ÌâÄ¿ÄÚÈÝ

½«1 mol I2(g)ºÍ2 mol H2ÖÃÓÚij2 LÃܱÕÈÝÆ÷ÖУ¬ÔÚÒ»¶¨Î¶ÈÏ·¢Éú·´Ó¦£ºI2(g)£«H2(g)2HI(g)£»¦¤H>0£¬²¢´ïƽºâ¡£

HIµÄÌå»ý·ÖÊýw(HI)ËæÊ±¼ä±ä»¯ÈçͼÇúÏßbËùʾ£º 

 

(1)´ïƽºâʱ£¬I2(g)µÄÎïÖʵÄÁ¿Å¨¶ÈΪ___________¡£

(2)Èô¸Ä±ä·´Ó¦Ìõ¼þ£¬

ÔÚ¼×Ìõ¼þÏ£¬w(HI)µÄ±ä»¯ÈçͼÇúÏßaËùʾ£¬

ÔÚÒÒÌõ¼þÏ£¬w(HI)µÄ±ä»¯ÈçͼÇúÏßcËùʾ¡£

Ôò¼×Ìõ¼þ¿ÉÄÜÊÇ__________£»ÒÒÌõ¼þ¿ÉÄÜÊÇ___________¡£(ÌîÈëÏÂÁÐÐòºÅ)

¢ÙºãÈÝÌõ¼þÏ£¬Éý¸ßζȠ   ¢ÚºãÈÝÌõ¼þÏ£¬½µµÍζȠ

¢ÛºãÎÂÌõ¼þÏ£¬ËõС·´Ó¦ÈÝÆ÷Ìå»ý     ¢ÜºãÎÂÌõ¼þÏ£¬À©´ó·´Ó¦ÈÝÆ÷Ìå»ý    

¢ÝºãκãÈÝÌõ¼þÏ£¬¼ÓÈëÊʵ±´ß»¯¼Á

(3)Èô±£³ÖζȲ»±ä£¬ÔÚÁíÒ»ÏàͬµÄ2 LÃܱÕÈÝÆ÷ÖмÓÈëa mol I2(g)¡¢b mol H2ºÍc mol HI(a¡¢b¡¢c¾ù´óÓÚ0)£¬·¢Éú·´Ó¦£¬´ïƽºâʱ£¬HIµÄÌå»ý·ÖÊýÈÔΪ0.60£¬Ôòa¡¢b¡¢cµÄ¹ØÏµÊÇ________

(1)0.05 mol?L£­1

(2)¢Û¢Ý¢Ü

(3)4a£«c=2b

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø