¬Öظ´µÎ¶¨ËĴΣ¬Ã¿´ÎÏûºÄµÄÌå»ýÈçϱíËùʾÁо٣º
 
µÚÒ»´Î
µÚ¶þ´Î
µÚÈý´Î
µÚËÄ´Î
Ìå»ý£¨mL)
24.00
24.10
22.40
23.90
Çë»Ø´ð£º
£¨1£©×°ÖÃAµÄÃû³Æ         ¡£Èô²»ÓÃζȼƣ¬±¾ÊµÑé¿ØÖÆ·´Ó¦Î¶ȵĴëʩΪ         ¡£
£¨2£©°×É«´Ö²úÆ·ÖгýÁËKClÍ⣬ÆäËû¿ÉÄܵÄÎÞ»úÔÓÖÊΪ            ¡£
£¨3£©²Ù×÷IµÄÃû³Æ                                ¡£
£¨4£©²½Öè¢ÛÖÐÓõ½µÄ¶¨Á¿ÒÇÆ÷ÓР              £¬100mLÈÝÁ¿Æ¿£¬50mLËáʽ¡¢¼îʽµÎ¶¨¹Ü¡£
£¨5£©ÑùÆ·Öб½¼×Ëá´¿¶ÈΪ                      ¡£
£¨6£©µÎ¶¨²Ù×÷ÖУ¬Èç¹û¶Ô×°ÓÐKOH±ê×¼ÈÜÒºµÄµÎ¶¨¹Ü¶ÁÊýʱ£¬µÎ¶¨Ç°ÑöÊÓ£¬µÎ¶¨ºó¸©ÊÓÔò²â¶¨½á¹û        £¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°²»±ä¡±£©¡£
ÒÑ֪ľ̿ÔÚÒ»¶¨Ìõ¼þÏÂÓëŨÏõËá·´Ó¦Éú³ÉÁ½ÖÖ£«4¼ÛµÄÑõ»¯ÎΪÁË̽¾¿Ò»Ñõ»¯µª£¨NO£©ÄÜ·ñÓë¹ýÑõ»¯ÄÆ·´Ó¦£¬ÒÔ¼°·´Ó¦ºóµÄ²úÎïÖÐÊÇ·ñÓÐÑÇÏõËáÄÆ£¨NaNO2£©£¬Ä³Ð¡×éͬѧÉè¼ÆÁËÈçͼËùʾװÖ㨼гÖÒÇÆ÷ºÍÁ¬½ÓÓõĽº¹ÜÒѾ­Ê¡ÂÔ£©¡£

£¨1£©ÎªÁËÍê³É¸ÃʵÑ飬ÐéÏß¿òÄÚ»¹ÐèÒªÁ¬½ÓB¡«EËÄÌ××°Ö㬰´ÆøÁ÷·½ÏòÁ¬½ÓµÄ˳ÐòΪ£º
a¡ú(       )(       )¡ú(       )(       )¡ú(       )(       )¡ú (       )(       )£¨ÌîÒÇÆ÷½Ó¿ÚµÄ×Öĸ±àºÅ£©¡£Á¬½ÓºÃÒÇÆ÷£¬¼ì²éÆøÃÜÐÔ£¬×°ÈëÒ©Æ·ºó£¬ÒªÍ¨ÈëÒ»¶Îʱ¼äµÄµªÆø£¬ÔٵμÓŨÏõËᣬµãȼ¾Æ¾«µÆ£¬Í¨È뵪ÆøµÄÖ÷ҪĿµÄÊÇ                  ¡£
£¨2£©×°ÖÃEÖй۲쵽µÄÖ÷ҪʵÑéÏÖÏóÓР              ¡£
£¨3£©×°ÖÃCµÄ×÷ÓÃÊÇ                                     ¡£
£¨4£©Ä³Í¬Ñ§¾­²éÔÄ×ÊÁϺó·¢ÏÖÑÇÏõËáÊÇÈõËᣬÐÔÖʲ»Îȶ¨£¬ÊÒÎÂÏÂÒ×·Ö½âÉú³ÉÒ»Ñõ»¯µª¡£×°ÖÃDÖгä·Ö·´Ó¦ºó£¬Éè¼ÆʵÑéÖ¤Ã÷DÖÐÊÇ·ñÓÐÑÇÏõËáÄÆÉú³É£º                    ¡££¨Ð´³ö¼ìÑé²½Öè¼°ÏÖÏ󣩡£
£¨5£©ÑÇÏõËáÄÆÔÚËáÐÔÌõ¼þÏ¿ɽ«I£­Ñõ»¯ÎªI2£¬Í¬Ê±Éú³ÉNO£¬¸Ã·´Ó¦³£ÓÃÓÚÑÇÏõËáÄƺ¬Á¿µÄ²â¶¨£¬Çëд³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º       ¡£
ΪÁË»ØÊÕÀûÓøÖÌúÉú²ú¹ý³ÌÖвúÉúµÄSO2£¬¹¤ÒµÉϲÉÓÃÈíÃÌ¿ó£¨Ö÷Òª³É·ÖMnO2£©ÍÑÁòͬʱÖÆÈ¡ÁòËáÃ̼¼Êõ£¬ÆäÁ÷³ÌʾÒâͼÈçÏ£º

ÒÑÖª£º½þ³öÒºµÄpH½Ó½ü4£¬ÆäÖеĽðÊôÀë×ÓÖ÷ÒªÊÇMn2£«£¬»¹º¬ÓÐÉÙÁ¿µÄFe2£«¡£Íê³ÉÏÂÁÐÌî¿Õ¡£
£¨1£©Ð´³ö½þ³ö¹ý³ÌÖÐÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º                                    ¡£
£¨2£©½þ³ö¹ý³ÌµÄ¸±·´Ó¦Ö®Ò»ÊDz¿·ÖSO2±»Ñõ»¯ÎªÁòËᣬÖÂʹ½þ³öÒºµÄpHϽµ£¬Õ⽫   £¨¡°ÓÐÀû¡±¡¢¡°²»Àû¡±£©ÓÚÈíÃ̿󽬼ÌÐøÎüÊÕSO2¡£ÓûÏû³ýÉú³ÉµÄÁòËᣬÊÔ¼ÁA×îºÃÊÇ        ¡£
a£®MnCO3         b£®MnO2           c£®CaO            d£®CaCO3
£¨3£©²Ù×÷IµÄÄ¿µÄÊdzýÈ¥½þ³öÒºÖеÄFe2£«£¬MnO2ÔÚÑõ»¯Fe2£«µÄͬʱ»¹             £¬Ê¹Fe3£«³Áµí¡£¼ìÑé¹ýÂ˺óÈÜÒºÖÐÊÇ·ñº¬ÓÐFe3+µÄ²Ù×÷ÊÇ                  ¡£
£¨4£©ÒÑÖª´óÓÚ27¡æʱ£¬MnSO4¡¤H2OÈܽâ¶ÈËæζÈÉÏÉý¶øÃ÷ÏÔϽµ£¬Ôò²Ù×÷IIµÄ¹ý³ÌΪ£º           ¡¢            ¡¢Ï´µÓ¡¢¸ÉÔï¡£¹¤ÒµÉÏΪÁ˳ä·ÖÀûÓÃÃÌÔªËØ£¬ÔÚÁ÷³ÌÖР              ¿ÉÑ­»·Ê¹Óá£
£¨5£©Í¨¹ýìÑÉÕMnSO4¡¤H2O ¿ÉÖƵÃÉú²úÈí´ÅÌúÑõÌå²ÄÁϵÄMnxO4£¬ÈçͼÊÇìÑÉÕMnSO4¡¤H2OʱζÈÓëÊ£Óà¹ÌÌåÖÊÁ¿±ä»¯ÇúÏß¡£¸ÃÇúÏßÖÐA¶ÎËù±íʾÎïÖʵĻ¯Ñ§Ê½Îª      £»MnxO4ÖÐx£½           ¡£
(15·Ö)Í­µÄÂÈ»¯ÎïÊÇÖØÒªµÄ»¯¹¤Ô­ÁÏ£¬¹ã·ºµØÓÃ×÷ÓлúºÏ³É´ß»¯¼Á¡£
ʵÑéÊÒÖÐÒÔ´ÖÍ­(º¬ÔÓÖÊFe)ΪԭÁÏ£¬Ä³ÖÖÖƱ¸Í­µÄÂÈ»¯ÎïµÄÁ÷³ÌÈçÏ¡£

°´ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©²Ù×÷¢ÙµÄ²£Á§ÒÇÆ÷ÓÐ________________________£¬¼ìÑéÈÜÒº2ÖÐÊÇ·ñº¬ÓÐÔÓÖÊÀë×ӵIJÙ×÷ÊÇ                  ¡£
£¨2£©ÉÏÊöÁ÷³ÌÖУ¬ËùµÃ¹ÌÌå1ÐèÒª¼ÓÏ¡ÑÎËáÈܽ⣬ÆäÀíÓÉÊÇ                       £»
ÈÜÒº1¿É¼ÓÊÔ¼ÁXÓÃÓÚµ÷½ÚpHÒÔ³ýÈ¥ÔÓÖÊ£¬X¿ÉÑ¡ÓÃÏÂÁÐÊÔ¼ÁÖеÄ(ÌîÐòºÅ)___________¡£
a£®NaHCO3     b£®NH3¡¤H2O     c£®CuO     d£®Cu2(OH)2CO3
£¨3£©·´Ó¦¢ÚÊÇÏòÈÜÒº2ÖÐͨÈëÒ»¶¨Á¿µÄSO2£¬¼ÓÈÈÒ»¶Îʱ¼äºóÉú³ÉCuCl°×É«³Áµí¡£Ð´³ö   
ÖƱ¸CuClµÄÀë×Ó·½³Ìʽ£º                                                   ¡£
£¨4£©ÏÖÓÃÈçͼËùʾµÄʵÑéÒÇÆ÷¼°Ò©Æ·À´ÖƱ¸´¿¾»¡¢¸ÉÔïµÄÂÈÆø²¢Óë´ÖÍ­·´Ó¦(Ìú¼Ų̈¡¢Ìú¼ÐÊ¡ÂÔ)¡£

¢Ù°´ÆøÁ÷·½ÏòÁ¬½Ó¸÷ÒÇÆ÷½Ó¿Ú˳ÐòÊÇ£ºa¡ú  ¡¢¡¡¡¡¡ú¡¡¡¡¡¢¡¡¡¡¡ú¡¡¡¡¡¢¡¡¡¡¡ú¡¡¡¡¡¡¡£ÊµÑé´óÊԹܼÓÈÈÇ°Òª½øÐÐÒ»²½ÖØÒª²Ù×÷£¬Æä²Ù×÷ÊÇ                          ¡£
¢Ú·´Ó¦Ê±£¬Ê¢´ÖÍ­·ÛµÄÊÔ¹ÜÖеÄÏÖÏóÊÇ                              ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø